%3f URL --> '?'拼接引发的问题
转载自:https://www.reddit.com/r/swift/comments/2w19kp/how_do_you_send_a_through_nsmutableurlrequest/
how do you send a ? through NSMutableURLRequest without encoding the ? as %3F (self.swift)
submitted 1 year ago by xStory_Timex
I have a enum Router.swift that helps me use alamofire to interact with my API.
recently i changed the API and now when i send a URL request my code changes the "?" to "%3F" which i believe is "?" in url encoding.
here is the code Look at .ReadBrandProducts /products?brand_id=(id) when the id is 1 the request comes back as /products%3Fbrand_id=1
var path: String {
switch self {
case .AddReview(let id, _):
return "/products/\(id)/reviews"
case .ReadBrands:
return "/brands"
case .ReadBrandProducts(let id):
return "/products?brand_id=\(id)"
case .ReadProductData(let id):
return "/products/\(id)"
case .ReadReviews(let id):
return "/products/\(id)/reviews"
case .Favorite(let id):
return "/products/\(id)/favorite"
case .readFeed:
return "/activity"
}
}
// MARK: URLRequestConvertible
var URLRequest: NSURLRequest {
let URL = NSURL(string: Router.baseURLString)!
let mutableURLRequest = NSMutableURLRequest(URL: URL.URLByAppendingPathComponent(path))
mutableURLRequest.HTTPMethod = method.rawValue
if let token = KeychainService.loadToken() {
mutableURLRequest.setValue("Bearer \(token)", forHTTPHeaderField: "Authorization")
}
[–]lyinstevemod 2 points 1 year ago
If you're using Alamofire, you should really be submitting URL encoded parameters as a dictionary instead, because Alamofire handles serialization. You're doing more work than you should.
[–]xStory_Timex[S] 1 point 1 year ago
I don't understand, can you explain more
[–]lyinstevemod 1 point 1 year ago
So right now you're adding URL parameters, right? And you're serializing them into a string yourself.
You also said you're using Alamofire. Alamofire will actually take those arguments in a Dictionary as a parameter to the request() function. You don't need to -- and shouldn't -- manually create those strings.
Specifically just
?brand_id=\(id)
Instead, pass the parameters into the Alamofire request() function.
Alamofire.request(
.GET,
"/products",
parameters: ["brand_id": id]
)
QuestionQuestion mark is HTML escaped in NSMutableURLRequest self.iOSProgramming
Submitted 4 months ago by fourth_throwaway
ok, so I have an API that I built using ruby on rails. Pagination works completely in both the website and the API. Here is the api: https://sheltered-shelf-7331.herokuapp.com/api/yaks?page=1
just change out "page=1" at the end for "page=2" or "3", etc, and you'll see it works.
the problem though is that the "?" is read by the URL request as "%3F". Here is how the url request is printed in the console in Xcode:
URL: https://sheltered-shelf-7331.herokuapp.com/api/yaks%3F
So of course it has a response of html status code 404. How can I make the question mark not be converted to %3F in the URL? I'm using URLRequest Convertible. Here is my code:
static let baseURL = "https://sheltered-shelf-7331.herokuapp.com"
let result: (path: String, parameters: [String: AnyObject]?) = {
switch self {
case GetMainFeed:
return ("/api/yaks?", nil)
case PostLogin(let username, let password):
return ("/api/sessions", ["username": username, "password": password])
case PostCreateUser(let username, let password):
print(username, password)
return ("/api/users", ["username": username, "password": password])
case PostSendYak(let description, let image):
sending = true
return ("/api/yaks", ["description": description, "image": image])
case GetMyYaks:
sending = true
return ("/api/my-yaks", nil)
}
}()
let url = NSURL(string: Router.baseURL)
let URLRequest = NSMutableURLRequest(URL: (url?.URLByAppendingPathComponent(result.path))!)
let encoding = Alamofire.ParameterEncoding.JSON
print(URLRequest)
if sending == true {
let defaults = NSUserDefaults.standardUserDefaults()
if let token = defaults.objectForKey("auth_token") as? String {
print(token)
URLRequest.setValue(token, forHTTPHeaderField: "Authorization")
}
}
URLRequest.addValue("application/json", forHTTPHeaderField: "Content-Type")
let (encodedRequest, _) = encoding.encode(URLRequest, parameters: result.parameters)
encodedRequest.HTTPMethod = method.rawValue
return encodedRequest
[–]Power781 2 points 4 months ago
It's not how URL parameters work.
the endpoint is /api/yaks
page=x is a parameter of your call.
you just have to set the encoding to let encoding = Alamofire.ParameterEncoding.URL depending on if you have URL parameters or body parameters.
Example on how I did it :
public var parametersEncoding: Alamofire.ParameterEncoding {
switch self.method {
case .GET :
return .URL
case .POST, .PUT:
return .JSON
default:
return .JSON
}
}
[–]AyyBodyFrizzesAlone 1 point 4 months ago
?page=1 is not a path component. It's a URI parameter. Just append it with stringByAppendingString.
%3f URL --> '?'拼接引发的问题的更多相关文章
- php 对url 操作类:url拼接、get获取页面、post获取页面(带传参)
/* * @brief url封装类,将常用的url请求操作封装在一起 * */ class URL{ private $error; public function __construct(){ $ ...
- url拼接
在做网页抓取的时候经常会遇到一个问题就是页面中的链接是相对链接,这个时候就需要对链接进行url拼接,才能得到绝对链接. url严格按照一定的格式构成,一般为如下5个字段: 详细可参考RFC:http: ...
- Python相对完美的URL拼接函数
首先说下什么叫URL拼接,我们有这么一个HTML片段: <a href="../../a.html">click me</a> 做为一只辛苦的爬虫,我们 ...
- url拼接参数格式
在一些情况下,需要直接往url上拼接请求参数. http://www.yanggb.com?flag=1&type=normal&role=customer 通过上面的例子就可以看出, ...
- Ajax获取接口数据,url拼接参数跳转页面,js获取上一级页面参数给本页面
1.Ajax获取接口数据 function demo(){ //假设请求参数 var requestBody = [{ "name":"zhang", &quo ...
- 字符串拼接引发的BUG
译者按: bug虽小,却是个磨人的小妖精! 原文: Fixing a bug: when concatenated strings turn into numbers in JavaScript 译者 ...
- 接口测试get请求url拼接函数(python)
get请求地址一般是 协议+域名+端口+路径+参数,除了协议和域名其他均可为空. http(s)://domain:port/path?key1=value1&key2=value2& ...
- 相对URL拼接为绝对URL的过程
URL有两种方式:绝对的和相对的. 绝对URL中包含有访问资源的所需的全部信息 举一个例子: <HTML> <HEAD><TITLE>Joe's Tools< ...
- 关于url拼接传参数和利用view的字典传参数时,模板获取数据的方式问题
url = "{% url 'dashboard:internship-theme-stat' %}?teacher_name="+teacher_name+"& ...
随机推荐
- strstr() strpos() 获取db报错,判断报错中是否包含字符串,判断错误类型
model中直接获取添加公司的错误.(公司名称不能重复) $enterprise_id = $this->add($enterprisedata ); $err = $this->getD ...
- Lua高级教程Metatables
什么是Metatable metatable是Lua中的重要概念,每一个table都可以加上metatable,以改变相应的table的行为. Metatables举例 -- 声明一个正常的关系变量 ...
- [SOJ] 1282. Computer games (KMP)
坑爹题 1282. Computer Game Constraints Time Limit: 1 secs, Memory Limit: 32 MB Description Brian is an ...
- Java comparable 和 comparator
一.comparator 接口继承 public class ComparatorTest { /** * @param args */ public static void main(String[ ...
- 找斐波那契数列中的第N个数——递归与函数自调用算法
题目描述 Description 用递归的方法求斐波那契数列中的第N个数 输入输出格式 Input/output 输入格式:一行,一个正整数n输出格式: 一行,一个数,表示斐波那契数列中的第N个数 ...
- Openjudge-计算概论(A)-与7无关的数
描述: 一个正整数,如果它能被7整除,或者它的十进制表示法中某一位上的数字为7,则称其为与7相关的数.现求所有小于等于n(n < 100)的与7无关的正整数的平方和. 输入输入为一行,正整数n( ...
- Python 的方法重载
为防止两个模块互相导入的问题,Python默认所有的模块都只导入一次,如果需要重新导入模块,Python2 7可以直接用reload(),Python3可以用下 为防止两个模块互相导入的问题,Pyth ...
- Struts2如何传值到jsp页面
Struts2如何传值到jsp页面 不是action传值到jsp页面,而是jsp页面获取action中的属性值,或者范围(如request,session,application等)里的值.所以,有两 ...
- 【转】解决Windows不能在本地计算机启动apache tomcat
http://blog.163.com/ftskwsg@126/blog/static/5623853020094494117827/ 这个方法解决了我的问题. 在windows下以服务的方式启动时提 ...
- ios沙盒查找图片展示
iOS如何找到自己的沙盒 在ios开发我们会用到沙盒,由于自己对沙盒理解的不够,所以找不到沙盒文件在哪里,当然要知道路径了 例如我的路径 NSString* cachepath = [NSHomeDi ...