Given an array A of integers and integer K, return the maximum S such that there exists i < j with A[i] + A[j] = S and S < K. If no i, j exist satisfying this equation, return -1.

Example 1:

Input: A = [34,23,1,24,75,33,54,8], K = 60
Output: 58
Explanation:
We can use 34 and 24 to sum 58 which is less than 60.

Example 2:

Input: A = [10,20,30], K = 15
Output: -1
Explanation:
In this case it's not possible to get a pair sum less that 15.

Note:

  1. 1 <= A.length <= 100
  2. 1 <= A[i] <= 1000
  3. 1 <= K <= 2000
class Solution {
public int twoSumLessThanK(int[] A, int K) {
if (A == null || A.length == 0) {
return -1;
}
Arrays.sort(A);
int start = 0, end = A.length - 1;
int res = -1;
while (start < end) {
if (A[start] + A[end] >= K) {
end -= 1;
} else {
res = Math.max(res, A[start] + A[end]);
start += 1;
}
}
return res;
}
}

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