Leetcode 203 Remove Linked List Elements 链表

去掉链表中相应的元素值

 /**
  * Definition for singly-linked list.
  * struct ListNode {
  *     int val;
  *     ListNode *next;
  *     ListNode(int x) : val(x), next(NULL) {}
  * };
  */
 class Solution {
 public:
     ListNode* removeElements(ListNode* head, int val) {
         if(!head) return NULL;
         ListNode* now = head;
         for(;now->next ;){
             if(now->next->val == val){
                 ListNode* next = now->next;
                 now->next = next->next;
                 delete next;
             }
             else  now = now->next;
         }
         if(head->val == val) {
             ListNode* t = head;
             head = head->next;
             delete t;
         }
         return head;
     }
 };