Task description

A zero-indexed array A consisting of N integers is given. Rotation of the array means that each element is shifted right by one index, and the last element of the array is also moved to the first place.

For example, the rotation of array A = [3, 8, 9, 7, 6] is [6, 3, 8, 9, 7]. The goal is to rotate array A K times; that is, each element of A will be shifted to the right by K indexes.

Write a function:

class Solution { public int[] solution(int[] A, int K); }

that, given a zero-indexed array A consisting of N integers and an integer K, returns the array A rotated K times.

For example, given array A = [3, 8, 9, 7, 6] and K = 3, the function should return [9, 7, 6, 3, 8].

Assume that:

  • N and K are integers within the range [0..100];
  • each element of array A is an integer within the range [−1,000..1,000].

In your solution, focus on correctness. The performance of your solution will not be the focus of the assessment.

Solution

 
Programming language used: Java
Code: 09:43:49 UTC, java, final, score:  100
// you can also use imports, for example:
// import java.util.*; // you can write to stdout for debugging purposes, e.g.
// System.out.println("this is a debug message"); class Solution {
public int[] solution(int[] A, int K) {
// write your code in Java SE 8
int length = A.length;
int temp[] = new int[length];
if(K<0 || K>100 || length == 0)
return temp;
if(length == 1)
return A;
for(int i=0; i< length; i++) {
temp[(i+K)%length] = A[i];
}
return temp;
}
}

Codility------CyclicRotation的更多相关文章

  1. Codility NumberSolitaire Solution

    1.题目: A game for one player is played on a board consisting of N consecutive squares, numbered from ...

  2. codility flags solution

    How to solve this HARD issue 1. Problem: A non-empty zero-indexed array A consisting of N integers i ...

  3. GenomicRangeQuery /codility/ preFix sums

    首先上题目: A DNA sequence can be represented as a string consisting of the letters A, C, G and T, which ...

  4. *[codility]Peaks

    https://codility.com/demo/take-sample-test/peaks http://blog.csdn.net/caopengcs/article/details/1749 ...

  5. *[codility]Country network

    https://codility.com/programmers/challenges/fluorum2014 http://www.51nod.com/onlineJudge/questionCod ...

  6. *[codility]AscendingPaths

    https://codility.com/programmers/challenges/magnesium2014 图形上的DP,先按照路径长度排序,然后依次遍历,状态是使用到当前路径为止的情况:每个 ...

  7. *[codility]MaxDoubleSliceSum

    https://codility.com/demo/take-sample-test/max_double_slice_sum 两个最大子段和相拼接,从前和从后都扫一遍.注意其中一段可以为0.还有最后 ...

  8. *[codility]Fish

    https://codility.com/demo/take-sample-test/fish 一开始习惯性使用单调栈,后来发现一个普通栈就可以了. #include <stack> us ...

  9. *[codility]CartesianSequence

    https://codility.com/programmers/challenges/upsilon2012 求笛卡尔树的高度,可以用单调栈来做. 维持一个单调递减的栈,每次进栈的时候记录下它之后有 ...

  10. [codility]CountDiv

    https://codility.com/demo/take-sample-test/count_div 此题比较简单,是在O(1)时间里求区间[A,B]里面能被K整除的数字,那么就计算一下就能得到. ...

随机推荐

  1. CORDOVA :添加cordova-plugin-file-opener2插件cordova打包报错

    原文:CORDOVA :添加cordova-plugin-file-opener2插件cordova打包报错 最近在接触android项目,其中涉及到APP自动更新的问题,当新APP下载成功后需要打开 ...

  2. webpack单独构建scss文件与.vue组件里构建scss的一个坑

    在入口main.js里构建scss是通过引入模块的方式 import './assets/_reset.scss'; import './assets/_flex.scss'; import './a ...

  3. 【50.88%】【Codeforces round 382B】Urbanization

    time limit per test2 seconds memory limit per test256 megabytes inputstandard input outputstandard o ...

  4. 矿Java开发学习之旅------&gt;Java排序算法经典的二分法插入排序

    一.折半插入排序(二分插入排序) 将直接插入排序中寻找A[i]的插入位置的方法改为採用折半比較,就可以得到折半插入排序算法.在处理A[i]时,A[0]--A[i-1]已经按关键码值排好序.所谓折半比較 ...

  5. 【oracle ocp 知识点二】

    1.数据库操作语言 DML在运行时下面的语句 添加一个新行到表 更新表现出一定的线 从表删除现有行 一个事务处理是由一系列的DML语句逻辑组成 A.insert 每次插入一行数据 字符和日期的须要单引 ...

  6. 解决:eth0安装插卡无法自己主动,网卡的配置信息不network-scripts于

    问题方案:eth0安装插卡无法自己主动,网卡的配置信息不network-scripts于 解决: 1>vi /etc/rc.d/rc.loacl 最后加 ifup eth0 2>reboo ...

  7. python reversed

    reversed()函数是返回序列seq的反向访问的迭代子.参数可以是列表,元组,字符串,不改变原对象. 例题: 牛客最近来了一个新员工Fish,每天早晨总是会拿着一本英文杂志,写些句子在本子上.同事 ...

  8. VS2015编译环境下CUDA安装配置

    CUDA下载 CUDA是NVIDIA推出的通用并行计算架构,该架构使GPU能够解决复杂的计算问题,CUDA只支持NVIDIA自家的显卡,过旧的版本型号也不被支持. 下载地址:https://devel ...

  9. ude—基于udp的全双工可靠传输协议

    ude是一款基于udp的可靠传输协议,专门用于在数据传输方面对实时性要求较高的应用领域.    tcp协议虽然能保证数据的可靠传输,但它有以下几个缺点:1.tcp的数据确认机制会导致发送方重复发送一些 ...

  10. 【甘道夫】基于Mahout0.9+CDH5.2执行分布式ItemCF推荐算法

    环境: hadoop-2.5.0-cdh5.2.0 mahout-0.9-cdh5.2.0 引言 尽管Mahout已经宣布不再继续基于Mapreduce开发,迁移到Spark.可是实际面临的情况是公司 ...