题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5233

题意:有n颗树,第 i 棵树的高度为 h[i],树上有鸟,现在这个人要打m次枪,每次打的高度是 q[i], 求每次

打枪能打下鸟的编号,否则输出-1 ;

STL中的map和vector:

#include <iostream>
#include <stdio.h>
#include <string.h>
#include <algorithm>
#include <map> using namespace std; #define met(a, b) memset(a, b, sizeof(a))
#define INF 0x3f3f3f3f
#define N 100010 int dir[][] = { {,}, {-,}, {,}, {,-}, {,}, {,-}, {-,}, {-,-} }; int n, m, h[N], q[N]; map<int, vector<int> > mp; int main()
{
while(scanf("%d %d", &n, &m) != EOF)
{
mp.clear(); for(int i=; i<=n; i++) scanf("%d", &h[i]); for(int i=n; i>=; i--) mp[h[i]].push_back(i); for(int i=; i<=m; i++)
{
scanf("%d", &q[i]); if(mp[q[i]].size()>=)
{
printf("%d\n", mp[q[i]].back()); mp[q[i]].pop_back();
}
else printf("-1\n");
}
}
return ;
}

二分:

#include <iostream>
#include <stdio.h>
#include <string.h>
#include <algorithm>
#include <map> using namespace std; #define met(a, b) memset(a, b, sizeof(a))
#define INF 0x3f3f3f3f
#define N 100010 int dir[][] = { {,}, {-,}, {,}, {,-}, {,}, {,-}, {-,}, {-,-} }; struct node
{
int num, Id;
}h[N]; int n, m, q[N], vis[N]; int cmp(node a, node b)
{
if(a.num!=b.num)
return a.num < b.num;
return a.Id < b.Id;
} int BeSearch(int L, int R, int num)
{
int ans = -; while(L <= R)
{
int Mid = (L+R)/; if(num == h[Mid].num)
{
if(!vis[Mid])
{
ans = Mid; R = Mid - ;///先输出最左边的;
}
else
L = Mid + ;
}
else if(h[Mid].num > num) R = Mid - ;
else L = Mid + ;
}
if(ans != -)
{
vis[ans] = ;
return h[ans].Id;
}
return -;
} int main()
{
while(scanf("%d %d", &n, &m) != EOF)
{
met(vis, );
met(h, );
met(q, ); for(int i=; i<n; i++)
{
scanf("%d", &h[i].num); h[i].Id = i+;
} sort(h, h+n, cmp); for(int i=; i<=m; i++)
{
scanf("%d", &q[i]); int pos = BeSearch(, n, q[i]); printf("%d\n", pos);
}
}
return ;
}

Gunner II--hdu5233(map&vector/二分)的更多相关文章

  1. hdoj--5233--Gunner II(map+queue&&二分)

     Gunner II Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Tot ...

  2. Gunner II(二分,map,数字转化)

    Gunner II Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total ...

  3. uva--11991 - Easy Problem from Rujia Liu?(sort+二分 map+vector vector)

    11991 - Easy Problem from Rujia Liu? Though Rujia Liu usually sets hard problems for contests (for e ...

  4. 二分查找 BestCoder Round #42 1002 Gunner II

    题目传送门 /* 题意:查询x的id,每次前排的树倒下 使用lower_bound ()查找高度,f[i]记录第一棵高度为x树的位置,查询后+1(因为有序) */ #include <cstdi ...

  5. HDU 3081 Marriage Match II (网络流,最大流,二分,并查集)

    HDU 3081 Marriage Match II (网络流,最大流,二分,并查集) Description Presumably, you all have known the question ...

  6. 2018.09.26 洛谷P2464 [SDOI2008]郁闷的小J(map+vector)

    传送门 本来出题人出出来想考数据结构的. 但是我们拥有map+vector/set这样优秀的STL,因此直接用map离散化,vector存下标在里面二分找答案就行了. 代码: #include< ...

  7. UVa 11991:Easy Problem from Rujia Liu?(STL练习,map+vector)

    Easy Problem from Rujia Liu? Though Rujia Liu usually sets hard problems for contests (for example, ...

  8. map,vector 等容器内容的循环删除问题(C++)

    map,vector 等容器内容的循环删除问题(C++) map,vector等容器的循环删除不能用普通的方法删除: for(auto p=list.begin();p!=list.end();p++ ...

  9. hdu5233 Gunner II

    Problem Description Long long ago, there was a gunner whose name is Jack. He likes to go hunting ver ...

随机推荐

  1. python右键不显示IDLE

    打开注册表,在HKEY_CLASSES_ROOT\SystemFileAssociations中添加.py\shell\Edit with IDLE\command(右键 ->‘新建’ -> ...

  2. jquery checkbox选中

    楼主写的在1.6之前是没有问题的,jquery 1.6后就要这样写了,<input type='checkbox' id='cb'/> <script> //获取是否选中 va ...

  3. linux 短信收发

    #include <termios.h>#include <stdio.h>#include <stdlib.h>#include <unistd.h> ...

  4. PHP——自定义函数

    <?php //定义有默认值的函数 function Main3($f=5,$g=6) { echo $f*$g; } Main3(2,3); echo "<br />&q ...

  5. golang Time to String

    golang Time to String allenhaozi · 2016-09-02 09:00:00 · 2447 次点击 · 预计阅读时间 1 分钟 · 19分钟之前 开始浏览 这是一个创建 ...

  6. jQuery替换内容

    <html> <head> <meta http-equiv="Content-Type" content="text/html; char ...

  7. Thymeleaf 3.0.9.RELEASE is the current stable version. It requires Java SE 6 or newer.

    Thymeleaf 3.0.9.RELEASE is the current stable version. It requires Java SE 6 or newer. Release date: ...

  8. Spring Cloud对于中小型互联网公司来说是一种福音

    Spring Cloud对于中小型互联网公司来说是一种福音,因为这类公司往往没有实力或者没有足够的资金投入去开发自己的分布式系统基础设施,使用Spring Cloud一站式解决方案能在从容应对业务发展 ...

  9. hdu 1233 还是畅通project

    本题链接:点击打开链接 本题大意: 有n个村庄,n*(n-1)/2条路,输入每条路所连接是哪两个村庄及长度,求使全部村庄均连通(并不是都两两连通) 所铺公路的最短路程. 解题思路: 使用并查集基础及K ...

  10. mysql的优化基础知识

    1.查看各种SQL执行的频率 mysql> show status like 'Com_select';--Com_insert,Com_delete,connections(试图连接mysql ...