hdu 1015(DFS)
Safecracker
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 13237 Accepted Submission(s): 6897
"The
item is locked in a Klein safe behind a painting in the second-floor
library. Klein safes are extremely rare; most of them, along with Klein
and his factory, were destroyed in World War II. Fortunately old
Brumbaugh from research knew Klein's secrets and wrote them down before
he died. A Klein safe has two distinguishing features: a combination
lock that uses letters instead of numbers, and an engraved quotation on
the door. A Klein quotation always contains between five and twelve
distinct uppercase letters, usually at the beginning of sentences, and
mentions one or more numbers. Five of the uppercase letters form the
combination that opens the safe. By combining the digits from all the
numbers in the appropriate way you get a numeric target. (The details of
constructing the target number are classified.) To find the combination
you must select five letters v, w, x, y, and z that satisfy the
following equation, where each letter is replaced by its ordinal
position in the alphabet (A=1, B=2, ..., Z=26). The combination is then
vwxyz. If there is more than one solution then the combination is the
one that is lexicographically greatest, i.e., the one that would appear
last in a dictionary."
v - w^2 + x^3 - y^4 + z^5 = target
"For
example, given target 1 and letter set ABCDEFGHIJKL, one possible
solution is FIECB, since 6 - 9^2 + 5^3 - 3^4 + 2^5 = 1. There are
actually several solutions in this case, and the combination turns out
to be LKEBA. Klein thought it was safe to encode the combination within
the engraving, because it could take months of effort to try all the
possibilities even if you knew the secret. But of course computers
didn't exist then."
=== Op tech directive, computer division, 2002/11/02 12:30 CST ===
"Develop
a program to find Klein combinations in preparation for field
deployment. Use standard test methodology as per departmental
regulations. Input consists of one or more lines containing a positive
integer target less than twelve million, a space, then at least five and
at most twelve distinct uppercase letters. The last line will contain a
target of zero and the letters END; this signals the end of the input.
For each line output the Klein combination, break ties with
lexicographic order, or 'no solution' if there is no correct
combination. Use the exact format shown below."
#include<iostream>
#include<cstdio>
#include<cmath>
#include<map>
#include<cstdlib>
#include<vector>
#include<set>
#include<queue>
#include<cstring>
#include<string.h>
#include<algorithm>
#define INF 0x3f3f3f3f
typedef long long ll;
typedef unsigned long long LL;
using namespace std;
const int N = 1e6+;
const ll mod = 1e9+;
char s[];
int a[];
int b[];
int visited[];
int n;
int flag=;
void DFS(int t){
if(flag==)return;
if(t==){
int sum1=b[]+b[]*b[]*b[]+b[]*b[]*b[]*b[]*b[];
int sum2=b[]*b[]+b[]*b[]*b[]*b[];
if(sum1-sum2==n){
flag=;
printf("%c%c%c%c%c\n",b[]-+'A',b[]-+'A',b[]-+'A',b[]-+'A',b[]-+'A');
return ;
}
return ;
}
for(int i=;i>=;i--){
if(visited[i]==)continue;
else if(visited[i]==&&a[i]==){
visited[i]=;
b[t]=i;
DFS(t+);
visited[i]=;
}
}
}
int main(){
while(scanf("%d %s",&n,s)!=EOF){
if(n==&&strcmp(s,"END")==)break;
int len=strlen(s);
flag=;
memset(a,,sizeof(a));
for(int i=;i<len;i++){
int tt=s[i]-'A'+;
a[tt]=;
}
memset(visited,,sizeof(visited));
DFS();
if(flag==)cout<<"no solution"<<endl; } }
hdu 1015(DFS)的更多相关文章
- HDOJ(HDU).1015 Safecracker (DFS)
HDOJ(HDU).1015 Safecracker [从零开始DFS(2)] 从零开始DFS HDOJ.1342 Lotto [从零开始DFS(0)] - DFS思想与框架/双重DFS HDOJ.1 ...
- hdu 1342(DFS)
Lotto Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submi ...
- F - JDG HDU - 2112 (最短路)&& E - IGNB HDU - 1242 (dfs)
经过锦囊相助,海东集团终于度过了危机,从此,HDU的发展就一直顺风顺水,到了2050年,集团已经相当规模了,据说进入了钱江肉丝经济开发区500强.这时候,XHD夫妇也退居了二线,并在风景秀美的诸暨市浬 ...
- F - Auxiliary Set HDU - 5927 (dfs判断lca)
题目链接: F - Auxiliary Set HDU - 5927 学习网址:https://blog.csdn.net/yiqzq/article/details/81952369题目大意一棵节点 ...
- hdu - 1072(dfs剪枝或bfs)
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1072 思路:深搜每一个节点,并且进行剪枝,记录每一步上一次的s1,s2:如果之前走过的时间小于这一次, ...
- HDU——2647Reward(DFS或差分约束)
Reward Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total Sub ...
- P - Sudoku Killer HDU - 1426(dfs + map统计数据)
P - Sudoku Killer HDU - 1426 自从2006年3月10日至11日的首届数独世界锦标赛以后,数独这项游戏越来越受到人们的喜爱和重视. 据说,在2008北京奥运会上,会将数独列为 ...
- hdu 1142(DFS+dijkstra)
#include<iostream> #include<cstdio> #include<cmath> #include<map> #include&l ...
- hdu 1181(DFS)变 形 课
变形课 Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 131072/65536 K (Java/Others)Total Submis ...
随机推荐
- CCS3.3下执行优化
最近想研究一下CCS下的程序优化,之前也了解一些,现在查阅一下资料,整理一下. 当然优化有很多种,我本次先说的是执行优化方式. 首先打开我们自己的工程.工程文件若显示为黄色的,则表示此文件默认优化选项 ...
- $.grep(array, callback, [invert])过滤,常用
$.grep(array, callback, [invert])过滤,常用 解释: 使用过滤函数过滤数组元素.此函数至少传递两个参数(第三个参数为true或false,对过滤函数返回值取反,个人觉得 ...
- Android菜鸟成长记10 -- ListVew
ListView在我们学习Android的过程中是非常重要得一个部分. listview主要有两个职责 1)将数据填充到布局. 2)处理用户的选择点击等操作. 一个ListView的创建需要3个元素 ...
- NetBios 的结构体详解
[NetBios 的结构体详解] NetBIOS是早期的局域网传输协议. 1.结构体. 2.命令 NetBIOS命令的使用方式有两种,即等待和非等待(或称为同步与异步)方式. 如果命令码的高阶位是0时 ...
- 配置BUG-Linux系统下ssh登陆很慢的解决办法
很多的Linux用户发现连接上Linux服务器在输入用户名之后还要再等一下才能输入密码,时间过长了,现在小编与大家分享一下如何解决ssh登陆问题的问题,希望对您有所帮助 . 1.我们平时登陆Linux ...
- Versioned table in Netezza
Problem One QC process need to obtain tables and their row counts in a database in Netezza. We use t ...
- SQL Server中 ldf 文件过大的解决方法
在SQL Server中经常遇到事务日志变大的情况,除了将数据库设置为"自动收缩"外,还可以使用下面的SQL命令进行快速清除数据库中的事务日志,命令如下: - 第一步:清空日志 ...
- Markdown syntax guide and writing on MWeb
Philosophy Markdown is intended to be as easy-to-read and easy-to-write as is feasible.Readability, ...
- 技术英文单词贴--I
I increase 增加,增大 individual 个人的,个别的 instead 代替 integer 整数,整形
- LR连接oracle数据库-lr_db_connect
在Loadrunner中也提供了C对数据库操作的相关功能函数,以下这些数据库功能函数只能用于Web Services协议. lr_db_connect 连接数据库 lr_db_disconnect 断 ...