转载自:https://www.reddit.com/r/swift/comments/2w19kp/how_do_you_send_a_through_nsmutableurlrequest/

how do you send a ? through NSMutableURLRequest without encoding the ? as %3F (self.swift)

submitted 1 year ago by xStory_Timex

I have a enum Router.swift that helps me use alamofire to interact with my API.

recently i changed the API and now when i send a URL request my code changes the "?" to "%3F" which i believe is "?" in url encoding.

here is the code Look at .ReadBrandProducts /products?brand_id=(id) when the id is 1 the request comes back as /products%3Fbrand_id=1

var path: String {
switch self {
case .AddReview(let id, _):
return "/products/\(id)/reviews"
case .ReadBrands:
return "/brands"
case .ReadBrandProducts(let id):
return "/products?brand_id=\(id)"
case .ReadProductData(let id):
return "/products/\(id)"
case .ReadReviews(let id):
return "/products/\(id)/reviews"
case .Favorite(let id):
return "/products/\(id)/favorite"
case .readFeed:
return "/activity"
}
} // MARK: URLRequestConvertible var URLRequest: NSURLRequest {
let URL = NSURL(string: Router.baseURLString)!
let mutableURLRequest = NSMutableURLRequest(URL: URL.URLByAppendingPathComponent(path))
mutableURLRequest.HTTPMethod = method.rawValue if let token = KeychainService.loadToken() {
mutableURLRequest.setValue("Bearer \(token)", forHTTPHeaderField: "Authorization")
}
 
 
 
 
sorted by:

best
 
 

[–]lyinstevemod 2 points 1 year ago

If you're using Alamofire, you should really be submitting URL encoded parameters as a dictionary instead, because Alamofire handles serialization. You're doing more work than you should.

 

[–]xStory_Timex[S] 1 point 1 year ago

I don't understand, can you explain more

 

[–]lyinstevemod 1 point 1 year ago

So right now you're adding URL parameters, right? And you're serializing them into a string yourself.

You also said you're using Alamofire. Alamofire will actually take those arguments in a Dictionary as a parameter to the request() function. You don't need to -- and shouldn't -- manually create those strings.

Specifically just

?brand_id=\(id)

Instead, pass the parameters into the Alamofire request() function.

Alamofire.request(
.GET,
"/products",
parameters: ["brand_id": id]
)
 
 
 
 
 
 
 
 
 
 
 
 
 

QuestionQuestion mark is HTML escaped in NSMutableURLRequest self.iOSProgramming

Submitted 4 months ago by fourth_throwaway

ok, so I have an API that I built using ruby on rails. Pagination works completely in both the website and the API. Here is the api: https://sheltered-shelf-7331.herokuapp.com/api/yaks?page=1

just change out "page=1" at the end for "page=2" or "3", etc, and you'll see it works.

the problem though is that the "?" is read by the URL request as "%3F". Here is how the url request is printed in the console in Xcode:

  URL: https://sheltered-shelf-7331.herokuapp.com/api/yaks%3F

So of course it has a response of html status code 404. How can I make the question mark not be converted to %3F in the URL? I'm using URLRequest Convertible. Here is my code:

static let baseURL = "https://sheltered-shelf-7331.herokuapp.com"
let result: (path: String, parameters: [String: AnyObject]?) = { switch self {
case GetMainFeed:
return ("/api/yaks?", nil)
case PostLogin(let username, let password):
return ("/api/sessions", ["username": username, "password": password])
case PostCreateUser(let username, let password):
print(username, password)
return ("/api/users", ["username": username, "password": password])
case PostSendYak(let description, let image):
sending = true
return ("/api/yaks", ["description": description, "image": image])
case GetMyYaks:
sending = true
return ("/api/my-yaks", nil)
}
}() let url = NSURL(string: Router.baseURL)
let URLRequest = NSMutableURLRequest(URL: (url?.URLByAppendingPathComponent(result.path))!)
let encoding = Alamofire.ParameterEncoding.JSON
print(URLRequest)
if sending == true {
let defaults = NSUserDefaults.standardUserDefaults()
if let token = defaults.objectForKey("auth_token") as? String {
print(token)
URLRequest.setValue(token, forHTTPHeaderField: "Authorization")
} }
URLRequest.addValue("application/json", forHTTPHeaderField: "Content-Type")
let (encodedRequest, _) = encoding.encode(URLRequest, parameters: result.parameters)
encodedRequest.HTTPMethod = method.rawValue
return encodedRequest
 
 
 
all 3 comments
sorted by:

best
 
 

[–]Power781 2 points 4 months ago

It's not how URL parameters work.
the endpoint is /api/yaks
page=x is a parameter of your call.
you just have to set the encoding to let encoding = Alamofire.ParameterEncoding.URL depending on if you have URL parameters or body parameters.
Example on how I did it :

    public var parametersEncoding: Alamofire.ParameterEncoding {
switch self.method {
case .GET :
return .URL
case .POST, .PUT:
return .JSON
default:
return .JSON
}
}
 
 
 
 

[–]AyyBodyFrizzesAlone 1 point 4 months ago

?page=1 is not a path component. It's a URI parameter. Just append it with stringByAppendingString.

 

[–]tonygoold 1 point 4 months ago

It's actually the query, not the parameter (which isn't used by HTTP), an important distinction if you're trying to get the query string from an NSURL. You're right about why it's encoding the question mark though.

%3f URL --> '?'拼接引发的问题的更多相关文章

  1. php 对url 操作类:url拼接、get获取页面、post获取页面(带传参)

    /* * @brief url封装类,将常用的url请求操作封装在一起 * */ class URL{ private $error; public function __construct(){ $ ...

  2. url拼接

    在做网页抓取的时候经常会遇到一个问题就是页面中的链接是相对链接,这个时候就需要对链接进行url拼接,才能得到绝对链接. url严格按照一定的格式构成,一般为如下5个字段: 详细可参考RFC:http: ...

  3. Python相对完美的URL拼接函数

    首先说下什么叫URL拼接,我们有这么一个HTML片段:   <a href="../../a.html">click me</a> 做为一只辛苦的爬虫,我们 ...

  4. url拼接参数格式

    在一些情况下,需要直接往url上拼接请求参数. http://www.yanggb.com?flag=1&type=normal&role=customer 通过上面的例子就可以看出, ...

  5. Ajax获取接口数据,url拼接参数跳转页面,js获取上一级页面参数给本页面

    1.Ajax获取接口数据 function demo(){ //假设请求参数 var requestBody = [{ "name":"zhang", &quo ...

  6. 字符串拼接引发的BUG

    译者按: bug虽小,却是个磨人的小妖精! 原文: Fixing a bug: when concatenated strings turn into numbers in JavaScript 译者 ...

  7. 接口测试get请求url拼接函数(python)

    get请求地址一般是 协议+域名+端口+路径+参数,除了协议和域名其他均可为空.  http(s)://domain:port/path?key1=value1&key2=value2& ...

  8. 相对URL拼接为绝对URL的过程

    URL有两种方式:绝对的和相对的. 绝对URL中包含有访问资源的所需的全部信息 举一个例子: <HTML> <HEAD><TITLE>Joe's Tools< ...

  9. 关于url拼接传参数和利用view的字典传参数时,模板获取数据的方式问题

    url = "{% url 'dashboard:internship-theme-stat' %}?teacher_name="+teacher_name+"& ...

随机推荐

  1. 二、WCF应用的通信过程

    注:本文为学习摘抄,原文地址:http://www.cnblogs.com/iamlilinfeng/archive/2012/09/26/2703759.html 一.概述 WCF能够建立一个跨平台 ...

  2. ECOS CMD更新

    update update --force-update-db

  3. ajax的项目实操(只用于记录部分文件未引入)

    <!DOCTYPE HTML> <html> <head> <meta http-equiv="Content-Type" content ...

  4. 让人头疼的CSS兼容

    先说点Hack的知识(真正的高手是不用Hack的,但要成为高手必须通过Hack这一关) /* CSS属性级Hack */ color:red; /* 所有浏览器可识别*/ _color:red; /* ...

  5. samba连接提示“找不到网络路径”

    在运行里面输入services.msc,打开服务管理界面. 根据服务的描述,找到了TCP/IP NetBIOS Helper服务描述中提到TCP/IP NetBIOS Helper服务能使用户能够共享 ...

  6. MyBatis 批量修改记录

    <insert id="update" parameterType="java.util.List"> UPDATE setting SET con ...

  7. [WPF] 浏览百度地图并获取经纬度地址信息

    项目中需要利用登记的区域和地址在百度地图上定位,并获取该地址的经纬度. 本次功能对我来说主要难点如下:1.百度地图API的基本使用方法,请首选使用百度地图的JavaScript大众版(PS:之前使用W ...

  8. Java 微信登录授权后获取微信用户信息昵称乱码问题解决

    String getUserInfoUrl = "https://api.weixin.qq.com/sns/userinfo?access_token="+access_toke ...

  9. java学习第21天(IO流的使用)

    IO流分类: A:流向 输入流 读取数据 输出流 写出数据 B:数据类型 字节流 字节输入流 字节输出流 字符流 字符输入流 字符输出流 注意: a:如果我们没有明确说明按照什么分,默认按照数据类型分 ...

  10. openwrt 中make的使用

    make 命令简单说明 make V=99 V=99表示输出详细的debug信息 make world 表示编译所有 make j=2 V=99 如是多核CPU,加j=2 选项理论上能加快编译速度 m ...