base64规则:

* 字符串只可能包含A-Z,a-z,0-9,+,/,=字符
* 字符串长度是4的倍数
* =只会出现在字符串最后,可能没有或者一个等号或者两个等号

首先,C# 做上传文件的时候,需要替换掉这些字符:

data:image/jpeg;base64,

data:image/png;base64,

data:image/gif;base64,

if (str.Contains("base64,"))
{
str = str.Split("base64,")[];
}

如果还存在错误的话,可以进行一些字符替换试试:

var imgData = "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";
//过滤特殊字符即可
string dummyData = imgData.Trim().Replace("%", "").Replace(",", "").Replace(" ", "+");byte[] byteArray = Convert.FromBase64String(dummyData);

上面两步操作完了还没有解决问题的话,可以调试看看base64字符串的长度,如果长度不是4的倍数,比如8057或者8041,可以尝试截掉最后一个字符,使字符长度变为4的倍数。(能正常解决bug,但不确定是否会产生其他问题)

str = str.Substring(, str.Length - );

上面两个长度其实是本人调试的时候遇到的,神奇的是,复制粘贴后就会变成8056长度,可以正常解析。如果有大佬知道是怎么回事的话,欢迎评论沟通。

Base-64字符串无效,The input is not a valid Base-64 string as it contains a non-base 64 character的更多相关文章

  1. winform错误提示 :窗口类名无效(Window class name is not valid)

    winfrom 程序在 xp 操作系统上报错提示 窗口类名无效(Window class name is not valid) 解决方法 注释 Program类 里 这句 Application.En ...

  2. git是一种分布式代码管理工具,git通过树的形式记录文件的更改历史,比如: base'<--base<--A<--A' ^ | --- B<--B' 小米工程师常常需要寻找两个分支最近的分割点,即base.假设git 树是多叉树,请实现一个算法,计算git树上任意两点的最近分割点。 (假设git树节点数为n,用邻接矩阵的形式表示git树:字符串数组matrix包含n个字符串,每个字符串由字符'0

    // ConsoleApplication10.cpp : 定义控制台应用程序的入口点. // #include "stdafx.h" #include <iostream& ...

  3. [Swift]LeetCode434. 字符串中的单词数 | Number of Segments in a String

    Count the number of segments in a string, where a segment is defined to be a contiguous sequence of ...

  4. [Swift]LeetCode806. 写字符串需要的行数 | Number of Lines To Write String

    We are to write the letters of a given string S, from left to right into lines. Each line has maximu ...

  5. [Swift]LeetCode833. 字符串中的查找与替换 | Find And Replace in String

    To some string S, we will perform some replacement operations that replace groups of letters with ne ...

  6. 循环遍历Java字符串字符的规范方法——类似python for ch in string

    比如我将string作为CNN 文本处理输入: float [] input = new float[maxLength]; // 1 sentence by maxLenWords // int[] ...

  7. C#LeetCode刷题之#557-反转字符串中的单词 III(Reverse Words in a String III)

    问题 该文章的最新版本已迁移至个人博客[比特飞],单击链接 https://www.byteflying.com/archives/3955 访问. 给定一个字符串,你需要反转字符串中每个单词的字符顺 ...

  8. C#LeetCode刷题之#345-反转字符串中的元音字母​​​​​​​(Reverse Vowels of a String)

    问题 该文章的最新版本已迁移至个人博客[比特飞],单击链接 https://www.byteflying.com/archives/3935 访问. 编写一个函数,以字符串作为输入,反转该字符串中的元 ...

  9. 字符串中判断存在的几种模式和效率(string.contains、string.IndexOf、Regex.Match)

    通常情况下,我们判断一个字符串中是否存在某值常常会用string.contains,其实判断一个字符串中存在某值的方法有很多种,最常用的就是前述所说的string.contains,相对来说比较常用的 ...

随机推荐

  1. 3.1Go变量

    3.1 Go变量 变量是对内存中数据存储空间的表示,如同门牌号对应着房间,同样的,变量名字对应变量的值. 变量:本质就是一块内存空间.用于存储某个数值.该数值在运行时可以改变. 变量使用步骤 1.声明 ...

  2. import * as x from 'xx' 和 import x from 'xx'

    普通xx.js文件 //不可变的依赖模拟数据 module.exports=[ { id: "d52dccfc-656d-11e8-b153-7cd30ad3aa7a", regi ...

  3. Ext.tree.TreePanel 属性详解

    Ext.tree.TreePanel 属性详解 2013-06-09 11:02:47|  分类: ExtJs|举报|字号 订阅  原文地址:http://blog.163.com/zzf_fly/b ...

  4. iOS开发常用技能点(持续更新中。。。)

    1,以屏幕原点开始布局  (默认从导航栏原点布局) self.extendedLayoutIncludesOpaqueBars = YES;   2,向button发送点击事件 [self.playB ...

  5. 计蒜客 - Fantastic Graph

    题目链接:https://nanti.jisuanke.com/t/31447 知识点: 最大流 题目大意: 给定一个二分图,左边有 $N$ 个点,右边有 $M$ 个点,给出 $K$ 条边.问是否能从 ...

  6. 虚拟机配置JAVA_HOME

    1.cp home/fan-vm2/es/tools/jdk-8u111-linux-x64.tar.gz usr/java2.tar -zxvf jdk-8u111-linux-x64.tar.gz ...

  7. vue中生命周期

    1,说器生命周期,总觉得有熟悉,又陌生,直到看到一道面试题,问父子组件的生命周期的执行顺序,我擦,真没太注意啊,不知道. 2,网上搜了一下,说法是有点像洋葱圈的形式,由外到内,在到外,因为就像一个盒子 ...

  8. 5.List链表类型介绍和操作

    数据类型List链表 (1)介绍 list类型其实就是一个双向链表.通过push,pop操作从链表的头部或者尾部添加删除元素.这使得list既可以用作栈,也可以用作队列. 该list链表类型应用场景: ...

  9. 【QT】利用pyqt5实现简单界面

    Topic: 利用pyqt5编写简单界面Env:win10 + Pycharm2018 + Python 3.6.8Date: 2019/4/29 by hw_Chen2018            ...

  10. 读Pyqt4教程,带你入门Pyqt4 _003

    编程中的一个重要事情是布局管理,布局管理是如何在窗体上摆放窗口组件.可以有两种方式进行管理:绝对定位或使用布局类. 绝对定位 程序员用像素指定每个控件的位置和尺寸.使用绝对定位时,你必须理解几件事情. ...