Geeks : Kruskal’s Minimum Spanning Tree Algorithm 最小生成树
版权声明:本文作者靖心,靖空间地址:http://blog.csdn.net/kenden23/。未经本作者同意不得转载。
https://blog.csdn.net/kenden23/article/details/26821635
寻找图中最小连通的路径,图例如以下:

算法步骤:
1. Sort all the edges in non-decreasing order of their weight. 2. Pick the smallest edge. Check if it forms a cycle with the spanning tree
formed so far. If cycle is not formed, include this edge. Else, discard it. 3. Repeat step#2 until there are (V-1) edges in the spanning tree.
关键是第二步难,这里使用Union Find来解决,能够差点儿小于O(lgn)的时间效率来推断是否须要推断的顶点和已经选择的顶点成环。
正由于这步,使得原本简单的贪心法。变得不那么简单了。
这样本算法的时间效率达到:max(O(ElogE) , O(ElogV))
原文參考:http://www.geeksforgeeks.org/greedy-algorithms-set-2-kruskals-minimum-spanning-tree-mst/
#pragma once
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
class KruskalsMST
{
struct Edge
{
int src, des, weight;
};
static int cmp(const void *a, const void *b)
{
Edge *a1 = (Edge *) a, *b1 = (Edge *) b;
return a1->weight - b1->weight;
}
struct Graph
{
int V, E;
Edge *edges;
Graph(int v, int e) : V(v), E(e)
{
edges = new Edge[e];
}
virtual ~Graph()
{
if (edges) delete [] edges;
}
};
struct SubSet
{
int parent, rank;
};
int find(SubSet *subs, int i)
{
if (subs[i].parent != i)
subs[i].parent = find(subs, subs[i].parent);
return subs[i].parent;
}
void UnionTwo(SubSet *subs, int x, int y)
{
int xroot = find(subs, x);
int yroot = find(subs, y);
if (subs[xroot].rank < subs[yroot].rank)
subs[xroot].parent = yroot;
else if (subs[xroot].rank > subs[yroot].rank)
subs[yroot].parent = xroot;
else
{
subs[xroot].rank++;
subs[yroot].parent = xroot;
}
}
Graph *graph;
Edge *res;
SubSet *subs;
void initSubSet()
{
subs = new SubSet[graph->V];
for (int i = 0; i < graph->V; i++)
{
subs[i].parent = i;
subs[i].rank = 0;
}
}
void mst()
{
res = new Edge[graph->V-1];
qsort(graph->edges, graph->E, sizeof(graph->edges[0]), cmp);
initSubSet();
for (int e = 0, i = 0; e < graph->V - 1 && i < graph->E; i++)
{
Edge nextEdge = graph->edges[i];
int x = find(subs, nextEdge.src);
int y = find(subs, nextEdge.des);
if (x != y)
{
res[e++] = nextEdge;
UnionTwo(subs, x, y);
}
}
}
void printResult()
{
printf("Following are the edges in the constructed MST\n");
for (int i = 0; i < graph->V-1; ++i)
printf("%d -- %d == %d\n", res[i].src, res[i].des, res[i].weight);
}
public:
KruskalsMST()
{
/* Let us create following weighted graph
10
0--------1
| \ |
6| 5\ |15
| \ |
2--------3
4 */
int V = 4; // Number of vertices in graph
int E = 5; // Number of edges in graph
graph = new Graph(V, E);
// add edge 0-1
graph->edges[0].src = 0;
graph->edges[0].des = 1;
graph->edges[0].weight = 10;
// add edges 0-2
graph->edges[1].src = 0;
graph->edges[1].des = 2;
graph->edges[1].weight = 6;
// add edges 0-3
graph->edges[2].src = 0;
graph->edges[2].des = 3;
graph->edges[2].weight = 5;
// add edges 1-3
graph->edges[3].src = 1;
graph->edges[3].des = 3;
graph->edges[3].weight = 15;
// add edges 2-3
graph->edges[4].src = 2;
graph->edges[4].des = 3;
graph->edges[4].weight = 4;
mst();
printResult();
}
~KruskalsMST()
{
if (res) delete [] res;
if (subs) delete [] subs;
if (graph) delete graph;
}
};Geeks : Kruskal’s Minimum Spanning Tree Algorithm 最小生成树的更多相关文章
- MST(Kruskal’s Minimum Spanning Tree Algorithm)
You may refer to the main idea of MST in graph theory. http://en.wikipedia.org/wiki/Minimum_spanning ...
- 【HDU 4408】Minimum Spanning Tree(最小生成树计数)
Problem Description XXX is very interested in algorithm. After learning the Prim algorithm and Krusk ...
- 说说最小生成树(Minimum Spanning Tree)
minimum spanning tree(MST) 最小生成树是连通无向带权图的一个子图,要求 能够连接图中的所有顶点.无环.路径的权重和为所有路径中最小的. graph-cut 对图的一个切割或者 ...
- 最小生成树(Minimum Spanning Tree)——Prim算法与Kruskal算法+并查集
最小生成树——Minimum Spanning Tree,是图论中比较重要的模型,通常用于解决实际生活中的路径代价最小一类的问题.我们首先用通俗的语言解释它的定义: 对于有n个节点的有权无向连通图,寻 ...
- HDU 4408 Minimum Spanning Tree 最小生成树计数
Minimum Spanning Tree Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Ot ...
- 【算法】关于图论中的最小生成树(Minimum Spanning Tree)详解
本节纲要 什么是图(network) 什么是最小生成树 (minimum spanning tree) 最小生成树的算法 什么是图(network)? 这里的图当然不是我们日常说的图片或者地图.通常情 ...
- 数据结构与算法分析–Minimum Spanning Tree(最小生成树)
给定一个无向图,如果他的某个子图中,任意两个顶点都能互相连通并且是一棵树,那么这棵树就叫做生成树(spanning tree). 如果边上有权值,那么使得边权和最小的生成树叫做最小生成树(MST,Mi ...
- Educational Codeforces Round 3 E. Minimum spanning tree for each edge 最小生成树+树链剖分+线段树
E. Minimum spanning tree for each edge time limit per test 2 seconds memory limit per test 256 megab ...
- hdu 4408 Minimum Spanning Tree
Problem Description XXX is very interested in algorithm. After learning the Prim algorithm and Krusk ...
随机推荐
- [HTML5] Canvas绘制简单形状
使用canvas来进行绘画,它像很多其他dom对象一样,有很多属性和方法,操作这些方法,实现绘画 获取canvas对象,调用document.getElementById()方法 调用canvas对象 ...
- log4j.properties配置模板
# For JBoss: Avoid to setup Log4J outside $JBOSS_HOME/server/default/deploy/log4j.xml! # For all oth ...
- 【原】Shiro框架基础搭建[2]
简介: 关于搭建一个最基础的shiro网上的例子有很多,这里是记录一下自己尝试去看官方文档所搭建的一个小demo,项目采用的是原始的java静态工程,导入相关jar包后就能运行. 首先进入官网http ...
- K:有限状态自动机
有限状态自动机是一种特殊的状态机.它表示有限个状态以及在这些状态之间的转移和动作等行为的数学模型.有限状态自动机分为两种,一种是 确定有限状态自动机(DFA) ,一种是 非确定有限状态自动机(NF ...
- Jquery全选系列操作(锋利的jQuery)
Jquery全选系列操作(锋利的jQuery) <!DOCTYPE html> <html xmlns="http://www.w3.org/1999/xhtml" ...
- spring代理例子
---------------------------------------------------------- 先来看一下目录结构 显然service里面有两个java文件,UserDao是接口 ...
- .NET源代码已经下载,潜心研读…
有兴趣的弟兄可以从这里下载:http://referencesource.microsoft.com
- Hadoop总结
背景 Hadoop是一个由Apache基金会所开发的分布式系统基础架构.用户可以在不了解分布式底层细节的情况下,开发分布式程序.充分利用集群的威力进行高速运算和存储. Mapreduce1 vs YA ...
- 扩展LV手记
情景概览 系统:CentOS Linux release 7.4.1708 (Core) 磁盘情况: 目标:将sda3扩展到sda2下的centos-root虚拟盘上 操作步骤 1.建立新的PV # ...
- java基础——队列
目录 前言 基础 实现: 两个队列模拟一个堆栈 前言 java已经提供了堆和栈的相对应的类,这里只是模拟一下队列. 队列是一种先进先出的线性表. 基础 java5中新增加了java.util.Queu ...