LeetCode_Flatten Binary Tree to Linked List

Given a binary tree, flatten it to a linked list in-place.

For example,
Given

         1
        / \
       2   5
      / \   \
     3   4   6
The flattened tree should look like:
   1
    \
     2
      \
       3
        \
         4
          \
           5
            \
             6

　思路; 展开后的树其实就是先根遍历的一个结果，不过注意是连接在右子树上。所以先做了一下先根遍历，并保存结果最后按照展开规则处理每个节点。

/**
 * Definition for binary tree
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
private :
  vector<TreeNode *> temp ;// record the preOrder result
public:
   void preOrder(TreeNode *root){
    temp.push_back(root);
    if(root->left) preOrder(root->left);
    if(root->right) preOrder(root->right);

   }
    void flatten(TreeNode *root) {
        // Start typing your C/C++ solution below
        // DO NOT write int main() function
        temp.clear();
        if(root == NULL) return ;
        preOrder(root);
        for(int i = ; i< temp.size()-; i++)
         {
            temp[i]->right = temp[i+];
            temp[i]->left = NULL ;
         }

    }
};