137. Single Number II
Given an array of integers, every element appears three times except for one. Find that single one.
代码如下:
public class Solution {
public int singleNumber(int[] nums) {
if(nums.length==1||nums.length==2)
return nums[0];
Arrays.sort(nums);
for(int i=0;i<nums.length-2;)
{
if(nums[i]==nums[i+1]&&nums[i]==nums[i+2])
i=i+3;
else return nums[i];
}
return nums[nums.length-1];
}
}
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