[ACM_模拟] ACM - Draw Something Cheat [n个长12的大写字母串,找出交集,按字母序输出]
Description
Have you played Draw Something? It's currently one of the hottest social drawing games on Apple iOS and Android Devices! In this game, you and your friend play in turn. You need to pick a word and draw a picture for this word. Then your friend will be asked what the word is, given the picture you have drawn. The following figure illustrates a typical scenario in guessing the word.

As you see, when guessing a word you will be given the picture and 12 letters. You must pick some of these letters to form a word that matches the picture. Each letter can only be used once. It is a lot of fun if your friend is a talented painter, but unfortunately some drawings from your friend are totally incomprehensible. After several times of becoming mad by the drawings, you find a way to cheat in the game.
In this game, letters not included in the correct answer are randomly generated. If you cannot find the correct answer when guessing, you can write down all the letters and restart the game. Then you would find some of these letters are changed. Of course these changed letters will never appear in the answer. By eliminating these letters you are a step closer to the answer.
So In this problem, you need to write a program to automate the cheating process. Given N strings of letters to the same picture, you need to eliminate as many letters as possible, and output the remaining letters.
Input
There are multiple test cases. The first line of the input is an integer T ≈ 1000 indicating the number of test cases.
Each test case begins with a positive integer N ≤ 20 indicating the number of times you have entered the game. Then N lines follow. Each line is a string of exactly 12 uppercase letters, indicating the candidate letters in one guess. It is guaranteed that the answer has at least 1 letter and has no more than 12 letters.
Output
For each test case, output the remaining letters in alphabet order after the process described above. One line for each test case.
Sample Input
2
2
ABCDEFGHIJKL
ABCDEFGHIJKL
2
SAWBCVUXDTPN
ZQTLFJYRCGAK
Sample Output
ABCDEFGHIJKL
ACT 题目大意:第一个T表示有T组,每组一个n表示接下来n个长为12的string,求这些string的交集并安字典序输出。
解题思路:用num_ABC[26]表示交集,用temp_num[26]表示每个string的情况,这里26表示26个大写字母,数组的值表示含该字母的数量
#include<iostream>
#include<string.h>
#include<cstring>
#include<string>
using namespace std;
int main(){
int T;cin>>T;
while(T--){
int num_ABC[];//交集
int temp_num[];//每个string的情况
string str;int n;
cin>>n;
for(int i=;i<;i++)num_ABC[i]=;//初始化很大的
while(n--){//n个string过来
cin>>str;
memset(temp_num,,sizeof(temp_num));
for(int i=;i<;i++){
temp_num[str[i]-'A']++;
}//统计
for(int i=;i<;i++)if(num_ABC[i]>temp_num[i]){
num_ABC[i]=temp_num[i];
}//更新交集
}
for(int i=;i<;i++){//输出
while(num_ABC[i]--){
cout<<(char)(i+'A');
}
}cout<<'\n';
}return ;
}
[ACM_模拟] ACM - Draw Something Cheat [n个长12的大写字母串,找出交集,按字母序输出]的更多相关文章
- zjuoj 3603 Draw Something Cheat
http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3603 Draw Something Cheat Time Limit: 2 ...
- The 9th Zhejiang Provincial Collegiate Programming Contest->Problem D:D - Draw Something Cheat
http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemCode=3603 题意:在给出的字符串中找出每行都出现的字母按字典序排序. #incl ...
- [ACM_模拟] POJ1068 Parencodings (两种括号编码转化 规律 模拟)
Description Let S = s1 s2...s2n be a well-formed string of parentheses. S can be encoded in two diff ...
- ACM_查找ACM(加强版)
查找ACM(加强版) Time Limit: 2000/1000ms (Java/Others) Problem Description: 作为一个acmer,应该具备团队合作能力和分析问题能力.给你 ...
- [ZOJ 3063] Draw Something Cheat
题目链接:http://acm.zju.edu.cn/onlinejudge/showProblem.do?problemId=4706 思路:字符串是一个集合(由0到多个A~Z字符组成),我们可以假 ...
- Linux下使用USB模拟ACM串口设备
这个想法之前就在脑袋里有过,最近公司产品要用到,所以多做了些了解. 1. USB 简介 USB 是 Universal Serial Bus 的缩写,从字面上看,就是通用串行总线的意思.从物理上看,其 ...
- [ACM_模拟][ACM_数学] LA 2995 Image Is Everything [由6个视图计算立方体最大体积]
Description Your new company is building a robot that can hold small lightweight objects. The robo ...
- [ACM_模拟] UVA 10881 Piotr's Ants[蚂蚁移动 数组映射 排序技巧]
"One thing is for certain: there is no stopping them;the ants will soon be here. And I, for one ...
- [ACM_模拟][ACM_暴力] Lazier Salesgirl [暴力 懒销售睡觉]
Description Kochiya Sanae is a lazy girl who makes and sells bread. She is an expert at bread making ...
随机推荐
- MYSQL服务器字符集设置
修改默认字符集 vi /etc/my.cnf 在[mysqld]下面加入default-character-set=utf8 在[client]下面加入default-character-set=ut ...
- 禅道Linux一键安装版
禅道Linux一键安装版 Linux一键安装包内置了apache, php, mysql这些应用程序,只需要下载解压缩即可运行禅道.从7.3版本开始,linux一键安装包分为32位和64位两个包,大家 ...
- 采用formdata做跨域的、无刷新、带进度条的文件上传
以前做无刷新上传,都要用iframe,如果想有进度条,就千难万难,不得不用flash等插件来实现. 现在HTML5终于普及了,筒子们不用再那么痛苦了. 所有这一切都变得异常简单!! 不信?且看如下代码 ...
- Scrum会议10.19
Scrum会议 组名称:好好学习 项目名称:记账本 参会成员:林莉(Master)胡丽娜 宫丽君 汪东涵 时间:2016.10.19 已完成内容: 1.完成新项目的查找,查找学姐的代码和项目. 2.理 ...
- 【随笔】ssh登录时如何直接在参数中加入登录密码
如同apt-get安装程序时会有-y参数来避免交互输入一样,我也希望在ssh登录时能够直接附加登录密码以避免交互式输入密码这一步,网上找了找,方法很多. 比如直接通过密钥免密码登录,不过需要改动很多, ...
- python命令行参数
〇.python中对应的argc, argv需要模块:sys参数个数:len(sys.argv)脚本名: sys.argv[0]参数1: sys.argv[1]参数2: sys. ...
- OA项目之导入
内容显示页: protected void btnIMP_Click(object sender, EventArgs e) { Response.Redire ...
- tar 打包命令
Usage: tar -[cxtzjhmvO] [-X FILE] [-T FILE] [-f TARFILE] [-C DIR] [FILE]... Create, extract, or list ...
- python 高阶函数与装饰器
高阶函数定义1.函数接收的参数是一个函数名2.函数的返回值是一个函数名以上两者满足任意一个,就是高阶函数装饰器定义本质就是函数,功能是为其他函数添加新功能 装饰器的原则 1.不修改被装饰函数的源代码( ...
- TextFile 类的创写
TextFile 作为自写的方法,继承自List<String>.像统计文本中出现的哪些单词,不重复等等,适合用Set集合完成统计. class TextFile extends Arra ...