一个python练习

问题描述：

有一对兔子，每隔3个月就生一对兔子，生下来的兔子也是每隔3个月就生兔子，以此类推。。。

用python模拟出来：

 #!/usr/bin/python3
 import random
 import string

 class APairOfRabbits():
     def __init__(self):
         self.age = 1
         self.malename = ''.join(random.sample(string.ascii_letters, 5))
         self.femalename = ''.join(random.sample(string.ascii_letters, 4))
         self.childs = []
         self.parent = None
     def getParentInfo(self):
         if (None == self.parent):
             return None
         else:
             print("ParentsName: %s" % self.parent.getName())
     def getChildsInfo(self):
         for child in self.childs:
             print("ChildsName:%s" % child.getName())
         print("")
     def info(self):
         print('%s and %s: age %d' % (self.malename, self.femalename, self.age))
         self.getParentInfo()
         self.getChildsInfo()

     def propagate(self):
         self.childs.append(APairOfRabbits())
         self.childs[-1].setParent(self)
     def getName(self):
         return self.malename + "-" + self.femalename
     def growUpOfMonth(self):
         self.age += 1
         if(0 == (self.age % 3)):
             self.propagate()

     def setParent(self, parent):
         self.parent = parent
     def getParent(self):
         return self.parent
     def getChilds(self):
         return self.childs

 class RabbitsFamily():
     def __init__(self):
         self.rootRabbits = APairOfRabbits()
     def dfsUpdateState(self, parent = None):
         if None == parent:
             parent = self.rootRabbits
         for child in parent.getChilds():
             self.dfsUpdateState(child)
         parent.growUpOfMonth()
     def dfsShowState(self, parent = None):
         if None == parent:
             parent = self.rootRabbits
         parent.info()
         for child in parent.getChilds():
             self.dfsShowState(child)

 rabbitsFamily = RabbitsFamily()
 for i in range(55):
     rabbitsFamily.dfsUpdateState()
 rabbitsFamily.dfsShowState()