Hamburgers

http://codeforces.com/problemset/problem/371/C

time limit per test

1 second

memory limit per test

256 megabytes

input

standard input

output

standard output

Polycarpus loves hamburgers very much. He especially adores the hamburgers he makes with his own hands. Polycarpus thinks that there are only three decent ingredients to make hamburgers from: a bread, sausage and cheese. He writes down the recipe of his favorite "Le Hamburger de Polycarpus" as a string of letters 'B' (bread), 'S' (sausage) и 'C' (cheese). The ingredients in the recipe go from bottom to top, for example, recipe "ВSCBS" represents the hamburger where the ingredients go from bottom to top as bread, sausage, cheese, bread and sausage again.

Polycarpus has nb pieces of bread, ns pieces of sausage and nc pieces of cheese in the kitchen. Besides, the shop nearby has all three ingredients, the prices are pb rubles for a piece of bread, ps for a piece of sausage and pc for a piece of cheese.

Polycarpus has r rubles and he is ready to shop on them. What maximum number of hamburgers can he cook? You can assume that Polycarpus cannot break or slice any of the pieces of bread, sausage or cheese. Besides, the shop has an unlimited number of pieces of each ingredient.

Input

The first line of the input contains a non-empty string that describes the recipe of "Le Hamburger de Polycarpus". The length of the string doesn't exceed 100, the string contains only letters 'B' (uppercase English B), 'S' (uppercase English S) and 'C' (uppercase English C).

The second line contains three integers nbnsnc (1 ≤ nb, ns, nc ≤ 100) — the number of the pieces of bread, sausage and cheese on Polycarpus' kitchen. The third line contains three integers pbpspc (1 ≤ pb, ps, pc ≤ 100) — the price of one piece of bread, sausage and cheese in the shop. Finally, the fourth line contains integer r (1 ≤ r ≤ 1012) — the number of rubles Polycarpus has.

Please, do not write the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the %I64dspecifier.

Output

Print the maximum number of hamburgers Polycarpus can make. If he can't make any hamburger, print 0.

Examples
input
BBBSSC
6 4 1
1 2 3
4
output
2
input
BBC
1 10 1
1 10 1
21
output
7
input
BSC
1 1 1
1 1 3
1000000000000
output
200000000001
 #include<iostream>
#include<cmath>
#include<cstring>
#include<string>
#include<algorithm>
#include<vector>
#include<cstdio>
#include<queue>
#include<map>
#include<stack>
typedef long long ll;
using namespace std; ll a,b,c,d,e,f;
ll S,B,C;
ll num;
bool erfen(ll mid){
ll SS=mid*S-b;
if(SS<) SS=;
ll BB=mid*B-a;
if(BB<) BB=;
ll CC=mid*C-c;
if(CC<) CC=;
ll tmp=SS*e+BB*d+CC*f;
if(tmp>num) return false;
return true;
} int main(){ string str;
cin>>str; for(int i=;i<str.length();i++){
if(str[i]=='S') S++;
else if(str[i]=='B') B++;
else C++;
}
cin>>a>>b>>c>>d>>e>>f>>num;
ll L=,R=1e15,mid;
while(L<=R){
mid=L+R>>;
if(erfen(mid)){
L=mid+;
}
else{
R=mid-;
}
}
cout<<R<<endl; }

Hamburgers的更多相关文章

  1. Codeforces Round #218 (Div. 2) C. Hamburgers

    C. Hamburgers time limit per test 1 second memory limit per test 256 megabytes input standard input ...

  2. CodeForces 371C Hamburgers

    B题又耽误时间了...人太挫了.... C. Hamburgers time limit per test 1 second memory limit per test 256 megabytes i ...

  3. B - Hamburgers

    Polycarpus loves hamburgers very much. He especially adores the hamburgers he makes with his own han ...

  4. Codeforces 371C Hamburgers (二分答案)

    题目链接 Hamburgers 二分答案,贪心判断即可. #include <bits/stdc++.h> using namespace std; #define REP(i,n) fo ...

  5. C. Hamburgers

    Polycarpus loves hamburgers very much. He especially adores the hamburgers he makes with his own han ...

  6. 二分搜索 Codeforces Round #218 (Div. 2) C. Hamburgers

    题目传送门 /* 题意:一个汉堡制作由字符串得出,自己有一些原材料,还有钱可以去商店购买原材料,问最多能做几个汉堡 二分:二分汉堡个数,判断此时所花费的钱是否在规定以内 */ #include < ...

  7. H Kuangyeye and hamburgers

    链接:https://ac.nowcoder.com/acm/contest/338/H来源:牛客网 题目描述 Kuangyeye is a dalao of the ACM school team ...

  8. cf C. Hamburgers

    http://codeforces.com/contest/371/problem/C 二分枚举最大汉堡包数量就可以. #include <cstdio> #include <cst ...

  9. CodeForces 371C Hamburgers(经典)【二分答案】

    <题目链接> 题目大意: 给以一段字符串,其中只包含"BSC"这三个字符,现在有一定量免费的'B','S','C‘,然后如果想再买这三个字符,就要付出相应的价格.现在总 ...

随机推荐

  1. UMG设置组件自适应居中或靠边

    转自:http://aigo.iteye.com/blog/2297430 比如你的UI中有些组件需要居中显示,有些需要始终在右上角并且与上边框和右边框保持固定的距离等等,对于这种需要动态适应屏幕分辨 ...

  2. (转)linux查找技巧: find grep xargs

    在当前目录下所有.cpp文件中查找efg函数 find . -name "*.cpp" | xargs grep 'efg' xargs展开find获得的结果,使其作为grep的参 ...

  3. 对话框(VC_Win32)

    资源描述表中对话框定义 格式: 对话框名 DIALOG[载入特性] X,Y,Width,Height[设置选项] { 对话框控件定义; } 说明: 对话框名称: 标识对话框资源,可为一个字符串也可以为 ...

  4. Hibernate JavaBean.hbm.xml配置

    主键生成策略: hibernate中必须设置主键 <generator> 由数据库维护: identity:用于自动生成主键方式(没有自增主键的数据库不使用eg:oracle) seque ...

  5. Web 下载图片为空

    问题描述: 文件下载功能是web开发中经常使用到的功能,使用HttpServletResponse对象就可以实现文件的下载.但是下载任务正常进行,下载下来的图片却是空 问题代码: //从服务器下载一张 ...

  6. 第2课 C 到 C++ 的升级

    1.  C与C++的关系 (1)C++继承了所有的C特性,并在C的基础上提供了更多的语法和特性. (2)C++的设计目标是运行效率与开发效率的统一,它更强调的是语言的实用性. 2. C到C++ 的升级 ...

  7. 使用javascript连接mqtt协议(自动重连问题)

    因为之前是在rabbitmq的插件"RabbitMQ Web MQTT plugin "中看到使用了mqttws31.js的实例,由于对mqttws31不了解,网上下载了连接成功, ...

  8. reduce|sum

    reduce() 函数会对参数序列中元素进行累积. 函数将一个数据集合(链表,元组等)中的所有数据进行下列操作:用传给 reduce 中的函数 function(有两个参数)先对集合中的第 1.2 个 ...

  9. JQ树插件 — zTree笔记

    1.zTree作者很贴心的为使用者将不同功能的代码封装成不同的文件,方便大家尽量减少加载的代码量,如果基本全用到,则不必一个个引用,有一个文件“jquery.ztree.all.js”,包含了所有.如 ...

  10. 不规则ROI的提取

    在网上看到基于opencv3.0之前的API实现不规则ROI的提取,我自己试了一下发现opencv3.0不行,第一想法是我写的有问题,最后发现是API的改版.原理很简单. 目标:提取黑线作为ROI 原 ...