codeforces B. Pasha and String

Pasha got a very beautiful string s for his birthday, the string consists of lowercase Latin letters. The letters in the string are numbered from 1 to |s| from
left to right, where |s| is the length of the given string.

Pasha didn't like his present very much so he decided to change it. After his birthday Pasha spent m days performing the following transformations on his
string — each day he chose integer ai and reversed a
piece of string (a segment) from position ai to
position|s| - ai + 1.
It is guaranteed that 2·ai ≤ |s|.

You face the following task: determine what Pasha's string will look like after m days.

Input

The first line of the input contains Pasha's string s of length from 2 to 2·105 characters,
consisting of lowercase Latin letters.

The second line contains a single integer m (1 ≤ m ≤ 105) — 
the number of days when Pasha changed his string.

The third line contains m space-separated elements ai (1 ≤ ai; 2·ai ≤ |s|) — the
position from which Pasha started transforming the string on the i-th day.

Output

In the first line of the output print what Pasha's string s will look like after m days.

Sample test(s)

input

abcdef
1
2

output

aedcbf

input

vwxyz
2
2 2

output

vwxyz

input

abcdef
3
1 2 3

output

fbdcea

这题和涂气球那道类似，用了叠加的思想。

#include<stdio.h>
#include<string.h>
int d[200005];
char str[200005];
int main()
{
    int n,m,i,j,a,len,s;
    char c;
    while(scanf("%s",str+1)!=EOF)
    {
        len=strlen(str+1);
        scanf("%d",&n);
        for(i=1;i<=n;i++)
        {
            scanf("%d",&a);
            d[a]++;
        }
        s=0;
        for(i=1;i<=len/2;i++)
        {
            s=s+d[i];
            d[i]=s;
        }
        for(i=1;i<=len/2;i++)
        {
            if(d[i]%2==1)
            {
                c=str[i];
                str[i]=str[len+1-i];
                str[len+1-i]=c;
            }
        }
        //printf("%d %d %d",d[1],d[2],d[3]);
        for(i=1;i<=len;i++)
        {
            printf("%c",str[i]);
        }
        printf("\n");

    }
}