关于python urlopen 一个类似radio流的timeout方法

终极解决方法来啦！看代码感受：

import requests
import eventlet
import time

eventlet.monkey_patch() 

try:
    with eventlet.Timeout(5):
        response = requests.get("http://t.co/iXJWRrfl5n", verify=False) #http://t.co/iXJWRrfl5n is a radio stream!!
        #response = requests.get("http://docs.python-requests.org/en/master/user/advanced/", verify=False)
        print response.text
except:
    print 'error'

print response.text
while True:
    time.sleep(1)
    print 'sec'

from urllib2 import urlopen
from threading import Timer
url = "http://t.co/iXJWRrfl5n"
fh = urlopen(url)
t = Timer(5.0, fh.close)
t.start()
data = fh.read()
t.cancel()

5s以后会把read（）方法给掐了

另见

http://stackoverflow.com/questions/2281850/timeout-function-if-it-takes-too-long-to-finish

with timeout(seconds=3):
    sleep(4)

class timeout:
    def __init__(self, seconds=1, error_message='Timeout'):
        self.seconds = seconds
        self.error_message = error_message
    def handle_timeout(self, signum, frame):
        raise TimeoutError(self.error_message)
    def __enter__(self):
        signal.signal(signal.SIGALRM, self.handle_timeout)
        signal.alarm(self.seconds)
    def __exit__(self, type, value, traceback):
        signal.alarm(0)

import signal

def signal_handler(signum, frame):
    raise Exception("Timed out!")

signal.signal(signal.SIGALRM, signal_handler)
signal.alarm(10)   # Ten seconds
try:
    long_function_call()
except Exception, msg:
    print "Timed out!"

signal.alarm(0)   # cancel alarm when function return in time

#other code...

 http://stackoverflow.com/questions/21965484/timeout-for-python-requests-get-entire-response

import requests
import eventlet
eventlet.monkey_patch()

with eventlet.Timeout(10):
    requests.get("http://ipv4.download.thinkbroadband.com/1GB.zip", verify=False)