原题链接在这里:https://leetcode.com/problems/snapshot-array/

题目:

Implement a SnapshotArray that supports the following interface:

  • SnapshotArray(int length) initializes an array-like data structure with the given length.  Initially, each element equals 0.
  • void set(index, val) sets the element at the given index to be equal to val.
  • int snap() takes a snapshot of the array and returns the snap_id: the total number of times we called snap() minus 1.
  • int get(index, snap_id) returns the value at the given index, at the time we took the snapshot with the given snap_id

Example 1:

Input: ["SnapshotArray","set","snap","set","get"]
[[3],[0,5],[],[0,6],[0,0]]
Output: [null,null,0,null,5]
Explanation:
SnapshotArray snapshotArr = new SnapshotArray(3); // set the length to be 3
snapshotArr.set(0,5); // Set array[0] = 5
snapshotArr.snap(); // Take a snapshot, return snap_id = 0
snapshotArr.set(0,6);
snapshotArr.get(0,0); // Get the value of array[0] with snap_id = 0, return 5

Constraints:

  • 1 <= length <= 50000
  • At most 50000 calls will be made to setsnap, and get.
  • 0 <= index < length
  • 0 <= snap_id < (the total number of times we call snap())
  • 0 <= val <= 10^9

题解:

Instead of make a copy of each snapshot, which takes a lot of memory space, we could record the state of cell when calling set method.

Have a TreeMap array, each TreeMap maintains the states of a cell.

When calling set, mark current snapshot id with the new value of this cell.

When calling get, try to get the floor entry with given snapshot id.

Time Complexity: SnapshotArray, O(length). set, O(logn). snap, O(1). get, O(logn). n is the number of total entries in arr, the number of previoius set call.

Space: O(n).

AC Java:

 class SnapshotArray {
TreeMap<Integer, Integer> [] arr;
int snapId; public SnapshotArray(int length) {
arr = new TreeMap[length];
for(int i = 0; i<length; i++){
arr[i] = new TreeMap<Integer, Integer>();
arr[i].put(0, 0);
} snapId = 0;
} public void set(int index, int val) {
arr[index].put(snapId, val);
} public int snap() {
return snapId++;
} public int get(int index, int snap_id) {
return arr[index].floorEntry(snap_id).getValue();
}
} /**
* Your SnapshotArray object will be instantiated and called as such:
* SnapshotArray obj = new SnapshotArray(length);
* obj.set(index,val);
* int param_2 = obj.snap();
* int param_3 = obj.get(index,snap_id);
*/

LeetCode 1146. Snapshot Array的更多相关文章

  1. 【leetcode】1146. Snapshot Array

    题目如下: Implement a SnapshotArray that supports the following interface: SnapshotArray(int length) ini ...

  2. 1146. Snapshot Array

    Implement a SnapshotArray that supports the following interface: SnapshotArray(int length) initializ ...

  3. LeetCode:Convert Sorted Array to Binary Search Tree,Convert Sorted List to Binary Search Tree

    LeetCode:Convert Sorted Array to Binary Search Tree Given an array where elements are sorted in asce ...

  4. Snapshot Array

    Implement a SnapshotArray that supports the following interface: SnapshotArray(int length) initializ ...

  5. [LeetCode] Shuffle an Array 数组洗牌

    Shuffle a set of numbers without duplicates. Example: // Init an array with set 1, 2, and 3. int[] n ...

  6. [LeetCode] Sort Transformed Array 变换数组排序

    Given a sorted array of integers nums and integer values a, b and c. Apply a function of the form f( ...

  7. [LeetCode] Product of Array Except Self 除本身之外的数组之积

    Given an array of n integers where n > 1, nums, return an array output such that output[i] is equ ...

  8. [LeetCode] Convert Sorted Array to Binary Search Tree 将有序数组转为二叉搜索树

    Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 这道 ...

  9. [LeetCode] Merge Sorted Array 混合插入有序数组

    Given two sorted integer arrays A and B, merge B into A as one sorted array. Note:You may assume tha ...

随机推荐

  1. Scala Http 请求调用 - scalaj-http

    Simplified Http This is a fully featured http client for Scala which wraps java.net.HttpURLConnectio ...

  2. Kubernetes 学习(八)Kubernetes 源码阅读之初级篇------源码及依赖下载

    0. 前言 阅读了一段时间 Golang 开源代码,准备正式阅读 Kubernetes 项目代码(工作机 Golang 版本为 Go 1.12) 参照 <k8s 源码阅读> 选择 1.13 ...

  3. linux 查看用户列表

    cat /etc/passwd|grep -v nologin|grep -v halt|grep -v shutdown|awk -F":" '{ print $1"| ...

  4. tomcat 下 base64图片上传超过2m的解决方案

    方案一: tomcat部署下默认post请求提交参数大小为2M左右,超过这个大小,就会传值不成功 要使post请求参数无大小限制,需要在server.xml上修改,如下: <Connector ...

  5. 【FPGA】Verilog实现交通信号灯

    大二数字电路的课程设计中,有一份日常作业使用Xilinx FPGA实现简易交通信号灯,但很可惜当时时间有限,没能最终完成.正好在这一学期选修SOPC设计课程,同样采用了Xilinx FPGA,故打算重 ...

  6. 获取Url地址中参数的3种方法【华为云技术分享】

    获取Url的代码如下:window.location.href; 方法一:原生js(假设已经获得了Url地址) var url = 'https://gitbook.cn/gitchat/geekbo ...

  7. JNDI学习总结(一):JNDI到底是什么?

    https://blog.csdn.net/wn084/article/details/80729230 分类专栏: JNDI  JNDI是 Java 命名与目录接口(Java Naming and ...

  8. 2019 苏州朗动java面试笔试题 (含面试题解析)

      本人5年开发经验.18年年底开始跑路找工作,在互联网寒冬下成功拿到阿里巴巴.今日头条.苏州朗动等公司offer,岗位是Java后端开发,因为发展原因最终选择去了苏州朗动,入职一年时间了,也成为了面 ...

  9. 简述Linux开机启动流程

    计算机开机是一个神秘的过程.我们只是按了开机键,就看到屏幕上的进度条或者一行行的输出,直到我们到达登录界面.然而,计算机开机又是个异常脆弱的过程,我们满心期望的登录界面可能并不会出现,而是一个命令行或 ...

  10. 为什么MES实施起来效果不佳?

    原因一:我国制造业存在管理基础的先天不足 我国企业与发达国家企业在管理发展上,存在较大的差别.发达制造国家经历了管理探索.发展.成熟.再提高的全过程,从管理基础的奠定到思想认识的深刻程度,都是我国所无 ...