leetcode — word-ladder-ii
import java.util.*;
/**
* Source : https://oj.leetcode.com/problems/word-ladder-ii/
*
*
* Given two words (start and end), and a dictionary, find all shortest transformation
* sequence(s) from start to end, such that:
*
* Only one letter can be changed at a time
* Each intermediate word must exist in the dictionary
*
* For example,
*
* Given:
* start = "hit"
* end = "cog"
* dict = ["hot","dot","dog","lot","log"]
*
* Return
*
* [
* ["hit","hot","dot","dog","cog"],
* ["hit","hot","lot","log","cog"]
* ]
*
* Note:
*
* All words have the same length.
* All words contain only lowercase alphabetic characters.
*
*/
public class WordLadder2 {
/**
* 在wordladder1的基础上,找到start到end的所有变化路径
*
* 这里需要回溯,采用深度优先DFS
*
* 优化:
* 因为这需要回溯,也就是说可能会重复计算某个单词的neighbors,所以可以实现将所有的单词构造成一棵树,就不需要每次计算neighbors
*
* @param start
* @param end
* @param dict
* @return
*/
public List<List<String>> findLadders (String start, String end, String[] dict) {
Set<String> set = new HashSet<String>(Arrays.asList(dict));
set.add(end);
List<List<String>> result = new ArrayList<List<String>>();
Set<String> list = new HashSet<String>();
list.add(start);
List<String> ladder = new ArrayList<String>();
recursion(list, end, ladder, result, set);
return result;
}
public void recursion (Set<String> list, String end, List<String> ladder, List<List<String>> result, Set<String> set) {
for (String str : list) {
ladder.add(str);
if (str.equals(end)) {
result.add(new ArrayList<String>(ladder));
}
Set<String> neighbors = findNeighbors(str,set);
recursion(neighbors, end, ladder, result, set);
set.addAll(neighbors);
ladder.remove(str);
}
}
private Set<String> findNeighbors (String cur, Set<String> dict) {
Set<String> neighbors = new HashSet<String>();
for (int i = 0; i < cur.length(); i++) {
for (int j = 0; j < 26; j++) {
char ch = (char) ('a' + j);
if (cur.charAt(i) != ch) {
String candidate = "";
if (i == cur.length()-1) {
candidate = cur.substring(0, i) + ch;
} else {
candidate = cur.substring(0, i) + ch + cur.substring(i+1);
}
if (dict.contains(candidate)) {
neighbors.add(candidate);
dict.remove(candidate);
}
}
}
}
return neighbors;
}
public static void print (List<List<String>> list) {
for (List<String> strList : list) {
System.out.println(Arrays.toString(strList.toArray(new String[strList.size()])));
}
}
public static void main(String[] args) {
WordLadder2 wordLadder2 = new WordLadder2();
String start = "hit";
String end = "cog";
String[] dict = new String[]{"hot","dot","dog","lot","log"};
print(wordLadder2.findLadders(start, end, dict));
}
}
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