uva 10107 - What is the Median?
#include <cstdio>
#include <iostream>
using namespace std; long long Median, arr[]; int main()
{
int i, cur_index, count, isOdd;
count = ;
while(scanf("%lld", &arr[]) != EOF) // arr[0] is a monitor
{
count ++; // count: caculate numbers
cur_index = count; // cur_index initial value: count
for(i=; i<count; i++)
{
if(arr[] < arr[i])
{
cur_index = i;
break;
}
} for(i=count; i>cur_index; i--) // backword move to arr[count]
arr[i] = arr[i-]; arr[cur_index] = arr[]; // whatever, this is must. isOdd = count % ;
if(isOdd)
Median = arr[count/ + ]; // odd
else Median = (arr[count/ +] + arr[count/]) / ; // even cout << Median << endl;
}
return ;
}
犯错:漏写 break; 语句
//
#include <cstdio>
#include <iostream>
using namespace std; int main()
{
int x, i, j, arr[], n = ;
while(scanf("%d", &x) != EOF)
{
j = n;
for(i = ; i < n; i++)
if(x < arr[i])
{
j = i;
break;
}
for(i=n; i > j; i--)
arr[i] = arr[i-];
arr[j] = x;
n ++; if(n % ) cout << arr[n / ] << endl;
else {
long median = ;
median = median + arr[n / - ] + arr[n / ];
cout << median / << endl;
}
}
return ;
}
uva 10107 - What is the Median?的更多相关文章
- No.004:Median of Two Sorted Arrays
问题: There are two sorted arrays nums1 and nums2 of size m and n respectively.Find the median of the ...
- [LeetCode] Find Median from Data Stream 找出数据流的中位数
Median is the middle value in an ordered integer list. If the size of the list is even, there is no ...
- [LeetCode] Median of Two Sorted Arrays 两个有序数组的中位数
There are two sorted arrays nums1 and nums2 of size m and n respectively. Find the median of the two ...
- Applying vector median filter on RGB image based on matlab
前言: 最近想看看矢量中值滤波(Vector median filter, VMF)在GRB图像上的滤波效果,意外的是找了一大圈却发现网上没有现成的code,所以通过matab亲自实现了一个,需要学习 ...
- 【leetcode】Median of Two Sorted Arrays
题目简述: There are two sorted arrays A and B of size m and n respectively. Find the median of the two s ...
- Codeforces Round #327 (Div. 2) B. Rebranding C. Median Smoothing
B. Rebranding The name of one small but proud corporation consists of n lowercase English letters. T ...
- uva 1354 Mobile Computing ——yhx
aaarticlea/png;base64,iVBORw0KGgoAAAANSUhEUgAABGcAAANuCAYAAAC7f2QuAAAgAElEQVR4nOy9XUhjWbo3vu72RRgkF5
- UVA 10564 Paths through the Hourglass[DP 打印]
UVA - 10564 Paths through the Hourglass 题意: 要求从第一层走到最下面一层,只能往左下或右下走 问有多少条路径之和刚好等于S? 如果有的话,输出字典序最小的路径 ...
- UVA 11404 Palindromic Subsequence[DP LCS 打印]
UVA - 11404 Palindromic Subsequence 题意:一个字符串,删去0个或多个字符,输出字典序最小且最长的回文字符串 不要求路径区间DP都可以做 然而要字典序最小 倒过来求L ...
随机推荐
- php 编译安装选项
./configure --prefix=/usr/local/php/ --with-config-file-path=/etc/php5/cli/ --with-config-file-scan- ...
- Android事件监听器Event Listener
在 Android 中,我们可以通过事件处理使UI与用户互动(UI Events). UI的用户事件处理,即View处理用户的操作,在应用程序中几乎不可避免.View是重要的类,它是与用户互动的前线: ...
- 深入理解CSS选择器优先级的计算
选择器的优先级关系到元素应用哪个样式.在CSS2.1的规范(http://www.w3.org/TR/2009/CR-CSS2-20090908/cascade.html#specificity)中是 ...
- ural 1106 Two Teams
http://acm.timus.ru/problem.aspx?space=1&num=1106 #include <cstdio> #include <cstring&g ...
- mysql System Tablespace
System Tablespace 数据文件配置: mysql> show variables like '%innodb_data_file_path%'; +---------------- ...
- Oracle extent
extent 上的块 物理上绝对连续 多个连续的block组成一个extent 不连续怎么多块读? Oracle 给表分配的单位是extent 去做 全表扫描的时候 以块为单位,按照extent来读取 ...
- 【HDOJ】1332 LC-Display
水题. #include <cstdio> #include <cstring> #include <cstdlib> #define MAXN 11 #defin ...
- 易pc,1G容量以上的u盘,另外还要一台装了windows系统的电脑。
一.硬件:易pc,1G容量以上的u盘,另外还要一台装了windows系统的电脑. 二.软件: 1.windows xp的安装包.考虑到易PC的硬盘容量,还是用精简版的吧,比如“Deepin XP Li ...
- 简述WebService与.NET Remoting的区别及适应场合 WCF
原创作品,允许转载,转载时请务必以超链接形式标明文章 原始出处 .作者信息和本声明.否则将追究法律责任.http://zhoufoxcn.blog.51cto.com/792419/166990 为了 ...
- JS浏览器对象-Screen对象
代码: <!DOCTYPE html> <html> <head> <meta charset="UTF-8"> <title ...