HDU 6077 17多校4 Time To Get Up 水题

Problem Description

Little Q's clock is alarming! It's time to get up now! However, after reading the time on the clock, Little Q lies down and starts sleeping again. Well, he has 5 alarms, and it's just the first one, he can continue sleeping for a while.

Little Q's clock uses a standard 7-segment LCD display for all digits, plus two small segments for the '':'', and shows all times in a 24-hour format. The '':'' segments are on at all times.

Your job is to help Little Q read the time shown on his clock.

 

Input

The first line of the input contains an integer T(1≤T≤1440), denoting the number of test cases.

In each test case, there is an 7×21 ASCII image of the clock screen.

All digit segments are represented by two characters, and each colon segment is represented by one character. The character ''X'' indicates a segment that is on while ''.'' indicates anything else. See the sample input for details.

 

Output

For each test case, print a single line containing a string t in the format of HH:MM, where t(00:00≤t≤23:59), denoting the time shown on the clock.

 

Sample Input

1

.XX...XX.....XX...XX.

X..X....X......X.X..X

X..X....X.X....X.X..X

......XX.....XX...XX.

X..X.X....X....X.X..X

X..X.X.........X.X..X

.XX...XX.....XX...XX.

 

Sample Output

02:38

题意：把字符串翻译成时间。

题解：直接利用他们的区别判断即可。

 #include <iostream>
 #include<cstdio>
 #include<algorithm>
 #include<queue>
 #include<map>
 #include<vector>
 #include<cmath>
 #include<cstring>
 using namespace std;

 char time[+][+];
 int check(int i)
 {
     int j;
     if(time[][i]=='X')
     {
         if(time[][i+]=='.')
             return ;
         else if(time[][i]=='.')
             return ;
         else if(time[][i+]=='.')
             return ;
         else
             return ;
     }
     else
     {
         if(time[][i]=='X')
         {
             if(time[][i+]=='X')
             {
                 if(time[][i+]=='X')
                     return ;
                 else
                     return ;
             }
             else
                 return ;
         }
         else
         {
             if(time[][i+]=='.')
             {
                 if(time[][i+]=='X')
                     return ;
                 else
                     return ;
             }
             else
                 return ;
         }
     }
 }

 int main()
 {
     int a,b,c,d;
     int T;
     scanf("%d",&T);
     while(T--)
     {
         for(int i=;i<=;i++)
             for(int j=;j<=;j++)
                 cin>>time[i][j];
         a=check();
         b=check();
         c=check();
         d=check();
         printf("%d%d:%d%d\n",a,b,c,d);
     }
     return ;
 }