145 is a curious number, as 1! + 4! + 5! = 1 + 24 + 120 = 145.

Find the sum of all numbers which are equal to the sum of the factorial of their digits.

Note: as 1! = 1 and 2! = 2 are not sums they are not included.

#include <iostream>
#include <vector>
using namespace std; vector<int> int_vet(int a)
{
vector<int> res;
while (a)
{
int tmp = a % 10;
a /= 10;
res.push_back(tmp);
}
return res;
} int a[10] = { 0 };
void p()
{
a[0] = 1;
a[1] = 1;
for (int i = 2; i <= 9; i++)
a[i] = a[i - 1] * i;
} int main()
{
p();
int res = 0;
for (int i = 3; i < 10000000; i++)
{
int count = 0;
vector<int> num = int_vet(i);
for (int j = 0; j < num.size(); j++)
count += a[num[j]];
if (count == i)
res += count;
}
cout << res << endl; system("pause");
return 0;
}

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