uva 11054 wine trading in gergovia (归纳【好吧这是我自己起的名字】)——yhx
As you may know from the comic \Asterix and the Chieftain's Shield", Gergovia consists of one street,
and every inhabitant of the city is a wine salesman. You wonder how this economy works? Simple
enough: everyone buys wine from other inhabitants of the city. Every day each inhabitant decides how
much wine he wants to buy or sell. Interestingly, demand and supply is always the same, so that each
inhabitant gets what he wants.
There is one problem, however: Transporting wine from one house to another results in work. Since
all wines are equally good, the inhabitants of Gergovia don't care which persons they are doing trade
with, they are only interested in selling or buying a specic amount of wine. They are clever enough
to gure out a way of trading so that the overall amount of work needed for transports is minimized.
In this problem you are asked to reconstruct the trading during one day in Gergovia. For simplicity
we will assume that the houses are built along a straight line with equal distance between adjacent
houses. Transporting one bottle of wine from one house to an adjacent house results in one unit of
work.
Input
The input consists of several test cases. Each test case starts with the number of inhabitants n
(2 n 100000). The following line contains n integers ai (
uva 11054 wine trading in gergovia (归纳【好吧这是我自己起的名字】)——yhx的更多相关文章
- UVA 11054 Wine trading in Gergovia 葡萄酒交易 贪心+模拟
题意:一题街道上很多酒店,交易葡萄酒,正数为卖出葡萄酒,负数为需要葡萄酒,总需求量和总售出量是相等的,从一家店到另外一家店需要路费(路费=距离×运算量),假设每家店线性排列且相邻两店之间距离都是1,求 ...
- UVa 11054 Wine trading in Gergovia【贪心】
题意:给出n个等距离的村庄,每个村庄要么买酒,要么卖酒,买酒和卖酒的总量相等, 把k个单位的酒从一个村庄运送到相邻的村庄,需要耗费k个单位劳动力,问怎样运送酒使得耗费的劳动力最少 买 卖 ...
- UVa 11054 Wine trading in Gergovia
题意: 直线上有n个等距的酒庄,每个酒庄对酒的需求量为ai(正数说明需要买酒,负数需要卖酒),而且保证所有的酒庄供需平衡. 搬运x个单位的酒到相邻的酒庄需要x个劳动力,求要使所有酒庄供需平衡最少需要多 ...
- UVA 11054 Wine trading in Gergovia(思维)
题目链接: https://vjudge.net/problem/UVA-11054 /* 问题 输入村庄的个数n(2=<n<=100000)和n个村庄的数值,正代表买酒,负代表卖酒,k个 ...
- UVA - 11054 Wine trading in Gergovia 扫描法
题目:点击打开题目链接 思路:考虑第一个村庄,如果第一个村庄需要买酒,那么a1>0,那么一定有劳动力从第二个村庄向第一个村庄搬酒,这些酒可能是第二个村庄生产的,也可能是从其他村庄搬过来的,但这一 ...
- UVA - 11054 Wine trading in Gergovia (Gergovia 的酒交易)(贪心+模拟)
题意:直线上有n(2<=n<=100000)个等距的村庄,每个村庄要么买酒,要么卖酒.设第i个村庄对酒的需求为ai(-1000<=ai<=1000),其中ai>0表示买酒 ...
- 【例题 8-5 UVA - 11054】Wine trading in Gergovia
[链接] 我是链接,点我呀:) [题意] 在这里输入题意 [题解] 考虑第一个店. 如果它要酒的话,只能从第二个店那里运过来. 这样,问题就转化成后n-1个店的问题了. 然后会发现,第二家店它的情况也 ...
- 【uva 11054】Wine trading in Gergovia(算法效率--等价转换)
题意:N个等距村庄,买(>0)卖(<0)酒,供需平衡,运K则需K劳动力.问所需的最小劳动力. 解法:由于运出或运入1的都需经过2,所以无论如何,都可以等价于从2本身运入或运出.因此可以将1 ...
- 8-5 Wine trading in Gergovia Gergovia的酒交易 uva11054
等价转换思维题 题意: 直线上有n(2<=n<=100000)个等距的村庄 每个村庄要么买酒 要么卖酒 设第i个村庄对酒的需求量为ai 绝对值小于一千 其中ai大于0表示买酒 ...
随机推荐
- 【AngularJS学习笔记】01 指令、服务和过滤器
AngularJS 指令是扩展的 HTML 属性,带有前缀 ng-. 比如: ng-app 指令初始化一个 AngularJS 应用程序.注意ng-app一般为空,如果值不为空,就得加这样一句代码va ...
- IIS减少工作线程阻塞的方法
IIS的工作进程(w3wp.exe)只提供了有限的工作线程(Work Thread)来处理请求.如果这些线程都因为要等待长时间运行的任务而阻塞,则运行时会将新来的请求排队,而不是立即执行,Web服务器 ...
- AutoMapper映射ExpressionTree
问题描述 项目中使用AutoMapper进行VO&DTO&Entity的互相映射,但是默认Map方法不支持Expression的转换.如 Expression<Func<E ...
- Selenium&EmguCV实现爬虫图片识别
概述 爬虫需要抓取网站价格,与一般抓取网页区别的是抓取内容是通过AJAX加载,并且价格是通过CSS背景图片显示的. 每一个数字对应一个样式,如'p_h57_5' .p_h57_5 { backgrou ...
- ng-show
//当ng-show="false"时,自动添加 #animate.ng-hide { } #animate.ng-hide-add { } #animate.ng-hide-ad ...
- Force.com微信开发系列(一) 后台配置
为寻找国内免费云资源作为微信后台,花了一天时间试用SinaAppEngine(SAE),调试太不方便用户体验差.新浪作为媒体公司技术功底经不起考验,亚马逊能推出AWS,新浪还不行!更好选项是百度Bai ...
- 独立博客开张!有关读书、GTD和IT方面的内容将发布在新网站上
2015年自己建个独立博客http://www.shenlongbin.com,以后与读书.GTD和IT技术有关的主题都放在个人博客中,2015年计划基本制定,请移步到这里. 感谢博客园提供了如此优秀 ...
- Spring(三)Bean继续入门
一.Aware相关接口 对于应用程序来说,应该尽量减少对Sping Api的耦合程度,然而有些时候为了运用Spring所提供的一些功能,有必要让Bean了解Spring容器对其进行管理的细节信息,如让 ...
- SqlServer int型转varchar型 出现*号
今天调一个bug,错误提示执行语句 * 附近有语法错误,看了存储过程半天没啥反应,我就更本没有* .打印了一下语句发现 where Mor_Id=* 仔细一看set @sqlupdate+=' whe ...
- iOS之学习资源收集--很好的IOS技术学习网站
点击图片也能打开相关的网站: https://boxueio.com/skill/swift http://ios.b2mp.cn/ http://gold.xitu.io/welcome/?utm_ ...