视频分析:

http://v.youku.com/v_show/id_XMTMyODkyNDA0MA==.html?from=y1.7-1.2



class Solution(object):
def isHappy(self, n):
if n==1:
return True
elif n==4:
return False
else:
return self.isHappy(self.Happy(n)) def Happy(self,n):
z=0
while n!=0:
d=n%10
z+=pow(d,2)
n=(n-n%10)//10
return z def HappySeq(self,start,cnt):
tmp=start
print (tmp,end=' ')
for x in range(1, cnt):
tmp=self.Happy(tmp)
print (tmp,end=' ')
if tmp==4 or tmp==1:
break

leetcode-happy number implemented in python的更多相关文章

  1. LeetCode Single Number I II Python

    Single Number Given an array of integers, every element appears twice except for one. Find that sing ...

  2. [LeetCode] 200. Number of Islands 岛屿的数量

    Given a 2d grid map of '1's (land) and '0's (water), count the number of islands. An island is surro ...

  3. [LeetCode] 323. Number of Connected Components in an Undirected Graph 无向图中的连通区域的个数

    Given n nodes labeled from 0 to n - 1 and a list of undirected edges (each edge is a pair of nodes), ...

  4. C#版 - Leetcode 191. Number of 1 Bits-题解

    版权声明: 本文为博主Bravo Yeung(知乎UserName同名)的原创文章,欲转载请先私信获博主允许,转载时请附上网址 http://blog.csdn.net/lzuacm. C#版 - L ...

  5. [leetcode]200. Number of Islands岛屿个数

    Given a 2d grid map of '1's (land) and '0's (water), count the number of islands. An island is surro ...

  6. [leetcode]694. Number of Distinct Islands你究竟有几个异小岛?

    Given a non-empty 2D array grid of 0's and 1's, an island is a group of 1's (representing land) conn ...

  7. [LeetCode] 711. Number of Distinct Islands II_hard tag: DFS

    Given a non-empty 2D array grid of 0's and 1's, an island is a group of 1's (representing land) conn ...

  8. [LeetCode] 694. Number of Distinct Islands

    Given a non-empty 2D array grid of 0's and 1's, an island is a group of 1's (representing land) conn ...

  9. 力不从心 Leetcode(ugly number heap) 263, 264,313

    Leetcode ugly number set (3 now) new ugly number is generated by multiplying a prime with previous g ...

随机推荐

  1. IO/序列化/JSON

    一.读写文件 1.open:打开文件 open(path, mode, encoding='xxx', errors='ignore') mode取值:rU 或 Ua 以读方式打开, 同时提供通用换行 ...

  2. 我的Android进阶之旅------>Android字符串资源中的单引號问题error: Apostrophe not preceded by 的解决的方法

    刚刚在string字符串资源文件里,写了一个单引號.报错了,错误代码例如以下 error: Apostrophe not preceded by \ (in OuyangPeng's blog ) 资 ...

  3. Firefly 流程架构

    print '----startmaster------' 1print '----appmain------' 2 print '----netserver------' 3 print '---- ...

  4. 【Firefly API文档】—— Package Distributed

    http://bbs.gameres.com/forum.php?mod=viewthread&tid=219654 package distributed 这个包中主要封装了各个服务进程间进 ...

  5. ES2017 keys,values,entries使用

    let {keys, values, entries} = Object; let obj = { a: 1, b: 2, c: 3 }; for (let key of keys(obj)) { c ...

  6. Linux下SVN部署/安全及权限配置,实现web同步更新

    转自:http://www.cnblogs.com/me115/archive/2013/04/07/3002058.html 本文包含以下内容: SVN服务器安装 SVN权限管理 SVN使用SASL ...

  7. C++14系列(1):Linux下C++14开发环境配置

    g++安装 參考地址: http://sysads.co.uk/2014/07/install-gcc-gnu-4-9-1-on-ubuntu-14-04/ 当前Ubuntu的LTS版本号为14.04 ...

  8. hiberbnate 缓存策略概述

    1. 首先了解什么是缓存 这里说的缓存并不是指计算机的内存或者CPU的一二级缓存. 缓存是指为了降低应用程序对物理数据源访问的频次,从而提高应用程序的运行性能的一种策略.即对物理数据源的复制,存在于内 ...

  9. canvas学习笔记(上篇)-- canvas入门教程 -- canvas标签/方块/描边/路径/圆形/曲线

    [上篇] -- 建议学习时间4小时  课程共(上中下)三篇 此笔记是我初次接触canvas的时候的学习笔记,这次特意整理为博客供大家入门学习,几乎涵盖了canvas所有的基础知识,并且有众多练习案例, ...

  10. unity, Awake的调用时机

    Awake是在setActive(true)时才会被调用,不过如果再setActive(false)然后重新setActive(true)的话,Awake就不会再被调用了,也就是说Awake能保证仅被 ...