hdu 5058 So easy
题目连接
http://acm.hdu.edu.cn/showproblem.php?pid=5058
So easy
Description
Small W gets two files. There are n integers in each file. Small W wants to know whether these two files are same. So he invites you to write a program to check whether these two files are same. Small W thinks that two files are same when they have the same integer set.
For example file A contains (5,3,7,7),and file B contains (7,5,3,3). They have the same integer set (3,5,7), so they are same.
Another sample file C contains(2,5,2,5), and file D contains (2,5,2,3).
The integer set of C is (2,5),but the integer set of D is (2,3,5),so they are not same.
Now you are expected to write a program to compare two files with size of n.
Input
Multi test cases (about 100). Each case contain three lines. The first line contains one integer n represents the size of file. The second line contains n integers
$a_1, a_2, a_3, \ldots, a_n$ - represents the content of the first file. The third line contains n integers $b_1, b_2, b_3, \ldots, b_n$ - represents the content of the second file.
Process to the end of file.
$1 \leq n \leq 100$
$1 \leq a_i , b_i \leq 1000000000$
Output
For each case, output "YES" (without quote) if these two files are same, otherwise output "NO" (without quote).
Sample Input
3
1 1 2
1 2 2
4
5 3 7 7
7 5 3 3
4
2 5 2 3
2 5 2 5
3
1 2 3
1 2 4
Sample Output
刷些水题打发时间。。
#include<cstdio>
#include<set>
using std::set;
set<int> A, B;
int main() {
int n, v;
while (~scanf("%d", &n)) {
for (int i = ; i < n << ; i++) {
scanf("%d", &v);
if (i < n) A.insert(v);
else B.insert(v);
}
if (A == B) puts("YES");
else puts("NO");
A.clear(), B.clear();
}
return ;
}
hdu 5058 So easy的更多相关文章
- HDU 5572 An Easy Physics Problem (计算几何+对称点模板)
HDU 5572 An Easy Physics Problem (计算几何) 题目链接http://acm.hdu.edu.cn/showproblem.php?pid=5572 Descripti ...
- BestCoder12 1001.So easy(hdu 5058) 解题报告
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5058 (格式有点问题,为了方便阅读---整个复制下来吧) 题目意思:给出两个长度都为 n 的集合你,问 ...
- hdu 5475 An easy problem(暴力 || 线段树区间单点更新)
http://acm.hdu.edu.cn/showproblem.php?pid=5475 An easy problem Time Limit: 8000/5000 MS (Java/Others ...
- HDU 5475 An easy problem 线段树
An easy problem Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pi ...
- 数据结构(主席树):HDU 4729 An Easy Problem for Elfness
An Easy Problem for Elfness Time Limit: 5000/2500 MS (Java/Others) Memory Limit: 65535/65535 K (J ...
- HDU 4565 So Easy(矩阵解公式)
So Easy [题目链接]So Easy [题目类型]矩阵解公式 &题解: 感觉这种类型的题都是一个套路,这题和hdu 2256就几乎是一样的. 所以最后2Xn就是答案 [时间复杂度]\(O ...
- hdu 5058 set应用
http://acm.hdu.edu.cn/showproblem.php?pid=5058 set应用 水题 #include <cstdio> #include <cstdlib ...
- HDU 2132 An easy problem
http://acm.hdu.edu.cn/showproblem.php?pid=2132 Problem Description We once did a lot of recursional ...
- HDU 5650 so easy 数学
so easy 题目连接: http://acm.hdu.edu.cn/showproblem.php?pid=5650 Description Given an array with n integ ...
随机推荐
- Openstack-Mitaka Ceilometer 中使用 SNMP 监控真实物理机
Ceilometer 是 Openstack 的监控管理计费模块,我所用的版本为 Mitaka 版本.在 Ceilometer 中,可以使用 SNMP 监控服务器的实时硬件资源信息. 系统环境为 Ce ...
- Object-oriented features
Python is an object-oriented programing language, which means that it provides features that support ...
- $(function(){})与 (function(){})() (function($){})() 的区别
1. $(function(){ }) 或 jQuery(function(){ }) 此函数也可以写成 jQuery(function(){ }), 用于存放操作DOM对象的代码,执行其中代码时DO ...
- mysql中explain看性能
select distinct col_name from table where a=X and b=Y and date(time)='xx-xx-xx';执行时间 27.9772 秒 expla ...
- epoll在socket通信中的应用
当服务器需要服务多个客户时,需要使用并发通信,实现并发通信有以下几种方法: 1.在服务器中fork子进程来为每个客户服务 具体可参考http://www.cnblogs.com/ggjucheng/ ...
- jar包程序 读取properties文件
String proFilePath = System.getProperty("user.dir") + "\\Mysettings.properties"; ...
- new 、operator new 和 placement new
一.原生operator new 我们先从原生operator new开始.考虑如下代码,它用来分配5个int型的空间并返回指向他们的指针[1]: int* v = static_cast<in ...
- iOS 如何根据经纬度来定位位置
/** * 初始化一个经纬度结构体 */ CLLocationCoordinate2D center = {[latitudeTF.text floatValue],[longitudeTF.tex ...
- curl返回常见错误码
转自:http://blog.csdn.net/cwj649956781/article/details/8086337 CURLE_OK() 所有罚款.继续像往常一样. CURLE_UNSUPPOR ...
- Oracle笔记 十三、PL/SQL面向对象之package
--将方法和过程用包定义 create or replace package pkg_emp as --输入员工编号查询出员工信息 procedure pro_findInfo( in_empno e ...