C/C++ 结构体 指针 函数传递

 #include <stdio.h>
 #include <stdlib.h>

 struct student{
     int num;
     char str[];
     double dec;
 };

 void scan(struct student *stu[], int *n){
     scanf("%d", n);
     *stu = (struct student *)malloc(*n * sizeof(struct student));

     for(int i = ; i < *n; ++i){
         scanf("%d%s%lf", &(*stu)[i].num, (*stu)[i].str, &(*stu)[i].dec);
     }
 }

 void print(struct student stu[], int n){    

     printf("%d\n", n);
     for(int i = ; i < n; ++i){
         printf("%d %s %lf\n", stu[i].num, stu[i].str, stu[i].dec);
     }
 }

 int main(){
     int n;
     struct student *stu;

     scan(&stu, &n);
     print(stu, n);

     free(stu);
     return ;
 }
 /*
 3
 20 字符串0 20.02
 21 字符串1 21.12
 22 字符串2 22.22
 */