#查找列表中元素，移除每个元素的空格，并查找以 a或A开头 并且以 c 结尾的所有元素

 #!/usr/bin/env python
 #查找列表中元素，移除每个元素的空格，并查找以 a或A开头 并且以 c 结尾的所有元素。
 #    li = ["alec", " aric", "Alex", "Tony", "rain"]
 #    tu = ("alec", " aric", "Alex", "Tony", "rain") 
 #    dic = {'k1': "alex", 'k2': ' aric',  "k3": "Alex  ", "k4": "Tony"}

 li = ["   alex ","aric","Alex","Tony","rain"]
 tu = ("alex   ","aric ","Alex ","  Tony"," rain")
 dic = {'k1':"alex",'k2':" aric   ",'k3':"Alex",'k4':"Tony"}
 for i,j in enumerate(li,0) :
     j = j.strip()
     li[i] = j
     if j.endswith('c') and (j.startswith('a') or j.startswith('A')):
         print(j)
 print(li)
 print("-------------------")

 for j in tu :
     print(j)
     j = j.strip()
     print(j)
     if j.endswith('c') and (j.startswith('a') or j.startswith('A')):
         print(j)
 print(tu)
 print("-------------------")

 for i,j in enumerate(dic,0) :
     print(j)
     dic[j] = dic[j].strip()
     if dic[j].endswith('c') and (dic[j].startswith('a') or dic[j].startswith('A')):
         print(dic[j])
 print(dic)

 for i in dic.values() :
     i = i.strip()
     if i.endswith('c') and (i.startswith('a') or i.startswith('A')):
         print(dic[j])
 print(dic)