PAT (Advanced Level) 1082. Read Number in Chinese (25)
模拟题。
#include<cstdio>
#include<cstring>
#include<cmath>
#include<vector>
#include<map>
#include<stack>
#include<queue>
#include<string>
#include<iostream>
#include<algorithm>
using namespace std; string num[]=
{
"ling","yi","er","san","si",
"wu","liu","qi","ba","jiu"
};
string tmp="";
string ans="";
string s=""; string f(string TMP)
{
if(TMP[]==''&&TMP[]==''&&TMP[]==''&&TMP[]=='') return "ling";
string t="";
int p;
for(int i=TMP.length()-;i>=;i--)
if(TMP[i]!='') {p=i; break;} for(int i=;i<=p;i++) t=t+TMP[i]; if(t=="" ) return "ling"; if(t.length()==) return "ling";
if(t.length()==) return num[t[]-''];
if(t.length()==)
{
if(t[]=='') return num[t[]-'']+" Shi";
return num[t[]-'']+" shi "+num[t[]-''];
}
if(t.length()==)
{
if(t[]==''&&t[]=='') return num[t[]-'']+" Bai";
if(t[]==''&&t[]!='') return num[t[]-'']+" Bai "+num[t[]-'']+" Shi";
if(t[]!=''&&t[]=='') return num[t[]-'']+" Bai ling "+num[t[]-''];
if(t[]!=''&&t[]!='') return num[t[]-'']+" Bai "+num[t[]-'']+" Shi "+num[t[]-''];
}
if(t.length()==)
{
if(t[]==''&&t[]==''&&t[]=='') return num[t[]-'']+" Qian";
if(t[]!=''&&t[]==''&&t[]=='') return num[t[]-'']+" Qian ling "+num[t[]-''];
if(t[]==''&&t[]!=''&&t[]=='') return num[t[]-'']+" Qian ling "+num[t[]-'']+" Shi";
if(t[]!=''&&t[]!=''&&t[]=='') return num[t[]-'']+" Qian ling "+num[t[]-'']+" Shi "+num[t[]-''];
if(t[]==''&&t[]==''&&t[]!='') return num[t[]-'']+" Qian "+num[t[]-'']+" Bai";
if(t[]!=''&&t[]==''&&t[]!='') return num[t[]-'']+" Qian "+num[t[]-'']+" Bai ling "+num[t[]-''];
if(t[]==''&&t[]!=''&&t[]!='') return num[t[]-'']+" Qian "+num[t[]-'']+" Bai "+num[t[]-'']+" Shi";
if(t[]!=''&&t[]!=''&&t[]!='') return num[t[]-'']+" Qian "+num[t[]-'']+" Bai "+num[t[]-'']+" Shi "+num[t[]-''];
}
} int main()
{
cin>>tmp;
int len=tmp.length();
for(int i=;i<len/;i++)
swap(tmp[i],tmp[len-i-]); if(tmp[tmp.length()-]=='-') ans=ans+"Fu "; for(int i=;i<tmp.length();i++)
{
if(tmp[i]=='-') continue;
else s=s+tmp[i];
} if(s.length()==)
{
string s1,s2,s3; string g="";
g=g+s[]+s[]+s[]+s[];
s2=f(g); g="";
g=g+s[]+s[]+s[]+s[];
s3=f(g); ans=ans+num[s[s.length()-]-'']+" Yi"; if(s2=="ling") {}
else
{
ans=ans+" ";
if(s[]=='') ans=ans+"ling ";
ans=ans+s2;
ans=ans+" Wan";
} if(s3=="ling"){}
else
{
ans=ans+" ";
if(s[]=='') ans=ans+"ling ";
ans=ans+s3;
}
}
else if(s.length()>=&&s.length()<=)
{
string s2;
string s3; int len=s.length();
for(int i=len;i<;i++) s=s+''; string g;
g=g+s[]+s[]+s[]+s[];
s2=f(g); g="";
g=g+s[]+s[]+s[]+s[];
s3=f(g); ans=ans+s2;
ans=ans+" Wan"; if(s3=="ling"){}
else
{
ans=ans+" ";
if(s[]=='') ans=ans+"ling ";
ans=ans+s3;
} }
else if(s.length()<=)
{
string s3; int len=s.length();
for(int i=len;i<;i++) s=s+''; string g;
g=g+s[]+s[]+s[]+s[];
s3=f(g); ans=ans+s3;
} cout<<ans<<endl; return ;
}
PAT (Advanced Level) 1082. Read Number in Chinese (25)的更多相关文章
- PTA (Advanced Level)1082.Read Number in Chinese
Given an integer with no more than 9 digits, you are supposed to read it in the traditional Chinese ...
- 【PAT甲级】1082 Read Number in Chinese (25 分)
题意: 输入一个九位整数,输出它的汉字读法(用拼音表示). trick: 字符串数组""其实会输出一个空格,而不是什么都不输出,导致测试点0和4格式错误. AAAAAccepted ...
- PAT (Advanced Level) 1024. Palindromic Number (25)
手动模拟加法高精度. 注意:如果输入数字的就是回文,这个时候输出0步. #include<iostream> #include<cstring> #include<cma ...
- PAT (Advanced Level) Practise - 1094. The Largest Generation (25)
http://www.patest.cn/contests/pat-a-practise/1094 A family hierarchy is usually presented by a pedig ...
- 1082. Read Number in Chinese (25)
题目如下: Given an integer with no more than 9 digits, you are supposed to read it in the traditional Ch ...
- 1082. Read Number in Chinese (25)-字符串处理
题意就是给出9位以内的数字,按照汉子的读法读出来. 读法请看下方的几个例子: 5 0505 0505 伍亿零伍佰零伍万零伍佰零伍 5 5050 5050 伍亿伍仟零伍拾万伍仟零伍拾 (原本我以为这个 ...
- 1082 Read Number in Chinese (25分)
// 1082.cpp : 定义控制台应用程序的入口点. // #include <iostream> #include <string> #include <vecto ...
- PAT (Advanced Level) 1102. Invert a Binary Tree (25)
简单题. #include<cstdio> #include<cstring> #include<cmath> #include<vector> #in ...
- PAT (Advanced Level) 1098. Insertion or Heap Sort (25)
简单题.判断一下是插排还是堆排. #include<cstdio> #include<cstring> #include<cmath> #include<ve ...
随机推荐
- mybatis 做 insert操作的时候返回插入的那条数据的id
著作权归作者所有.商业转载请联系作者获得授权,非商业转载请注明出处.作者:吃丸子的小鹿链接:http://www.zhihu.com/question/20810321/answer/16843223 ...
- Oracle自增长序列
create table user_info ( id number(6) primary key, username varchar2(30) not null, password varchar2 ...
- java socket解析和发送二进制报文工具(附java和C++转化问题)
解析: 首先是读取字节: /** * 读取输入流中指定字节的长度 * <p/> * 输入流 * * @param length 指定长度 * @return 指定长度的字节数组 */ pu ...
- nginx之fastcgi
fastcgi的应用程序就是一个while循环在,不停的accept,如果收到相应的服务请求则负责服务并将结果返回. 在fastcgi的进程环境中,标准输入与标准输出已经被重定向到了监听的socket ...
- svn 设置文件可执行权限
本地文件在commit到仓库之前若没有chmod +x 权限的话,那在svn仓库里的文件将会保持当前无可执行属性状态. 即使在本地chmod +x filename 之后,再提交到仓库也是没有用的.c ...
- Django - 模型表单(创建、更新、删除)
urls.py # /music/alubm/add/ url(r'^album/add/$', views.AlbumCreate.as_view(), name="album-add&q ...
- Ng-model undefined in the controller
这个问题是我最近在项目中碰到的,暂时没找到原因,找到一个解决方法,还多请大神指教,在Stack Overflow找到解决方法: I am having some "problems" ...
- jq的合成事件
jq中有两个合成事件 hover()和toggle() 1.hover() hover方法用于模拟光标悬停事件.当光标移动到元素上时,会触发指定的第一个函数(enter),当光标移出这个元素时,会触发 ...
- 修改maven本地仓库路径
修改maven配置文件conf/settings.xml 在setting标签中添加 <localRepository>E:/bhuwifi_java/repo</localRepo ...
- 利用线程把文本文件填充到richTextBox;防止导入大文本文件窗口假死现象
private void btnDr_Click(object sender, EventArgs e) { richTextBox1.Text = ""; //richTextB ...