Codeforces E. Weakness and Poorness(三分最大子列和)
题目描述:
E. Weakness and Poorness
time limit per test
2 seconds
memory limit per test
256 megabytes
input
standard input
output
standard output
You are given a sequence of n integers a1, a2, ..., a**n.
Determine a real number x such that the weakness of the sequence a1 - x, a2 - x, ..., a**n - x is as small as possible.
The weakness of a sequence is defined as the maximum value of the poorness over all segments (contiguous subsequences) of a sequence.
The poorness of a segment is defined as the absolute value of sum of the elements of segment.
Input
The first line contains one integer n (1 ≤ n ≤ 200 000), the length of a sequence.
The second line contains n integers a1, a2, ..., a**n (|a**i| ≤ 10 000).
Output
Output a real number denoting the minimum possible weakness of a1 - x, a2 - x, ..., a**n - x. Your answer will be considered correct if its relative or absolute error doesn't exceed 10 - 6.
Examples
Input
Copy
31 2 3
Output
Copy
1.000000000000000
Input
Copy
41 2 3 4
Output
Copy
2.000000000000000
Input
Copy
101 10 2 9 3 8 4 7 5 6
Output
Copy
4.500000000000000
Note
For the first case, the optimal value of x is 2 so the sequence becomes - 1, 0, 1 and the max poorness occurs at the segment "-1" or segment "1". The poorness value (answer) equals to 1 in this case.
For the second sample the optimal value of x is 2.5 so the sequence becomes - 1.5, - 0.5, 0.5, 1.5 and the max poorness occurs on segment "-1.5 -0.5" or "0.5 1.5". The poorness value (answer) equals to 2 in this case.
思路:
这道题是要求一个数列减去一个数$x$后的子列和的绝对值最大(poorness)的情况下的可能的最小值(weakness)。(有点绕哈
Codeforces E. Weakness and Poorness(三分最大子列和)的更多相关文章
- [codeforces] 578C Weakness and Poorness || 三分
原题 题目定义了两个变量: poorness表示一个区间内和的绝对值. weakness表示一个所有区间最大的poornesss 题目要求你求一个x使得 a1 − x, a2 − x, ..., an ...
- codeforces 578c - weekness and poorness - 三分
2017-08-27 17:24:07 writer:pprp 题意简述: • Codeforces 578C Weakness and poorness• 给定一个序列A• 一个区间的poornes ...
- Codeforces Round #320 (Div. 1) [Bayan Thanks-Round] C. Weakness and Poorness 三分 dp
C. Weakness and Poorness Time Limit: 1 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/5 ...
- Codeforces Round #320 (Div. 2) [Bayan Thanks-Round] E. Weakness and Poorness 三分
E. Weakness and Poorness time limit per test 2 seconds memory limit per test 256 megabytes input sta ...
- codeforces 578c//Weakness and Poorness// Codeforces Round #320 (Div. 1)
题意:一个数组arr,一个数字x,要使arr-x的最大子段最小,问该最小值. 三分x,复杂度logn,内层是最大子段的模板,只能用n复杂度的.因为是绝对值最大,正负各求一次,取大的.精度卡得不得了,要 ...
- cf578c Weakness and Poorness 三分
其实三分就是一个求单峰函数的最值的东西,用法比较统一.这个题就是观察发现不美好值是一个单峰函数,然后枚举t进行三分就行了. 题干: 给定一个长度为n的数组ai,求一个实数x,使得序列a1-x,a2-x ...
- Codeforces 578.C Weakness and Poorness
C. Weakness and Poorness time limit per test 2 seconds memory limit per test 256 megabytes input sta ...
- 【CodeForces】578 C. Weakness and Poorness
[题目]C. Weakness and Poorness [题意]给定含n个整数的序列ai,定义新序列为ai-x,要使新序列的最大子段和绝对值最小,求实数x.n<=2*10^5. [算法]二分| ...
- PAT复杂度_最大子列和问题、最大子列和变种
01-复杂度1. 最大子列和问题 给定K个整数组成的序列{ N1, N2, ..., NK },“连续子列”被定义为{ Ni, Ni+1, ..., Nj },其中 1 <= i <= j ...
随机推荐
- 使用termux在安卓手机上搭建python开发环境
下载安装termux应用. 应用链接如下:https://download.csdn.net/upload/11342944设置-应用-termux赋予存储权限 cd mkdir .termux vi ...
- UE4 Animation]IK Related
转自:https://dawnarc.com/2018/05/ue4animationik-related/ Examples 工程1 在油管上看到一个UE4 IK动画的demo工程示例 该示例作者的 ...
- VS2015 控制台cl编译器全局环境变量配置
Visual C++的cl.exe编译器是微软推出的编译器 为了可以在CMD里使用cl.exe手工执行编译操作 设置环境变量 PATH C:\Program Files (x86)\Microsoft ...
- chrome表单自动填充如何取消
autocomplete="new-password"
- 图像变化之Laplacian()函数 and Schaar()滤波及综合例子
先来 Laplacian()函数 #include<math.h> #include<opencv2/opencv.hpp> #include<string.h> ...
- 软件测试人员必备的Python知识图库
UI自动化测试(Python+Selenium等) 接口测试(Python requests等) 性能测试(Python Locust等) 安全性测试(Python Scapy等) 兼容性测试(Pyt ...
- redis 缓存穿透、击穿、雪崩
缓存穿透: 大量查询 redis 中不存在的key(用随救数进行查询),导致每次都会去查询数据库,造成数据库压力过大(甚至宕机). 解决办法: 1.对我们的 api 接口 进行限流处理.用户授权.黑名 ...
- kubernetes-dashboard登录出现forbidden 403
登录k8s dashboard https://xxxxx:6443/api/v1/namespaces/kube-system/services/https:kubernetes-dashboard ...
- 如何定位 golang 进程 hang 死的 bug
之前在 golang 群里有人问过为什么程序会莫名其妙的 hang 死然后不再响应任何请求.单核 cpu 打满. 这个特征和我们公司的某个系统曾经遇到的情况很相似,内部经过了很长时间的定位分析总结,期 ...
- 洛谷【P1048 采药】题解
题目链接 分析:典型的01背包问题,设dp[i][j]为空间(也就是题面中的时间)是j的背包在装前i个物品(草药)所得的最大价值,v[i]为第i个物品的重量(采药的时间),w[i]为第i个物品(草药) ...