http://www.cbcb.umd.edu/software/jellyfish/
 
http://www.genome.umd.edu/jellyfish.html
https://github.com/gmarcais/Jellyfish/releases
 
 
wget https://github.com/gmarcais/Jellyfish/releases/download/v2.2.3/jellyfish-2.2.3-CentOS6.tar.gz
tar -zxvf jellyfish-2.2.3-CentOS6.tar.gz
 
jellyfish就在bin里面,直接将这个可执行程序复制到你的环境变量目录里就可以用了
服务器安装包地址:
/home/cmiao/jellyfish-2.2.3
 
 
 
 
 
jellyfish不能用fq.gz 要先转为fq才行
用gunzip -c *.fq.gz > *.fq 
 
$ jellyfish count -t 30 -C -m 21 -s 150G  --min-quality=20 --quality-start=33 ./*.fastq
 
Assume a haploid genome, for simplicity. In the picture provided, the first peak at depth ~31 indicates amount of 1-copy content (in other words, the genome has exactly 1 copy of that kmer, so it is unique). The weak peak at ~62x indicates the amount of 2-copy content. Everything under ~11x can be assumed to be error kmers, unrelated to genome size.

So, to estimate manually, take the sum of the counts of unique kmers under the first peak and multiply by 1; add the sum of the counts of unique kmers under the peak at 2x the depth of the first peak and multiply by 2; etc, for all peaks. This will give you the haploid genome size. So if your genome is tetraploid, the actual size will be 1/4 of your result, since the first peak will correspond to mutations present on only 1 ploidy (1/0/0/0 genotype).

You can make this more accurate by modelling the peaks as a sum of Gaussian curves, but that probably won't change the result much. Of course, this method is subjective because calling peaks is subjective.

Please note - I think 17-mers are too short for this kind of analysis. I prefer 31-mers because they are the longest computationally-efficient kmers. Also, FYI, BBNorm is faster than Jellyfish and can also generate kmer-frequency histograms:

khist.sh in=reads.fq hist=khist.txt

Also, it makes more sense to plot these things as log-log rather than linear-linear; and the Y-axis should be count, not frequency, which is useless for the purpose of genome-size estimation.
 

Outline

  1. count k-mer occurence using Jellyfish (jellyfish count)
  2. summarize as histogram (jellyfish histo)
  3. plot graph with R
  4. determine the total number of k-mer analyzed and the peak position
  5. compare the peak shape with poisson distribution

Count k-mer occurence

In this example we have 5 pair of fastq files in three different subdirectories. The file to process can be specified with "*/*.qf.fastq" and veriied with ls.

$ ls */*.qf.fastq
run1/s_1_1_sequence.qf.fastq  run2/s_2_2_sequence.qf.fastq
run1/s_1_2_sequence.qf.fastq  run3/s_1_1_sequence.qf.fastq
run2/s_1_1_sequence.qf.fastq  run3/s_1_2_sequence.qf.fastq
run2/s_1_2_sequence.qf.fastq  run3/s_2_1_sequence.qf.fastq
run2/s_2_1_sequence.qf.fastq  run3/s_2_2_sequence.qf.fastq

Next, we issue the jellyfish count command

jellyfish count -t 8 -C -m 25 -s 5G -o spec1_25mer --min-quality=20 --quality-start=33 */*.qf.fastq
-t 8
specifies the number of threads to be used. This value should be equal to the number of cores on the machine or the number of slots you reserved through job management system ($NSLOTS in SGE or UGE).
-C
specifies the both strands are considered. If you do not specify this, the apparent depth would be half, --- that is undesirable
-m 25
specified that now you are counting for 25 mer (i.e., k=25)
-s 5G
is some kind of magical number specification of hash size. This should be as high as the physical memory allows. The higher the faster, but exceeding the available memory leads to failure or extremely slow counting.
-o spec1_25mer
specifies the prefix of output file names.
--quality-start=33
specified that your fastq file have 33 based quality value string. Be careful on the dataformat. There are cases that your data are 64 based depending on the sequending system and software versions. This is relevant only when you specify --min-quality
--min-quality=20
specifies that nucleotide having qv lower than 20 should not included in the count. This selection reduces the k-mers derived from sequence errors and make the peak clearer.
*/*.qf.fastq
will be expanded to the ten filenames explained above by the shell and passed to jellyfish as input files

summarize as histogram (jellyfish histo)

First confirm that you got the output file

$ ls spec1_25mer*
spec1_25mer_0

now that there is a single file spec1_25mer_0

$ jellyfish histo -o spec1_25mer.histo spec1_25mer_0

Confirm that you got the output

$ ls spec1_25mer*
spec1_25mer_0  spec1_25mer.histo

Examine the numbers by your eyes

$ head -25 spec1_25mer.histo
1 461938583
2 95606044
3 19280477
4 13836754
5 11018480
6 9555090
7 8557935
8 7863244
9 7319505
10 6920880
11 6589723
12 6321923
13 6148638
14 6036120
15 5972264
16 5962234
17 5987696
18 6051171
19 6154429
20 6297373
21 6485135
22 6700579
23 6932570
24 7217627
25 7533211
 
 
运行出错:
terminate called after throwing an instance of 'jellyfish::invertible_hash::ErrorAllocation'
  what():  Failed to allocate 628292358736 bytes of memory
Aborted (core dumped)
解决:
50G should be more than enough. That is the amount of memory I usually am using and I have never had any problems. This also means that you probably do not need the high memory nodes.
 
 
 
 
 
freemao
FAFU

jellyfish K-mer analysis and genome size estimate的更多相关文章

  1. Evaluate|GC content|Phred|BAC|heterozygous single nucleotide polymorphisms|estimate genome size|

    (Evaluate):检查reads,可使用比对软件:使用SOAPaligner重新排列:采用massively parallel next-generation sequencing technol ...

  2. Maximum Size Subarray Sum Equals k -- LeetCode

    Given an array nums and a target value k, find the maximum length of a subarray that sums to k. If t ...

  3. 【LeetCode】325. Maximum Size Subarray Sum Equals k 解题报告 (C++)

    作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 prefix Sum 日期 题目地址:https:// ...

  4. The sequence and de novo assembly of the giant panda genome.ppt

    sequencing:使用二代测序原因:高通量,短序列 不用长序列原因: 1.算法错误率高 2.长序列测序将嵌合体基因错误积累.嵌合体基因:通过重组由来源与功能不同的基因序列剪接而形成的杂合基因 se ...

  5. [LeetCode] Longest Substring with At Least K Repeating Characters 至少有K个重复字符的最长子字符串

    Find the length of the longest substring T of a given string (consists of lowercase letters only) su ...

  6. [LeetCode] Kth Largest Element in an Array 数组中第k大的数字

    Find the kth largest element in an unsorted array. Note that it is the kth largest element in the so ...

  7. k近邻算法的Java实现

    k近邻算法是机器学习算法中最简单的算法之一,工作原理是:存在一个样本数据集合,即训练样本集,并且样本集中的每个数据都存在标签,即我们知道样本集中每一数据和所属分类的对应关系.输入没有标签的新数据之后, ...

  8. 6.3Sum && 4Sum [ && K sum ] && 3Sum Closest

    3Sum Given an array S of n integers, are there elements a, b, c in S such that a + b + c = 0? Find a ...

  9. 剑指offer系列55---最小的k个数

    [题目] 输入n个整数,找出其中最小的K个数.例如输入4,5,1,6,2,7,3,8这8个数字,则最小的4个数字是1,2,3,4,. *[思路]排序,去除k后的数. package com.exe11 ...

随机推荐

  1. POJ 3687 逆序拓扑

    额.题目大意:有N个球.编号和重量都是唯一不重复的.然后.给你m个pair a和b,表示编号为a的点一定比编号为b的点轻.然后捏.输出每个点对应的重量.关键是要求.如果有多种可能性的话,输出让序号小的 ...

  2. mysql的部分命令图解

    1.查询有哪些库: show databases;  图中除了Carlton库之外,其它都是系统自带的. 要养成在命令后加入:的习惯 2.查看某个库的表 show tables; 3. 查看表的字段 ...

  3. VBA读取固定文件夹中txt内容

    Sub OneTxt() '打开一个txt文件 Dim Filename As Variant, extLine&, mArr() As String Dim i%, j%, txtpath ...

  4. 关于JavaScript是否会阻塞图片加载

    <?php //1.js.php sleep(5); file_put_contents("tmp.txt", __FILE__.'->'.__LINE__.' -&g ...

  5. hdu 4630 No Pain No Game

    http://acm.hdu.edu.cn/showproblem.php?pid=4630 离散化+树状数组 将数组 *a  从后向前遍历 遍历到 a[x] 的时候 再枚举a[x]的约数 假如 约数 ...

  6. Android Phonebook编写联系人UI加载及联系人保存流程(二)

    2014-01-06 17:18:29 1. Phonebook中新建/编辑联系人的UI不是用xml文件写的,它是随着帐号类型的改变来加载不同的UI,比如SIM联系人,只有Name.Phone Num ...

  7. Rhel6-heartbeat配置文档

    系统环境: rhel6 x86_64 iptables and selinux disabled 主机: 192.168.122.119 server19.example.com 192.168.12 ...

  8. UVA 10970-Big Chocolate

    题目: 给你一块M*N的巧克力,问把它切成最小单元需要最少切几刀,分开的就不能一起切了. 分析: 每次切割只能多产生一个部分,分成M*N个部分,必然要切M*N-1刀. 一个长为m宽为n的长方形和m*n ...

  9. Android 移动缩放的ImageView

    今天介绍一下Android中怎么实现ImageView的缩放和移动,自定义TouchImageView. public class TouchImageView extends ImageView { ...

  10. 另类加载dll---快捷方式启动参数

    http://blogs.360.cn/360safe/2014/08/29/cnc_trojan_and_fake_proto/ 原文: BMP1和BMP2是两个lnk文件(快捷方式),我们知道bm ...