java:利用xpath删除xml中的空节点

原始xml内容：

 <data>
   <a> </a>
   <b>b1</b>
   <awb>
     <awbpre>123</awbpre>
     <awbno></awbno>
   </awb>
   <spls>
     <spl />
   </spls>
 </data>

可用下面的代码去掉 <awbno></awbno>、<spls><spl/></spls>这二个空节点 （注<a> </a>中间有一个空格，不算空节点）

     @Test
     public void testDeleteEmptyNode() throws DocumentException {
         String xmlOrigin = "<data><a> </a><b>b1</b><awb><awbpre>123</awbpre><awbno></awbno></awb><spls><spl/></spls></data>";
         SAXReader saxReader = new SAXReader();
         Document document = saxReader.read(new ByteArrayInputStream(xmlOrigin
                 .getBytes()));

         while (true) {
             @SuppressWarnings("unchecked")
             List<Element> list = document.selectNodes("//*[not(node())]");
             if (list == null || list.size() <= 0) {
                 break;
             }
             for (Element e : list) {
                 System.out.println(e.getName());
                 e.getParent().remove(e);
             }
         }
         System.out.println(document.asXML());

     }

以上代码使用了dom4j

输出内容：

awbno
spl
spls
<?xml version="1.0" encoding="UTF-8"?>
<data><a> </a><b>b1</b><awb><awbpre>123</awbpre></awb></data>

即：

 <data>
   <a> </a>
   <b>b1</b>
   <awb>
     <awbpre>123</awbpre>
   </awb>
 </data>