LeetCode 337. House Robber III 动态演示
每个节点是个房间,数值代表钱。小偷偷里面的钱,不能偷连续的房间,至少要隔一个。问最多能偷多少钱
TreeNode* cur
mp[{cur, true}]表示以cur为根的树,最多能偷的钱
mp[{cur, false}]表示以cur为根的树,不偷cur节点的钱,最多能偷的钱
可以看出有下面的关系
mp[{node, false}] = mp[{node->left,true}] + mp[{node->right,true}]
mp[{node, true}] = max(node->val + mp[{node->left,false}] + mp[{node->right,false}], mp[{node, false}])
class Solution {
public:
void helper(TreeNode* node, map<pair<TreeNode*, bool>,int>& mp){
if(!node){
return;
}
//a(node)
//lk("root",node)
helper(node->left, mp);
helper(node->right, mp);
mp[{node, false}] = mp[{node->left,true}] + mp[{node->right,true}];
mp[{node, true}] = max(node->val + mp[{node->left,false}] + mp[{node->right,false}],
mp[{node, false}]);
//dsp
}
int rob(TreeNode* root) {
map<pair<TreeNode*, bool>,int> mp;
//amap(mp, pair<TreeNode*, bool>,int)
//ahd(root)
mp[{NULL, true}]=;
mp[{NULL, false}]=;
helper(root, mp);
return max(mp[{root, false}], mp[{root, true}]);
}
};
动态演示 http://simpledsp.com/FS/Html/lc337.html
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原文链接:https://blog.csdn.net/bntx2jsqfehy7/article/details/78977178