Game on Tree
D - Game on Tree
Time limit : 2sec / Memory limit : 256MB
Score : 1100 points
Problem Statement
There is a tree with N vertices numbered 1,2,…,N. The edges of the tree are denoted by (xi,yi).
On this tree, Alice and Bob play a game against each other. Starting from Alice, they alternately perform the following operation:
- Select an existing edge and remove it from the tree, disconnecting it into two separate connected components. Then, remove the component that does not contain Vertex 1.
A player loses the game when he/she is unable to perform the operation. Determine the winner of the game assuming that both players play optimally.
Constraints
- 2≤N≤100000
- 1≤xi,yi≤N
- The given graph is a tree.
Input
Input is given from Standard Input in the following format:
N
x1 y1
x2 y2
:
xN−1 yN−1
Output
Print Alice if Alice wins; print Bob if Bob wins.
Sample Input 1
5
1 2
2 3
2 4
4 5
Sample Output 1
Alice
If Alice first removes the edge connecting Vertices 1 and 2, the tree becomes a single vertex tree containing only Vertex 1. Since there is no edge anymore, Bob cannot perform the operation and Alice wins.
Sample Input 2
5
1 2
2 3
1 4
4 5
Sample Output 2
Bob
Sample Input 3
6
1 2
2 4
5 1
6 3
3 2
Sample Output 3
Alice
Sample Input 4
7
1 2
3 7
4 6
2 3
2 4
1 5
Sample Output 4
Bob
在树上的博弈,从0,1开始看看这棵树的异或和
#include <bits/stdc++.h>
using namespace std;
const int N=;
vector<int>vec[N];
int dfs(int u,int fa) {
int re=;
for(int i=; i<vec[u].size(); i++) {
if(vec[u][i]!=fa) {
re^=+dfs(vec[u][i],u);
}
}
return re;
}
int main() {
int n;
scanf("%d",&n);
for(int i=; i<n; i++) {
int a,b;
scanf("%d%d",&a,&b);
vec[a].push_back(b);
vec[b].push_back(a);
}
printf(dfs(,)?"Alice\n":"Bob\n");
return ;
}
Game on Tree的更多相关文章
- [数据结构]——二叉树(Binary Tree)、二叉搜索树(Binary Search Tree)及其衍生算法
二叉树(Binary Tree)是最简单的树形数据结构,然而却十分精妙.其衍生出各种算法,以致于占据了数据结构的半壁江山.STL中大名顶顶的关联容器--集合(set).映射(map)便是使用二叉树实现 ...
- SAP CRM 树视图(TREE VIEW)
树视图可以用于表示数据的层次. 例如:SAP CRM中的组织结构数据可以表示为树视图. 在SAP CRM Web UI的术语当中,没有像表视图(table view)或者表单视图(form view) ...
- 无限分级和tree结构数据增删改【提供Demo下载】
无限分级 很多时候我们不确定等级关系的层级,这个时候就需要用到无限分级了. 说到无限分级,又要扯到递归调用了.(据说频繁递归是很耗性能的),在此我们需要先设计好表机构,用来存储无限分级的数据.当然,以 ...
- 2000条你应知的WPF小姿势 基础篇<45-50 Visual Tree&Logic Tree 附带两个小工具>
在正文开始之前需要介绍一个人:Sean Sexton. 来自明尼苏达双城的软件工程师.最为出色的是他维护了两个博客:2,000Things You Should Know About C# 和 2,0 ...
- Leetcode 笔记 110 - Balanced Binary Tree
题目链接:Balanced Binary Tree | LeetCode OJ Given a binary tree, determine if it is height-balanced. For ...
- Leetcode 笔记 100 - Same Tree
题目链接:Same Tree | LeetCode OJ Given two binary trees, write a function to check if they are equal or ...
- Leetcode 笔记 99 - Recover Binary Search Tree
题目链接:Recover Binary Search Tree | LeetCode OJ Two elements of a binary search tree (BST) are swapped ...
- Leetcode 笔记 98 - Validate Binary Search Tree
题目链接:Validate Binary Search Tree | LeetCode OJ Given a binary tree, determine if it is a valid binar ...
- Leetcode 笔记 101 - Symmetric Tree
题目链接:Symmetric Tree | LeetCode OJ Given a binary tree, check whether it is a mirror of itself (ie, s ...
- Tree树节点选中及取消和指定节点的隐藏
指定节点变色 指定节点隐藏 单击节点 未选中则选中该节点 已选中则取消该节点 前台: 1.HTML <ul id="listDept" name="listDept ...
随机推荐
- Lucene-如何编写Lucene程序
Lucene版本:7.1 使用Lucene的关键点 创建文档(Document),添加文件(Field),保存了原始数据信息: 把文档加入IndexWriter: 使用QueryParser.pars ...
- CentOS7.2上安装Python3.6
CentOS 7下安装Python3.6 1)安装python3.6可能使用的依赖yum -y install openssl-devel bzip2-devel expat-devel gdbm-d ...
- Python+selenium之调用JavaScript
webdriver提供了操作浏览器的前进和后退的方法,但是对于浏览器公东条并没有提供相应的操作方法.于是就需要借助JavaScript来控制浏览器的滚动条.webdriver提供了execute_sr ...
- 【LeetCode】4.Median of Two Sorted Arrays 两个有序数组中位数
题目: There are two sorted arrays nums1 and nums2 of size m and n respectively. Find the median of the ...
- python爬虫之路——构造URL集
例某网站的URL集是这样的 https://www.555zw.com/book/40/40934/10334793.html https://www.555zw.com/book/40/40934/ ...
- MySql5.7主从配置
记录 环境:ubuntu16.04,mysql5.7 主机:192.168.1.240,192.168.1.241:241为Salve 1.安装mysql sudo apt-get install m ...
- [学习笔记] AD笔记
Auto diff 深度学习基础知识,auto diff自动微分的笔记,tensorflow中的求导就是基于这个做的.多用于复杂神经网络求导.来自于一篇论文,没怎么看完,但是会算了,比较底层一点吧.. ...
- Spring归纳
Spring总结 bean标签的scope属性 scope="singleton",单例模式,默认值 scope="prototype",多例模式 注解元素 @ ...
- UML各种图总结
UML(Unified Modeling Language)是一种统一建模语言,为面向对象开发系统的产品进行说明.可视化.和编制文档的一种标准语言.下面将对UML的九种图+包图的基本概念进行介绍以及各 ...
- 1968: C/C++经典程序训练6---歌德巴赫猜想的证明
1968: C/C++经典程序训练6---歌德巴赫猜想的证明 Time Limit: 1 Sec Memory Limit: 64 MBSubmit: 1165 Solved: 499[Submi ...