Shortest Prefixes
Time Limit: 1000MS   Memory Limit: 30000K
Total Submissions: 15948   Accepted: 6887

Description

A prefix of a string is a substring starting at the beginning of the given string. The prefixes of "carbon" are: "c", "ca", "car", "carb", "carbo", and "carbon". Note that the empty string is not considered a prefix in this problem, but every non-empty string is considered to be a prefix of itself. In everyday language, we tend to abbreviate words by prefixes. For example, "carbohydrate" is commonly abbreviated by "carb". In this problem, given a set of words, you will find for each word the shortest prefix that uniquely identifies the word it represents.

In the sample input below, "carbohydrate" can be abbreviated to
"carboh", but it cannot be abbreviated to "carbo" (or anything shorter)
because there are other words in the list that begin with "carbo".

An exact match will override a prefix match. For example, the prefix
"car" matches the given word "car" exactly. Therefore, it is understood
without ambiguity that "car" is an abbreviation for "car" , not for
"carriage" or any of the other words in the list that begins with "car".

Input

The
input contains at least two, but no more than 1000 lines. Each line
contains one word consisting of 1 to 20 lower case letters.

Output

The
output contains the same number of lines as the input. Each line of the
output contains the word from the corresponding line of the input,
followed by one blank space, and the shortest prefix that uniquely
(without ambiguity) identifies this word.

Sample Input

carbohydrate
cart
carburetor
caramel
caribou
carbonic
cartilage
carbon
carriage
carton
car
carbonate

Sample Output

carbohydrate carboh
cart cart
carburetor carbu
caramel cara
caribou cari
carbonic carboni
cartilage carti
carbon carbon
carriage carr
carton carto
car car
carbonate carbona
题解:让找唯一能确定一个单词的前缀;我们想到当唯一确定的时候必定word[k]是1;那么很好解决了
代码:
 #include<iostream>
#include<algorithm>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<vector>
#define mem(x,y) memset(x,y,sizeof(x))
using namespace std;
typedef long long LL;
const int MAXN=;
char s[][];
int ch[MAXN][],word[MAXN];
int sz;
void initial(){
sz=;
mem(word,);
}
void insert(char *s){
int len=strlen(s);
int j,k=;
for(int i=;i<len;i++){
j=s[i]-'a';
if(!ch[k][j]){
mem(ch[sz],);
ch[k][j]=sz++;
}
k=ch[k][j];
word[k]++;
}
}
void find(char *s){
int len=strlen(s);
int j,k=;
for(int i=;i<len;i++){
j=s[i]-'a';
k=ch[k][j];
printf("%c",s[i]);
if(word[k]==)return;
}
}
int main(){
int x=;
initial();
while(~scanf("%s",s[x])){
insert(s[x]);x++;
}
for(int i=;i<x;i++){
printf("%s ",s[i]);
find(s[i]);puts("");
}
return ;
}
												

Shortest Prefixes(trie树唯一标识)的更多相关文章

  1. poj2001 Shortest Prefixes (trie树)

    Description A prefix of a string is a substring starting at the beginning of the given string. The p ...

  2. poj 2001 Shortest Prefixes(字典树trie 动态分配内存)

    Shortest Prefixes Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 15610   Accepted: 673 ...

  3. poj 2001 Shortest Prefixes trie入门

    Shortest Prefixes 题意:输入不超过1000个字符串,每个字符串为小写字母,长度不超过20:之后输出每个字符串可以简写的最短前缀串: Sample Input carbohydrate ...

  4. poj2001 Shortest Prefixes(字典树)

    Shortest Prefixes Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 21642   Accepted: 926 ...

  5. POJ 2001 Shortest Prefixes (Trie)

    题目链接:POJ 2001 Description A prefix of a string is a substring starting at the beginning of the given ...

  6. poj 2001 Shortest Prefixes(字典树)

    题目链接:http://poj.org/problem?id=2001 思路分析: 在Trie结点中添加数据域childNum,表示以该字符串为前缀的字符数目: 在创建结点时,路径上的所有除叶子节点以 ...

  7. POJ 2001 Shortest Prefixes(字典树)

    题目地址:POJ 2001 考察的字典树,利用的是建树时将每个点仅仅要走过就累加.最后从根节点開始遍历,当遍历到仅仅有1次走过的时候,就说明这个地方是最短的独立前缀.然后记录下长度,输出就可以. 代码 ...

  8. poj 2001:Shortest Prefixes(字典树,经典题,求最短唯一前缀)

    Shortest Prefixes Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 12731   Accepted: 544 ...

  9. POJ 2001 Shortest Prefixes 【 trie树(别名字典树)】

    Shortest Prefixes Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 15574   Accepted: 671 ...

随机推荐

  1. JAVA 语 言 如 何 进 行 异 常 处 理 , 关 键 字 : throws,throw,try,catch,final

    throws是获取异常throw是抛出异常try是将会发生异常的语句括起来,从而进行异常的处理,catch是如果有异常就会执行他里面的语句,而finally不论是否有异常都会进行执行的语句.

  2. BZOJ 1509: [NOI2003]逃学的小孩( 树形dp )

    树形dp求出某个点的最长3条链a,b,c(a>=b>=c), 然后以这个点为交点的最优解一定是a+2b+c.好像还有一种做法是求出树的直径然后乱搞... ----------------- ...

  3. BOM 浏览器对象模型学习

    window对象属性 innerWidth/innerHeight 浏览器窗口的内部宽度与高度 outerWidth/outerHeight 浏览器的外部宽度与高度 length window.fra ...

  4. 用python 10min手写一个简易的实时内存监控系统

    简易的内存监控系统 本文需要有一定的python和前端基础,如果没基础的,请关注我后续的基础教程系列博客 文章github源地址,还可以看到具体的代码,喜欢请在原链接右上角加个star 腾讯视频链接 ...

  5. Web存储(Web Storage)介绍

    Web存储即在客户端存储数据. 在没有Web Storage之前,是通过cookie来在客户端存储数据的.但是由于 浏览器能存cookie数比较少.如IE8,Firefox,opera每个域可以保存的 ...

  6. python进阶4--pywin32

    python 在windows下系统编程 1.环境配置:Python是没有自带访问windows系统API的库的,需要下载.库的名称叫pywin32,可以从网上直接下载. 以下链接地址可以下载: ht ...

  7. css 自适应布局

    转载一篇文章: 自适应网页设计(Responsive Web Design) 作者: 阮一峰 移动设备正超过桌面设备,成为访问互联网的最常见终端.于是,网页设计师不得不面对一个难题:如何才能在不同大小 ...

  8. #308 (div.2) A. Vanya and Table

    1.题目描写叙述:点击打开链接 2.解题思路:本题是一道简单的模拟题.每次扫描一个输入的长方形,然后将内部全部点都+1,终于统计数组全部元素的和就可以. 3.代码: #define _CRT_SECU ...

  9. JAVA訪问URL

    JAVA訪问URL: package Test; import java.io.BufferedReader; import java.io.IOException; import java.io.I ...

  10. 对武汉-and-IT软件开发的看法

    本编是一个武汉农村娃子,2015年毕业到现在算上实习 差不多快三年的时间了.在软件行业混的也就一般水平,从开心在学校学习的winform+DBHelper 的开发模式,到现在MVC+EF 的开发模式. ...