Python 小练习一

1.如果同一个ip地址60s之内访问超过200次，那么就把ip加入黑名单

需求分析：

1.60s读一次文件

2.分割，取第一个元素，ip地址

3.把所有ip加入到一个list里面，如果ip次数超过200次加入黑名单

import time

point = 0 # 文件指针

while True:

blk_set = set() # 定义空集合，存放需要加入黑名单的ip

ips = [] # 存放所有ip地址

with open('access.log') as f:

f.seek(point)

for line in f:

ip = line.split()[0]

ips.append(ip)

if ips.count(ip) > 200:

blk_set.add(ip)

for ip in blk_set: # 去重

print('已把%s加入黑名单' % ip)

point = f.tell()

time.sleep(60)

2.判断是否为小数

# 小数点的个数，小数点的个数是否等于1

# 按照小数点分割

def check_float(s):

s = str(s)

if s.count('.') == 1:

s_list = s.split('.')

# 1.2 [1, 2]

# -5.3 [-5, 4]

left = s_list[0]

right = s_list[1]

if left.isdigit() and right.isdigit(): # 正小数

return True

elif left.startswith('-') and left.count('-') == 1: # 负小数

if left.split('-')[-1].isdigit() and right.isdigit():

return True

return False

3.对比字典内容

dict1 = {

"version": "9.0.0",

"is_test": True,

"store": "",

"urs": "",

"device": {

"os": "android",

"ime1": "99001062198893",

"device_id": "CQliMWEyYTEzNTYyYzk5MzJmCTJlNmY3Zjkx",

"mac": "02:00:00:00:00:00",

"galaxy_tag": "CQliMWEyYTEzNTYyYzk5MzJmCTJlNmY3Zjkx",

"udid": "a34b1f67dd5797df93fdd8b072f1fb8110fd0db6",

"network_status": "wifi"

},

"adunit": {

"category": "VIDEO",

"location": "1",

"app": "7A16FBB6",

"blacklist": ""

},

"ext_param": {

"is_start": 0,

"vId": "VW0BRMTEV"

}

}

dict2 = {

"version": "9.0.0",

"is_test": True,

"urs": "",

"store": "",

"device": {

"os": "android",

"imei": "99001062298893",

"device_id": "CQliMWEyYTEzNTYyYzk5MzJmCTJlNmY3Zjkx",

"mac": "02:00:00:00:00:00",

"galaxy_tag": "CQliMWEyYTEzNTYyYzk5MzJmCTJlNmY3Zjkx",

"udid": "a34b1f67dd5797da93fdd8b072f1fb8110fd0db6",

"network_status": "wifi"

},

"adunit": {

"category": "VIDEO",

"location": "1",

"app": "7A16FBB6",

"blacklist": ""

}, "ext_param": {

"is_start": 0,

"vid": "VW0BRMTEV"

}

}

# 判断两个字典里面不一样的key，value

# 只需判断d1里面有

# 循环d1，通过key去d2里面取值

# 判断通过key取到的类型是什么，如果是字典的话，继续循环

# 然后再判断key和value

def compare(d1, d2):

for key in d1:

value1 = d1.get(key)

value2 = d2.get(key, '不存在')

if type(value1) == dict:

compare(value1, value2)

else:

if value1 != value2 and value2 == '不存在':

print('value不一样的key:%s，value1:%s，value2:%s' % (key, value1, value2))

res = set(d1.keys()).symmetric_difference(set(d2.keys())) # 对称差集，两个字典里面不一样的key

if res:

print('key不一样的是', ','.join(res))

compare(dict1, dict2)