Problem H
The Land of Justice
Input: standard input
Output: standard output
Time Limit: 4 seconds

In the Land of Justice theselling price of everything is fixed all over the country. Nobody can buy a thingand sell it in double price. But, that created problems for the businessmen.They left their business and went to the production. So, after some dayseverybody was in production and nobody in business. And the people didn’t gettheir necessary things though the country was self-sufficient in every sector.

The government became very muchanxious. But, they were intelligent enough to call the mathematicians.

The mathematicians gave asolution.  They suggested setting thesurface area of an object as its selling-unit instead of its volume. Actuallythe clever mathematicians were very much interested to establish their ownbusiness.

Now, the government asks theprogrammers to build the software that would calculate the profit things.

Here your job is to calculate thebusiness profit for a solid sphere. A businessman buys a complete sphere and tomaximize his profit he divides it in n equal parts. All cut should gothrough the axis of the sphere. And every part should look like the picturebelow:

Input

You are given a sequence ofintegers N (0 < N < 231), indicating the numbers of parts ofthe sphere. The input file is terminated with a negative number. This numbershould not be processed.

 

Output

Calculate the profit over the sold pieces. The resultshould be in percentage and rounded to the nearest integer.

Sample input

2

2

-1

Sampleoutput

50%

50%

题意: 我简单的说, 把球切拿去切, (按图中所示切 不要乱切哦)

然后问, 表面积比原先的表面积多出了百分之多少?

做法: 看别人的题解, 发现公式是: (n*25)%

除了n = 1时, 答案是 0%

注意点: n * 25 会超, 用long long

AC代码

#include<stdio.h>

long long n;
char ch = '%';
int main() {
while(scanf("%lld", &n) != EOF) {
if(n < 0)
break;
if(n == 1)
printf("0%c", ch);
else
printf("%lld%c", 25 * n, ch);
printf("\n");
}
return 0;
}

UVA 10499 (13.08.06)的更多相关文章

  1. UVA 253 (13.08.06)

     Cube painting  We have a machine for painting cubes. It is supplied withthree different colors: blu ...

  2. UVA 573 (13.08.06)

     The Snail  A snail is at the bottom of a 6-foot well and wants to climb to the top.The snail can cl ...

  3. UVA 10025 (13.08.06)

     The ? 1 ? 2 ? ... ? n = k problem  Theproblem Given the following formula, one can set operators '+ ...

  4. UVA 10790 (13.08.06)

     How Many Points of Intersection?  We have two rows. There are a dots on the toprow andb dots on the ...

  5. UVA 10194 (13.08.05)

    :W Problem A: Football (aka Soccer)  The Problem Football the most popular sport in the world (ameri ...

  6. UVA 465 (13.08.02)

     Overflow  Write a program that reads an expression consisting of twonon-negative integer and an ope ...

  7. UVA 10494 (13.08.02)

    点此连接到UVA10494 思路: 采取一种, 边取余边取整的方法, 让这题变的简单许多~ AC代码: #include<stdio.h> #include<string.h> ...

  8. UVA 424 (13.08.02)

     Integer Inquiry  One of the first users of BIT's new supercomputer was Chip Diller. Heextended his ...

  9. UVA 10106 (13.08.02)

     Product  The Problem The problem is to multiply two integers X, Y. (0<=X,Y<10250) The Input T ...

随机推荐

  1. Windows 环境搭建cocos2dx 3.x Eclipse的环境

    安装JDK,该步骤网上太多,不再赘述; 安装NDK,同样,直接去Google找到最新的NDK,下载解压到某个盘符根目录即可; 简便起见,使用ADT Bundle,而不要去使用Eclipse的原生包,可 ...

  2. dzzoffice教程、文档、开发手册等内容地址

    dzzoffice教程.文档.开发手册等内容全部都存放在DzzOffice开发者社区的文集中.搜索引擎收录不到DzzOffice中的应用内容,这里将文集地址提供在这里. 地址:http://dev.d ...

  3. java中子类与基类变量间的赋值

    Java中子类与基类变量间的赋值 子类对象可以直接赋给基类变量. 基类对象要赋给子类对象变量,必须执行类型转换, 其语法是: 子类对象变量=(子类名)基类对象名; 也不能乱转换.如果类型转换失败Jav ...

  4. 隐藏apache版本号 PHP版本号

    httpd-default.conf ServerTokens Prod ServerSignature Off php.ini expose_php Off 重启服务器

  5. webstorm+nodejs+JetBrains IDE Support+chrome打造前端开发神器

    #webstorm+nodejs+JetBrains IDE Support+chrome打造前端开发神器 -- 工欲善其事 必先利其器 ##各工具介绍 `webstorm`是**JetBrains* ...

  6. WS之cxf与spring整合1

    1.在web.xml中加入CXFServlet: <!-- 下面表示所有来自/cxfservice/*的请求,都交给 CXFServlet来处理 .--> <servlet>  ...

  7. asp web api 怎么使用put和delete。

    Method Overriding RESTful services allow the clients to act on the resources through methods such as ...

  8. 服务器多块磁盘 ,同时磁盘类型混合(SSD+STAT+SAS)

    服务器多块磁盘 ,同时磁盘类型混合(SSD+STAT+SAS)

  9. 统一入口的Ajax验证

    此前一直没有写博客的习惯,只是将一些心得和体会大致的用笔写在一个本子上,今天刚刚开通博客,就随便写一点吧! 关于服务端验证,大致可以分为登陆验证与功能权限验证,而以前端请求方式来区分的话,又可分为 1 ...

  10. InternetOpenA

    [ilink32 Error] Error: Unresolved external 'InternetOpenA' referenced from  ..\WIN32\DEBUG\NATIVEXML ...