!/usr/bin/env bash

 

_chef_dir ()
{

# Helper function:

# Recursive function that searches for chef configuration directory

# It looks upward from the cwd until it hits /. If no directory is found,

# ~/.chef is chosen if it exists

# You could simply hard-code the path below

 

if
[
"$PWD"
=
"/"
]; then

if
[ -d ".chef"
]; then


echo
"/.chef"

elif
[ -d "$HOME/.chef"
]; then


echo
"$HOME/.chef"

fi

return

fi

 

if
[ -d '.chef'
];then


echo
"${PWD}/.chef"

else

(cd ..; _chef_dir)

fi

}

 

_chomp ()
{

# helper function to remove newlines

awk '{printf "%s", $0}'

}

 

chef_api_request()
{

# This is the meat-and-potatoes, or rice-and-vegetables, your preference really.

 

local method path body timestamp chef_server_url client_name hashed_body hashed_path

local canonical_request headers auth_headers

 

chef_server_url="https://api.opscode.com/organizations/my_org"

# '/organizations/ORG_NAME' is needed for Hosted Chef or Private Chef

if echo
$chef_server_url | grep -q "/organizations/" ; then


endpoint=/organizations/${chef_server_url#*/organizations/}${2%%\?*}

else


endpoint=${$2%%\?*}

fi


path=${chef_server_url}$2

client_name="chef_user"

method=$1

body=$3

 

hashed_path=$(echo -n "$endpoint" | openssl dgst -sha1 -binary | openssl enc -base64)

hashed_body=$(echo -n "$body" | openssl dgst -sha1 -binary | openssl enc -base64)

timestamp=$(date -u "+%Y-%m-%dT%H:%M:%SZ")

 

canonical_request="Method:$method\nHashed Path:$hashed_path\nX-Ops-Content-Hash:$hashed_body\nX-Ops-Timestamp:$timestamp\nX-Ops-UserId:$client_name"

headers="-H X-Ops-Timestamp:$timestamp \

-H X-Ops-Userid:$client_name \

-H X-Chef-Version:0.10.4 \

-H Accept:application/json \

-H X-Ops-Content-Hash:$hashed_body \

-H X-Ops-Sign:version=1.0"

 

auth_headers=$(printf
"$canonical_request" | openssl rsautl -sign -inkey \

"$(_chef_dir)/${client_name}.pem" | openssl enc -base64 | _chomp | awk '{ll=int(length/60);i=0; \

while (i<=ll) {printf " -H X-Ops-Authorization-%s:%s", i+1, substr($0,i*60+1,60);i=i+1}}')

 

case
$method in

GET)

curl_command="curl $headers $auth_headers $path"

$curl_command

;;

*)

echo
"Unknown Method. I only know: GET" >&2

return 1

;;

esac

}

 

chef_api_request "$@"

How to interact with the Chef Server using the Chef Server API using Shell script的更多相关文章

  1. Server Tomcat v7.0 Server at localhost was unable to start within 45 seconds

    错误:Server Tomcat v7.0 Server at localhost was unable to start within 45 seconds 错误提示就是我们限定了部署的时间导致的错 ...

  2. Step by step Install a Local Report Server and Remote Report Server Database

    原创地址:http://www.cnblogs.com/jfzhu/p/4012097.html 转载请注明出处 前面的文章<Step by step SQL Server 2012的安装 &g ...

  3. Server Tomcat v7.0 Server at localhost was unable to&amp;nbs 报错问题解决

    在eclipse启动tomcat时遇到超时45秒的问题: Server Tomcat v7.0 Server at localhost was unable to start within 45 se ...

  4. Comparison of SQL Server Compact, SQLite, SQL Server Express and LocalDB

    Information about LocalDB comes from here and SQL Server 2014 Books Online. LocalDB is the full SQL ...

  5. Server Tomcat v6.0 Server at localhost was unable to start within 45 seconds...

    仰天长啸   Server Tomcat v6.0 Server at localhost was unable to start within 45 seconds... 当启动tomcat时候出现 ...

  6. Server Tomcat v7.0 Server at localhost was unable to start within 45 seconds -----》myeclipse2015

    错误:Server Tomcat v7.0 Server at localhost was unable to start within 45 seconds 错误提示就是我们限定了部署的时间导致的错 ...

  7. Server Tomcat v6.0 Server at localhost was unable to start within 45 seconds问题

    错误:Server Tomcat v6.0 Server at localhost was unable to start within 45 seconds. If the server requi ...

  8. Server Tomcat v7.0 Server at localhost was unable to&nbs 报错问题解决

    在eclipse启动tomcat时遇到超时45秒的问题: Server Tomcat v7.0 Server at localhost was unable to start within 45 se ...

  9. Server Tomcat v7.0 Server at localhost failed to start.临时解决办法

    错误名:Server Tomcat v7.0 Server at localhost failed to start. 解决办法:去掉下面这句话: (通常在代码开头部分,public class前) ...

随机推荐

  1. 69. Sqrt(x)

    题目: Implement int sqrt(int x). Compute and return the square root of x. 链接:   http://leetcode.com/pr ...

  2. CentOS7 升级python同时解决yum损坏问题

    CentOS7中的python版本为python2.7.5,升级到最新版的python时需要注意两个问题 新版的python安装好后要修改python的系统默认指向问题 升级到最新版python后yu ...

  3. 让Maven支持代理

    1.如果你的公司架设了防火墙并设置了HTTP代理服务器来禁止你们直接连接互联网,那么Maven就无法通过代理自动下载依赖包. 为了让Maven能够工作,你需要在Maven的配置文件 settings. ...

  4. c扩展调用php的函数(调用实现php函数的c函数)

    上一次是写的c扩展调用c的标准函数,但是只能调用头文件中申明的函数,今天来说下c扩展调用实现php函数的c函数,比方说,c扩展要用到php中ip2long这个函数,但是c不可能去php中调用,肯定是去 ...

  5. Fedora20 优化体验

    玩了些许天的fedora系统,到底是加深了对于linux系统的了解 为了便于大家对于fedora系统支持,我将这些天对于fedora的一些不适之处及改进的策略进行了一下小总结.便于新手对于fedora ...

  6. 石子合并(四边形不等式优化dp) POJ1160

    该来的总是要来的———————— 经典问题,石子合并. 对于 f[i][j]= min{f[i][k]+f[k+1][j]+w[i][j]} From 黑书 凸四边形不等式:w[a][c]+w[b][ ...

  7. UVa 1401 (Tire树) Remember the Word

    d(i)表示从i开始的后缀即S[i, L-1]的分解方法数,字符串为S[0, L-1] 则有d(i) = sum{ d(i+len(x)) | 单词x是S[i, L-1]的前缀 } 递推边界为d(L) ...

  8. sql2005主从数据库同步配置

    网站规模到了一定程度之后,该分的也分了,该优化的也做了优化,但是还是不能满足业务上对性能的要求:这时候我们可以考虑使用主从库.主从库是两台服务器上的两个数据库,主库以最快的速度做增删改操作+最新数据的 ...

  9. Java [Leetcode 66]Plus One

    题目描述: Given a non-negative number represented as an array of digits, plus one to the number. The dig ...

  10. 省常中模拟 Test4

    prime 数论 题意:分别求 1*n.2*n.3*n.... n*n 关于模 p 的逆元.p 是质数,n < p. 初步解法:暴力枚举.因为 a 关于模 p 的逆元 b 满足 ab mod p ...