POJ 1703 Find them,Catch them ----种类并查集(经典)

http://blog.csdn.net/freezhanacmore/article/details/8774033?reload  这篇讲解非常好，我也是受这篇文章的启发才做出来的。

代码：

#include <iostream>
#include <cstdio>
#include <cstring>
#include <cmath>
#include <algorithm>
using namespace std;
#define N 100100

int fa[N],same[N];

void makeset(int n)
{
    for(int i=;i<=n;i++)
    {
        fa[i] = i;
        same[i] = ;
    }
}

int findset(int x)
{
    if(x != fa[x])
    {
        int tmp = fa[x];
        fa[x] = findset(fa[x]);
        same[x] = (same[x] + same[tmp])%;
    }
    return fa[x];
}

int unionset(char s,int a,int b)
{
    int x = findset(a);
    int y = findset(b);
    if(x == y)    //属于同一个集合
    {
        if(s == 'A')
        {
            if(same[a] == same[b])
            {
                return ;  //same
            }
            else
            {
                return ;  //different
            }
        }
    }
    else  //不属于同一个集合
    {
        if(s == 'A')
        {
            return ;    //unsure
        }
        else if(s == 'D')
        {
            fa[x] = y;
            same[x] = (same[a] + same[b] + )%;
        }
    }
    return ;  //要加，这是对其他情况的处理，因为此函数必须返回一个值
}

int main()
{
    int t,n,m,i;
    char ss[];
    int a,b;
    scanf("%d",&t);
    while(t--)
    {
        scanf("%d%d",&n,&m);
        makeset(n);
        for(i=;i<m;i++)
        {
            scanf("%s %d %d",ss,&a,&b);
            if(unionset(ss[],a,b) == )
            {
                cout<<"In the same gang."<<endl;
            }
            else if(unionset(ss[],a,b) == )
            {
                cout<<"In different gangs."<<endl;
            }
            else if(unionset(ss[],a,b) == )
            {
                cout<<"Not sure yet."<<endl;
            }
        }
    }
    return ;
}