Find the Clones（字典树）

链接：http://poj.org/problem?id=2945

Description

Doubleville, a small town in Texas, was attacked by the aliens. They have abducted some of the residents and taken them to the a spaceship orbiting around earth. After some (quite unpleasant) human experiments, the aliens cloned
the victims, and released multiple copies of them back in Doubleville. So now it might happen that there are 6 identical person named Hugh F. Bumblebee: the original person and its 5 copies. The Federal Bureau of Unauthorized Cloning (FBUC) charged you with
the task of determining how many copies were made from each person. To help you in your task, FBUC have collected a DNA sample from each person. All copies of the same person have the same DNA sequence, and different people have different sequences (we know
that there are no identical twins in the town, this is not an issue).

Input

The input contains several blocks of test cases. Each case begins with a line containing two integers: the number 1 ≤ n ≤ 20000 people, and the length 1 ≤ m ≤ 20 of the DNA sequences. The next n lines contain the DNA sequences:
each line contains a sequence of m characters, where each character is either `A', `C', `G' or `T'.




The input is terminated by a block with n = m = 0 .

Output

For each test case, you have to output n lines, each line containing a single integer. The first line contains the number of different people that were not copied. The second line contains the number of people that were copied
only once (i.e., there are two identical copies for each such person.) The third line contains the number of people that are present in three identical copies, and so on: the i -th line contains the number of persons that are present in i identical copies.
For example, if there are 11 samples, one of them is from John Smith, and all the others are from copies of Joe Foobar, then you have to print `1' in the first andthe tenth lines, and `0' in all the other lines.

Sample Input

9 6
AAAAAA
ACACAC
GTTTTG
ACACAC
GTTTTG
ACACAC
ACACAC
TCCCCC
TCCCCC
0 0

Sample Output

1
2
0
1
0
0
0
0
0

Hint

Huge input file, 'scanf' recommended to avoid TLE.

#include <iostream>
#include <stdio.h>
#include <string.h>
#include <cstdio>
#include <algorithm>
using namespace std;
#define rd(x,y) scanf("%d%d",&x,&y)
int n,m;
struct Trie
{
    int cnt;//有多少单词经过该节点
    Trie *next[4];
    Trie()
    {
        cnt=0;
        for(int i=0;i<4;i++)
            next[i]=NULL;
    }
};

int coun[20005];
void create(char *s,Trie * root)//将字符串s建立在trie树中
{
    Trie *p=root;
    int len=strlen(s);
    for(int i=0;i<len;i++)
    {
        int id = -1;
        switch(s[i]){
            case 'A' : id=0;break;
            case 'G' : id=1;break;
            case 'C' : id=2;break;
            case 'T' : id=3;break;
        }
       // cout<<id<<' ';
        if(p->next[id]==NULL)
        {
            p->next[id]=new Trie;
            p->next[id]->cnt++;
        }
        else
            p->next[id]->cnt++;
        p=p->next[id];
    }
}

void searchTrie(Trie *r,int temp)//查找字符串s是多少单词的前缀。

{
    Trie *p=r;
    for(int i=0; i<4; i++)
        if(p->next[i]!=NULL)
            searchTrie(p->next[i],temp+1);
    if(temp == m)
        coun[(p->cnt)-1]++;
}

void release(Trie *r)//释放空间（该题中可以不用释放，也能过）
{
    if(r==NULL)  return  ;
    for(int i=0; i<4; i++)
    {
        if(r->next[i]!=NULL)
            release(r->next[i]);
    }
   // if(r!=&root)
      free(r);
}
int main()
{
    while(~rd(n,m)&&n!=0&&m!=0)
    {
        Trie root;
        memset(coun,0,sizeof(coun));
        char s[25];
        getchar();
        for(int i = 0;i < n ;i++)
        {
             gets(s);
            create(s,&root);//根据给定的字符串建立字典树
        }
        searchTrie(&root,0);

        for(int i = 0 ;i<n;i++)
            printf("%d\n",coun[i]);
        release(&root);
       // root.next[0]=root.next[1]=root.next[2]=root.next[3]=NULL;
    }
    return 0;
}