http://www.cbcb.umd.edu/software/jellyfish/
 
http://www.genome.umd.edu/jellyfish.html
https://github.com/gmarcais/Jellyfish/releases
 
 
wget https://github.com/gmarcais/Jellyfish/releases/download/v2.2.3/jellyfish-2.2.3-CentOS6.tar.gz
tar -zxvf jellyfish-2.2.3-CentOS6.tar.gz
 
jellyfish就在bin里面,直接将这个可执行程序复制到你的环境变量目录里就可以用了
服务器安装包地址:
/home/cmiao/jellyfish-2.2.3
 
 
 
 
 
jellyfish不能用fq.gz 要先转为fq才行
用gunzip -c *.fq.gz > *.fq 
 
$ jellyfish count -t 30 -C -m 21 -s 150G  --min-quality=20 --quality-start=33 ./*.fastq
 
Assume a haploid genome, for simplicity. In the picture provided, the first peak at depth ~31 indicates amount of 1-copy content (in other words, the genome has exactly 1 copy of that kmer, so it is unique). The weak peak at ~62x indicates the amount of 2-copy content. Everything under ~11x can be assumed to be error kmers, unrelated to genome size.

So, to estimate manually, take the sum of the counts of unique kmers under the first peak and multiply by 1; add the sum of the counts of unique kmers under the peak at 2x the depth of the first peak and multiply by 2; etc, for all peaks. This will give you the haploid genome size. So if your genome is tetraploid, the actual size will be 1/4 of your result, since the first peak will correspond to mutations present on only 1 ploidy (1/0/0/0 genotype).

You can make this more accurate by modelling the peaks as a sum of Gaussian curves, but that probably won't change the result much. Of course, this method is subjective because calling peaks is subjective.

Please note - I think 17-mers are too short for this kind of analysis. I prefer 31-mers because they are the longest computationally-efficient kmers. Also, FYI, BBNorm is faster than Jellyfish and can also generate kmer-frequency histograms:

khist.sh in=reads.fq hist=khist.txt

Also, it makes more sense to plot these things as log-log rather than linear-linear; and the Y-axis should be count, not frequency, which is useless for the purpose of genome-size estimation.
 

Outline

  1. count k-mer occurence using Jellyfish (jellyfish count)
  2. summarize as histogram (jellyfish histo)
  3. plot graph with R
  4. determine the total number of k-mer analyzed and the peak position
  5. compare the peak shape with poisson distribution

Count k-mer occurence

In this example we have 5 pair of fastq files in three different subdirectories. The file to process can be specified with "*/*.qf.fastq" and veriied with ls.

$ ls */*.qf.fastq
run1/s_1_1_sequence.qf.fastq  run2/s_2_2_sequence.qf.fastq
run1/s_1_2_sequence.qf.fastq  run3/s_1_1_sequence.qf.fastq
run2/s_1_1_sequence.qf.fastq  run3/s_1_2_sequence.qf.fastq
run2/s_1_2_sequence.qf.fastq  run3/s_2_1_sequence.qf.fastq
run2/s_2_1_sequence.qf.fastq  run3/s_2_2_sequence.qf.fastq

Next, we issue the jellyfish count command

jellyfish count -t 8 -C -m 25 -s 5G -o spec1_25mer --min-quality=20 --quality-start=33 */*.qf.fastq
-t 8
specifies the number of threads to be used. This value should be equal to the number of cores on the machine or the number of slots you reserved through job management system ($NSLOTS in SGE or UGE).
-C
specifies the both strands are considered. If you do not specify this, the apparent depth would be half, --- that is undesirable
-m 25
specified that now you are counting for 25 mer (i.e., k=25)
-s 5G
is some kind of magical number specification of hash size. This should be as high as the physical memory allows. The higher the faster, but exceeding the available memory leads to failure or extremely slow counting.
-o spec1_25mer
specifies the prefix of output file names.
--quality-start=33
specified that your fastq file have 33 based quality value string. Be careful on the dataformat. There are cases that your data are 64 based depending on the sequending system and software versions. This is relevant only when you specify --min-quality
--min-quality=20
specifies that nucleotide having qv lower than 20 should not included in the count. This selection reduces the k-mers derived from sequence errors and make the peak clearer.
*/*.qf.fastq
will be expanded to the ten filenames explained above by the shell and passed to jellyfish as input files

summarize as histogram (jellyfish histo)

First confirm that you got the output file

$ ls spec1_25mer*
spec1_25mer_0

now that there is a single file spec1_25mer_0

$ jellyfish histo -o spec1_25mer.histo spec1_25mer_0

Confirm that you got the output

$ ls spec1_25mer*
spec1_25mer_0  spec1_25mer.histo

Examine the numbers by your eyes

$ head -25 spec1_25mer.histo
1 461938583
2 95606044
3 19280477
4 13836754
5 11018480
6 9555090
7 8557935
8 7863244
9 7319505
10 6920880
11 6589723
12 6321923
13 6148638
14 6036120
15 5972264
16 5962234
17 5987696
18 6051171
19 6154429
20 6297373
21 6485135
22 6700579
23 6932570
24 7217627
25 7533211
 
 
运行出错:
terminate called after throwing an instance of 'jellyfish::invertible_hash::ErrorAllocation'
  what():  Failed to allocate 628292358736 bytes of memory
Aborted (core dumped)
解决:
50G should be more than enough. That is the amount of memory I usually am using and I have never had any problems. This also means that you probably do not need the high memory nodes.
 
 
 
 
 
freemao
FAFU

jellyfish K-mer analysis and genome size estimate的更多相关文章

  1. Evaluate|GC content|Phred|BAC|heterozygous single nucleotide polymorphisms|estimate genome size|

    (Evaluate):检查reads,可使用比对软件:使用SOAPaligner重新排列:采用massively parallel next-generation sequencing technol ...

  2. Maximum Size Subarray Sum Equals k -- LeetCode

    Given an array nums and a target value k, find the maximum length of a subarray that sums to k. If t ...

  3. 【LeetCode】325. Maximum Size Subarray Sum Equals k 解题报告 (C++)

    作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 prefix Sum 日期 题目地址:https:// ...

  4. The sequence and de novo assembly of the giant panda genome.ppt

    sequencing:使用二代测序原因:高通量,短序列 不用长序列原因: 1.算法错误率高 2.长序列测序将嵌合体基因错误积累.嵌合体基因:通过重组由来源与功能不同的基因序列剪接而形成的杂合基因 se ...

  5. [LeetCode] Longest Substring with At Least K Repeating Characters 至少有K个重复字符的最长子字符串

    Find the length of the longest substring T of a given string (consists of lowercase letters only) su ...

  6. [LeetCode] Kth Largest Element in an Array 数组中第k大的数字

    Find the kth largest element in an unsorted array. Note that it is the kth largest element in the so ...

  7. k近邻算法的Java实现

    k近邻算法是机器学习算法中最简单的算法之一,工作原理是:存在一个样本数据集合,即训练样本集,并且样本集中的每个数据都存在标签,即我们知道样本集中每一数据和所属分类的对应关系.输入没有标签的新数据之后, ...

  8. 6.3Sum && 4Sum [ && K sum ] && 3Sum Closest

    3Sum Given an array S of n integers, are there elements a, b, c in S such that a + b + c = 0? Find a ...

  9. 剑指offer系列55---最小的k个数

    [题目] 输入n个整数,找出其中最小的K个数.例如输入4,5,1,6,2,7,3,8这8个数字,则最小的4个数字是1,2,3,4,. *[思路]排序,去除k后的数. package com.exe11 ...

随机推荐

  1. CPU信息查询

    cat /proc/cpuinfo |grep "physical id"|sort |uniq|wc -l //查看CPU的个数 cat /proc/cpuinfo |grep ...

  2. 一些qml资料

    qml开发ios应用 http://www.seanyxie.com/qt-qml%E7%A7%BB%E5%8A%A8%E5%BC%80%E5%8F%91%E4%B9%8B%E5%9C%A8ios%E ...

  3. HTML元素,属性,基础标签

    元素,属性 元素 html有父元素和子元素,被包含的叫子元素,如html是head的父元素,他们是父子关系,head和body是兄弟关系 <html> <head></h ...

  4. MySQL存储过程之事务管理

    原文链接:http://hideto.iteye.com/blog/195275 MySQL存储过程之事务管理 ACID:Atomic.Consistent.Isolated.Durable 存储程序 ...

  5. [转载]java NIO详解

    Java NIO(New IO)是从Java 1.4版本开始引入的一个新的IO API,可以替代标准的Java IO API.下面的文章写的很详细,还配有插图,有助于深入学习和理解java NIO 文 ...

  6. js 替换 当前URL 特定参数

    js 替换 当前URL 特定参数 2012-12-24 20:45:53|  分类: JS&JQuery |举报 |字号 订阅   //替换指定传入参数的值,paramName为参数,repl ...

  7. (转载)Java基础知识总结

    写代码: 1,明确需求.我要做什么? 2,分析思路.我要怎么做?1,2,3. 3,确定步骤.每一个思路部分用到哪些语句,方法,和对象. 4,代码实现.用具体的java语言代码把思路体现出来. 学习新技 ...

  8. arm-linux-gcc-4.3.2安装步骤

        安装交叉编译工具链: 1.首先以root用户登入 2.复制arm-linux-gcc-4.3.2.tgz到根目录下tmp文件夹里 3.解压命令tar xvzf arm-linux-gcc-4. ...

  9. Hibernate中的多对多映射

    1.需求 项目与开发员工 一个项目,有多个开发人员 一个开发人员,参与多个项目 [多对多] 2.实体bean设计 Project: public class Project { private int ...

  10. HDU 1098 Ignatius's puzzle 费马小定理+扩展欧几里德算法

    题目大意: 给定k,找到一个满足的a使任意的x都满足 f(x)=5*x^13+13*x^5+k*a*x 被65整除 推证: f(x) = (5*x^12 + 13 * x^4 + ak) * x 因为 ...