leetcode@ [273] Integer to English Words (String & Math)
https://leetcode.com/problems/integer-to-english-words/
Convert a non-negative integer to its english words representation. Given input is guaranteed to be less than 231 - 1.
For example,
123 -> "One Hundred Twenty Three"
12345 -> "Twelve Thousand Three Hundred Forty Five"
1234567 -> "One Million Two Hundred Thirty Four Thousand Five Hundred Sixty Seven"
public class Solution {
private final String[] c = {"Billion", "Million", "Thousand", ""};
private final String[] Tens = {"", "", "Twenty", "Thirty", "Forty", "Fifty", "Sixty", "Seventy", "Eighty", "Ninety"};
private final String[] Basics = {"", "One", "Two", "Three", "Four", "Five", "Six", "Seven", "Eight", "Nine", "Ten", "Eleven", "Twelve", "Thirteen", "Fourteen", "Fifteen", "Sixteen", "Seventeen", "Eighteen", "Nineteen"};
private String getField(int idx, int size) {
if(size == 4) {
if(idx == 0) return "Billion";
else if(idx == 1) return "Million";
else if(idx == 2) return "Thousand";
else if(idx == 3) return "";
}
else if(size == 3) {
if(idx == 0) return "Million";
else if(idx == 1) return "Thousand";
else if(idx == 2) return "";
}
else if(size == 2) {
if(idx == 0) return "Thousand";
else if(idx == 1) return "";
}
return "";
}
private LinkedList<String> read(int n) {
LinkedList<String> rs = new LinkedList<String> ();
int hundred = (n % 1000) / 100;
int ten = (n % 100) / 10;
int unit = n % 10;
if(hundred > 0) {
rs.addLast(Basics[hundred]);
rs.addLast("Hundred");
}
if(ten > 0) {
if(ten == 1) {
int combo = ten * 10 + unit;
rs.addLast(Basics[combo]);
return rs;
} else {
rs.addLast(Tens[ten]);
}
}
if(unit > 0) {
rs.addLast(Basics[unit]);
}
return rs;
}
public String numberToWords(int num) {
if(num == 0) {
return "Zero";
}
LinkedList<Integer> d = new LinkedList<Integer> ();
while(num > 0) {
d.addFirst(num % 1000);
num/=1000;
}
LinkedList<String> ls = new LinkedList<String> ();
for(int i=0; i<d.size(); ++i) {
if(d.get(i) == 0) continue;
LinkedList<String> r = read(d.get(i));
String field = getField(i, d.size());
if(i == d.size() - 1) ls.addAll(r);
else {
ls.addAll(r);
ls.addLast(field);
}
}
StringBuffer rs = new StringBuffer();
for(int i=0; i<ls.size() - 1; ++i) {
rs.append(ls.get(i));
rs.append(" ");
}
rs.append(ls.peekLast());
return rs.toString().trim();
}
}
leetcode@ [273] Integer to English Words (String & Math)的更多相关文章
- [LeetCode] 273. Integer to English Words 整数转为英文单词
Convert a non-negative integer to its english words representation. Given input is guaranteed to be ...
- LeetCode 273. Integer to English Words
原题链接在这里:https://leetcode.com/problems/integer-to-english-words/description/ 题目: Convert a non-negati ...
- [leetcode]273. Integer to English Words 整数转英文单词
Convert a non-negative integer to its english words representation. Given input is guaranteed to be ...
- leetcode-【hard】273. Integer to English Words
题目: 273. Integer to English Words Convert a non-negative integer to its english words representation ...
- 【LeetCode】273. Integer to English Words
Integer to English Words Convert a non-negative integer to its english words representation. Given i ...
- 【LeetCode】Integer to English Words 解题报告
Integer to English Words [LeetCode] https://leetcode.com/problems/integer-to-english-words/ Total Ac ...
- 273. Integer to English Words
题目: Convert a non-negative integer to its english words representation. Given input is guaranteed to ...
- 273. Integer to English Words数字转为单词
[抄题]: Convert a non-negative integer to its english words representation. Given input is guaranteed ...
- [LC] 273. Integer to English Words
Convert a non-negative integer to its english words representation. Given input is guaranteed to be ...
随机推荐
- linux硬件驱动层
1.make menuconfig scripts/kconfig/lxdialog/menubox.o: In function `print_buttons':menubox.c:(.text+0 ...
- HDU 4664 Triangulation(SG函数)
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4664 题意:给出一个n个点的凸包(不存在三点共线).每次可以选择两个点连线,但是任意两条线只能在顶点处 ...
- Asp.net Web Api进行Nunit测试
有两种方式 1.模拟Web请求. 2.直接本地调用Api接口 但是由于本地直接调用没有模拟请求环境,所以request为null public static HttpResponseMessage C ...
- CSS控制超链接
一.伪类 CSS控制元素的某种状态---偽类(用于向某些选择器添加特殊的效果) 偽类的语法:元素标签 偽类名称{属性:属性值;} 二.超链接 a:link:未访问的链接 ...
- CSS之弧形阴影
简述 网页上经常会出现一些弧形的阴影效果,看起来很漂亮,下面我们来讲述下如何用CSS来实现一个弧形阴影. 简述 阴影 效果 注释 标题 效果 源码 合并 效果 源码 阴影 效果 首先实现一个简单的阴影 ...
- Uva 10382 (区间覆盖) Watering Grass
和 Uva 10020几乎是一样的,不过这里要把圆形区域转化为能够覆盖的长条形区域(一个小小的勾股定理) 学习一下别人的代码,练习使用STL的vector容器 这里有个小技巧,用一个微小量EPS来弥补 ...
- Web程序员最常用的11款PHP框架
PHP框架是Web程序员和开发人员最为有用的工具. PHP框架可以帮助用户更快地开发项目. 今天我将为开发人员带来几款最好的PHP框架,希望能对你有用. 1.Agavi Agavi是一款强大的,可扩展 ...
- cURL: PHP并发处理方式
function classic_curl($urls, $delay) { $queue = curl_multi_init(); $map = array(); foreach ($urls as ...
- Android RemoteViews 11问11答
1.什么是RemoteView? 答:其实就是一种特殊的view结构,这种view 能够跨进程传输.并且这种remoteview 还提供了一些方法 可以跨进程更新界面.具体在android里面 一个是 ...
- bootstrap-datepicker 插件修改为默认中文
bootstrap-datepicker 是一个非常优秀的时间选择插件,默认是英文显示日期的,通过下面几个小修改让其支持默认中文 1.首先将 bootstrap-datepicker.js 另存为 u ...