[LeetCode&Python] Problem 383. Ransom Note
Given an arbitrary ransom note string and another string containing letters from all the magazines, write a function that will return true if the ransom note can be constructed from the magazines ; otherwise, it will return false.
Each letter in the magazine string can only be used once in your ransom note.
Note:
You may assume that both strings contain only lowercase letters.
canConstruct("a", "b") -> false
canConstruct("aa", "ab") -> false
canConstruct("aa", "aab") -> true
from collections import Counter
class Solution(object):
def canConstruct(self, ransomNote, magazine):
"""
:type ransomNote: str
:type magazine: str
:rtype: bool
"""
c=Counter(magazine)
for i in ransomNote:
if c[i]==0 or i not in c:
return False
else:
c[i]-=1
return True
[LeetCode&Python] Problem 383. Ransom Note的更多相关文章
- 383. Ransom Note【easy】
383. Ransom Note[easy] Given an arbitrary ransom note string and another string containing letters f ...
- 【LeetCode】383. Ransom Note 解题报告(Java & Python)
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 Java解法 Python解法 日期 [LeetCo ...
- leetcode 383. Ransom Note
Given an arbitrary ransom note string and another string containing letters from all th ...
- leetcode修炼之路——383. Ransom Note
题目是这样的 Given an arbitrary ransom note string and another string containing letters from a ...
- 14. leetcode 383. Ransom Note
Given an arbitrary ransom note string and another string containing letters from all the magazines, ...
- Java [Leetcode 383]Ransom Note
题目描述: Given an arbitrary ransom note string and another string containing letters from al ...
- LeetCode: 383 Ransom Note(easy)
题目: Given an arbitrary ransom note string and another string containing letters from all the magazin ...
- 383. Ransom Note
Given an arbitrary ransom note string and another string containing letters from all th ...
- 383. Ransom Note 在字典数组中查找笔记数组
[抄题]: Given an arbitrary ransom note string and another string containing letters from all the magaz ...
随机推荐
- Python print打印
1.Python运算符: +:加 -:减 *:乘 /:除以 %:去除法后的余数 //:取整除 2.字符串center方法: a='111'print(a.center(4,'2')) #让字符串占位 ...
- ubuntu 双硬盘挂载 windows分区自动挂载
sudo fdisk -l 查看硬盘情况 1:新建一个目录,例:old 2:mount /dev/sdb1 old 3:cd old 4:ls (就可以看到新硬盘的内容了) 取消挂载:umoun ...
- Cyclic Components CodeForces - 977E(DFS)
Cyclic Components CodeForces - 977E You are given an undirected graph consisting of nn vertices and ...
- laravel处理菜单保持的方法:
<!-- 左侧菜单区域 --> <div class="col-md-3"> @section('leftmenu') <div class=&quo ...
- learning ddr3 protocol
refercece: www.jedec.org https://www.cnblogs.com/zhongguo135/p/8486979.html :
- java字符串根据空格截取并存进ArrayList,并在每个元素前后加上/
public class List { public static void main(String[] args) { String s = "abc nnn ooo/xzsxc bs&q ...
- eclipse.ini参数配置
-vmD:/jdk1.6/Java/jdk1.6.0_45/bin/javaw.exe-vmargs-Xms1024m-Xmx1024m-XX:MaxPermSize=1024m-XX:Reserve ...
- 【资料搜集】DirectX学习
[网站推荐:]GameRes游资网-游戏开发者门户 http://www.gameres.com/ [基础知识:] <游戏编程>第一部 基础篇 - GameRes.com http://d ...
- sublime text3 常用配置
. 打开Preferences菜单,并选择 Browse Packages… . 系统会打开Sublime Text 的Packages文件夹,回到上一级菜单,然后打开Installed Packag ...
- 第二节 java流程控制(循环结构)
1.for循环 for(初始化表达式;循环条件表达式;循环后的操作表达式){ 执行语句 } 2.while循环 while(条件表达式){ 执行语句 } while循环特点是只有条件满足才会执行我们 ...