React Router V4 正式版发布,该版本相较于前面三个版本有根本性变化,遵循 Just Component 的 API 设计理念。

本次升级的主要变更有:

  • 声明式 Declarative

  • 可组合 Composability

本次升级 React Router V4 吸取了 React 的理念:所有的东西都是 Component。因此 升级之后的 Route、Link、Switch……等都是一个普通的组件。

React Router V4 基于 Lerna 管理多个 Repository。在此代码库包括:

  • react-router React Router 核心

  • react-router-dom 用于 DOM 绑定的 React Router

  • react-router-native 用于 React Native 的 React Router

  • react-router-redux React Router 和 Redux 的集成

  • react-router-config 静态路由配置帮助助手

React Router V4 中文文档 React Router github

React Router V4发布的更多相关文章

  1. [Web 前端] React Router v4 入坑指南

    cp from : https://www.jianshu.com/p/6a45e2dfc9d9 万恶的根源 距离React Router v4 正式发布也已经过去三个月了,这周把一个React的架子 ...

  2. [React Router v4] Intercept Route Changes

    If a user has entered some input, or the current Route is in a “dirty” state and we want to confirm ...

  3. [React Router v4] Redirect to Another Page

    Overriding a browser's current location without breaking the back button or causing an infinite redi ...

  4. [React Router v4] Render Multiple Components for the Same Route

    React Router v4 allows us to render Routes as components wherever we like in our components. This ca ...

  5. [React Router v4] Conditionally Render a Route with the Switch Component

    We often want to render a Route conditionally within our application. In React Router v4, the Route ...

  6. [React Router v4] Render Catch-All Routes with the Switch Component

    There are many cases where we will need a catch-all route in our web applications. This can include ...

  7. [React Router v4] Render Nested Routes

    With React Router v4 the entire library is built as a series of React components. That means that cr ...

  8. [React Router v4] Parse Query Parameters

    React Router v4 ignores query parameters entirely. That means that it is up to you to parse them so ...

  9. [React Router v4] Use Regular Expressions with Routes

    We can use regular expressions to more precisely define the paths to our routes in React Router v4. ...

随机推荐

  1. 网络编程学习笔记--1.socket可读可写条件

    转至 :http://blog.csdn.net/majianfei1023/article/details/45788591 socket可读可写条件,经常做为面试题被问,因为它考察被面试者对网络编 ...

  2. selenium TestNG 依赖和忽略测试

    依赖:通过使用Test 注释的dependsOnMethods={"verifyLogin"}子句,verifyAccountInfo 测试指定了它依赖verifyLogin()方 ...

  3. Selenium2+python自动化67-用例失败自动截图【转载】

    前言: 装饰器其实就是一个以函数作为参数并返回一个替换函数的可执行函数 上一篇讲到用装饰器解决异常后自动截图,不过并没有与unittest结合,这篇把截图的装饰器改良了下,可以实现用例执行失败自动截图 ...

  4. onethink 插件模板定位

    <?php // +---------------------------------------------------------------------- // | OneThink [ ...

  5. python 输入 与如何查看文档 小结

    Python 2 中的输入小结 转载请声明本文的引用出处:仰望大牛的小清新 1.raw_input(prompt = None)与input(prompt = None) 两个都是默认参数类型,这个参 ...

  6. UVALive - 3211 (2-SAT + 二分)

    layout: post title: 训练指南 UVALive - 3211 (2-SAT + 二分) author: "luowentaoaa" catalog: true m ...

  7. 设计模式-设计原则(Design Principle)

    本文由@呆代待殆原创,转载请注明出处. 写在前面:所谓设计原则并不是一定要遵守的法则,只是一种建议,因为保持这些原则本身会有一定代价,若是这些代价超过了带来的好处就得不偿失了,所以一切还是以简单为准. ...

  8. AtCoder - 2061 Tree Restoring

    Problem Statement Aoki loves numerical sequences and trees. One day, Takahashi gave him an integer s ...

  9. Codeforces 786C Till I Collapse(树状数组+扫描线+倍增)

    [题目链接] http://codeforces.com/contest/786/problem/C [题目大意] 给出一个数列,问对于不同的k,将区间划分为几个, 每个区间出现不同元素个数不超过k时 ...

  10. python3开发进阶-Djamgo框架中的JSON和AJAX

    阅读目录 什么是JSON 什么是AJAX AJAX常见的应用情景 jQery实现AJAX AJAX请求如何设置csrf_token AJAX上传文件 补充Django内置的serializers 一. ...