PAT 甲级 1077 Kuchiguse (20 分)（简单，找最大相同后缀）

1077 Kuchiguse (20 分)

 

The Japanese language is notorious for its sentence ending particles. Personal preference of such particles can be considered as a reflection of the speaker's personality. Such a preference is called "Kuchiguse" and is often exaggerated artistically in Anime and Manga. For example, the artificial sentence ending particle "nyan~" is often used as a stereotype for characters with a cat-like personality:

• Itai nyan~ (It hurts, nyan~)

• Ninjin wa iyada nyan~ (I hate carrots, nyan~)

Now given a few lines spoken by the same character, can you find her Kuchiguse?

Input Specification:

Each input file contains one test case. For each case, the first line is an integer N (2). Following are N file lines of 0~256 (inclusive) characters in length, each representing a character's spoken line. The spoken lines are case sensitive.

Output Specification:

For each test case, print in one line the kuchiguse of the character, i.e., the longest common suffix of all N lines. If there is no such suffix, write nai.

Sample Input 1:

3
Itai nyan~
Ninjin wa iyadanyan~
uhhh nyan~

Sample Output 1:

nyan~

Sample Input 2:

3
Itai!
Ninjinnwaiyada T_T
T_T

Sample Output 2:

nai

题意：

题意是寻找一组字符串中最大相同后缀，并输出。如果没有：则输出‘nai’

题解：

简单题，可以reverse反转一下找最大前缀

AC代码：

#include<bits/stdc++.h>
using namespace std;
string a[];
int main(){
    int n;
    cin>>n;
    getchar();
    for(int i=;i<=n;i++){
        getline(cin,a[i]);
        reverse(a[i].begin(),a[i].end());
        //cout<<a[i]<<endl;
    }
    string s="";
    int f=;
    char c;
    for(int i=;i<;i++){
        for(int j=;j<=n;j++){
            if(i>=a[j].length()){
                f=;
                break;
            }
            if(j>=){
                if(a[j][i]!=a[][i]){
                    f=;
                    break;
                }
            }else{
                c=a[][i];
            }
        }
        if(f==){
            s+=c;
        }
    }
    reverse(s.begin(),s.end());
    if(s!="") cout<<s;
    else cout<<"nai";
    return ;
}