javaScript 习题总结(持续更新)

判定偶数

function collect_all_even(collection) {
  return collection.filter(item => item%2 == 0);
}

两个集合的交集

function get_intersection(collection_a, collection_b) {
  return collection_b.filter(item => collection_a.includes(item))
}

两个集合的并集

function get_union(collection_a, collection_b) {
  return new Set([...collection_a,...collection_b]);
}

升序排序

arr.sort((arr1, arr2) => arr1 - arr2)