Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list.

Example 1:

Input: 1->2->3->3->4->4->5
Output: 1->2->5

Example 2:

Input: 1->1->1->2->3
Output: 2->3
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) { val = x; }
* }
*/
class Solution {
public ListNode deleteDuplicates(ListNode head) {
if (head == null || head.next == null) {
return head;
} ListNode dummy = new ListNode(-1);
dummy.next = head;
ListNode cur = dummy;
// check the next two node
while(cur.next != null && cur.next.next != null) {
if (cur.next.val == cur.next.next.val) {
int num = cur.next.val;
while(cur.next != null && cur.next.val == num) {
cur.next = cur.next.next;
}
} else {
cur = cur.next;
}
}
return dummy.next;
}
}

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