React Router V4 正式版发布,该版本相较于前面三个版本有根本性变化,遵循 Just Component 的 API 设计理念。

本次升级的主要变更有:

  • 声明式 Declarative

  • 可组合 Composability

本次升级 React Router V4 吸取了 React 的理念:所有的东西都是 Component。因此 升级之后的 Route、Link、Switch……等都是一个普通的组件。

React Router V4 基于 Lerna 管理多个 Repository。在此代码库包括:

  • react-router React Router 核心

  • react-router-dom 用于 DOM 绑定的 React Router

  • react-router-native 用于 React Native 的 React Router

  • react-router-redux React Router 和 Redux 的集成

  • react-router-config 静态路由配置帮助助手

React Router V4 中文文档 React Router github

React Router V4发布的更多相关文章

  1. [Web 前端] React Router v4 入坑指南

    cp from : https://www.jianshu.com/p/6a45e2dfc9d9 万恶的根源 距离React Router v4 正式发布也已经过去三个月了,这周把一个React的架子 ...

  2. [React Router v4] Intercept Route Changes

    If a user has entered some input, or the current Route is in a “dirty” state and we want to confirm ...

  3. [React Router v4] Redirect to Another Page

    Overriding a browser's current location without breaking the back button or causing an infinite redi ...

  4. [React Router v4] Render Multiple Components for the Same Route

    React Router v4 allows us to render Routes as components wherever we like in our components. This ca ...

  5. [React Router v4] Conditionally Render a Route with the Switch Component

    We often want to render a Route conditionally within our application. In React Router v4, the Route ...

  6. [React Router v4] Render Catch-All Routes with the Switch Component

    There are many cases where we will need a catch-all route in our web applications. This can include ...

  7. [React Router v4] Render Nested Routes

    With React Router v4 the entire library is built as a series of React components. That means that cr ...

  8. [React Router v4] Parse Query Parameters

    React Router v4 ignores query parameters entirely. That means that it is up to you to parse them so ...

  9. [React Router v4] Use Regular Expressions with Routes

    We can use regular expressions to more precisely define the paths to our routes in React Router v4. ...

随机推荐

  1. 6.flume实战(三)※

    需求:将A服务器上的日志实时采集到B服务器上面去 大致原理: 技术选型: exec source + memory channel + avro sink avro source + memory c ...

  2. [ Openstack ] Openstack-Mitaka 高可用之 Dashboard

    目录 Openstack-Mitaka 高可用之 概述    Openstack-Mitaka 高可用之 环境初始化    Openstack-Mitaka 高可用之 Mariadb-Galera集群 ...

  3. slatstack Master的配置

    Salt系统非常简单并且易于配置,Salt系统的两个组件都有各自的配置文件.如"salt-master"是通过主配置文件来配置的,"salt-minion"是通 ...

  4. rest_framework 访问频率(节流)流程

    访问频率流程 访问频率流程与认证流程非常相似,只是后续操作稍有不同 当用发出请求时 首先执行dispatch函数,当执行当第二部时: #2.处理版本信息 处理认证信息 处理权限信息 对用户的访问频率进 ...

  5. Jstorm草草配置

    今天帮同事调试一个双节点的Jstorm测试集群. UI界面总是不能出现集群的具体信息. 参考几个URL调了一下.搞定了. 收获以下知识点: 1,UI是在storm.yaml里配置的 2,Jstorm分 ...

  6. elasticsearch中client.transport.sniff的使用方法和注意事项

    https://blog.csdn.net/J_bean/article/details/79507559

  7. C# axWindowsMediaPlayer制作播放器

    using System; using System.Collections.Generic; using System.ComponentModel; using System.Data; usin ...

  8. (十一)数组array

    变量:只能存一个值,数组可以存多个值 (1)普通数组,索引下标是整数: 1)定义: 方法一:一次赋一个值:语法:数组名[下标]=变量值 array[1]=linux array[2]=shell 方法 ...

  9. Codeforces 1023 D.Array Restoration-RMQ(ST)区间查询最值 (Codeforces Round #504 (rated, Div. 1 + Div. 2, based on VK Cup 2018 Fi)

    D. Array Restoration 这题想一下就会发现是只要两个相同的数之间没有比它小的就可以,就是保存一下数第一次出现和最后一次出现的位置,然后查询一下这个区间就可以,如果有0的话就进行填充. ...

  10. 一句话木马与caidao

    实验吧有个试验环境:http://www.shiyanbar.com/experiment-course/experiment-course/vid/1812 菜刀的主要功能是用来连接一句话木马的,a ...