Codeforces 799D. String Game 二分
Little Nastya has a hobby, she likes to remove some letters from word, to obtain another word. But it turns out to be pretty hard for her, because she is too young. Therefore, her brother Sergey always helps her.
Sergey gives Nastya the word t and wants to get the word p out of it. Nastya removes letters in a certain order (one after another, in this order strictly), which is specified by permutation of letters' indices of the word t: a1... a|t|. We denote the length of word x as |x|. Note that after removing one letter, the indices of other letters don't change. For example, if t = "nastya" and a = [4, 1, 5, 3, 2, 6] then removals make the following sequence of words "nastya"
"nastya"
"nastya"
"nastya"
"nastya"
"nastya"
"nastya".
Sergey knows this permutation. His goal is to stop his sister at some point and continue removing by himself to get the word p. Since Nastya likes this activity, Sergey wants to stop her as late as possible. Your task is to determine, how many letters Nastya can remove before she will be stopped by Sergey.
It is guaranteed that the word p can be obtained by removing the letters from word t.
The first and second lines of the input contain the words t and p, respectively. Words are composed of lowercase letters of the Latin alphabet (1 ≤ |p| < |t| ≤ 200 000). It is guaranteed that the word p can be obtained by removing the letters from word t.
Next line contains a permutation a1, a2, ..., a|t| of letter indices that specifies the order in which Nastya removes letters of t (1 ≤ ai ≤ |t|, all ai are distinct).
Print a single integer number, the maximum number of letters that Nastya can remove.
ababcba
abb
5 3 4 1 7 6 2
3
bbbabb
bb
1 6 3 4 2 5
4
In the first sample test sequence of removing made by Nastya looks like this:
"ababcba"
"ababcba"
"ababcba"
"ababcba"
Nastya can not continue, because it is impossible to get word "abb" from word "ababcba".
So, Nastya will remove only three letters.
题目链接:http://codeforces.com/contest/779/problem/D
题意:有2个字符串a,b。将a按照顺序删除,问a最多删除多少个字母后,依然包含b。保证数据有效,即一定有结果。
思路:二分。将a要删除的个数进行二分,每次二分后暴力寻找。时间复杂度为n*16.注意二分的姿势。
代码:
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
#include<algorithm>
using namespace std;
const int MAXN=2e5+;
char a[MAXN],b[MAXN];
int t[MAXN];
int main()
{
scanf("%s%s",a,b);
int n=strlen(a),m=strlen(b);
for(int i=; i<=n; i++)
{
int x;
scanf("%d",&x);
t[x-]=i;
}
int l=,r=n;
int ans=;
while(l<=r)
{
int mid=(l+r)/;
int i=,j=;
int flag=;
for(i=; i<n; i++)
{
if(t[i]<=mid) continue;
if(a[i]==b[j]) j++;
if(j==m) flag=;
}
if(flag==) l=mid+,ans=mid;
else r=mid-;
}
cout<<ans<<endl;
return ;
}
二分
Codeforces 799D. String Game 二分的更多相关文章
- [Codeforces 1199C]MP3(离散化+二分答案)
[Codeforces 1199C]MP3(离散化+二分答案) 题面 给出一个长度为n的序列\(a_i\)和常数I,定义一次操作[l,r]可以把序列中<l的数全部变成l,>r的数全部变成r ...
- codeforces D. Mahmoud and Ehab and the binary string(二分)
题目链接:http://codeforces.com/contest/862/submission/30696399 题解:这题一看操作数就知道是二分答案了.然后就是怎么个二分法,有两种思路第一种是找 ...
- CodeForces 779D. String Game(二分答案)
题目链接:http://codeforces.com/problemset/problem/779/D 题意:有两个字符串一个初始串一个目标串,有t次机会删除初始串的字符问最多操作几次后刚好凑不成目标 ...
- Codeforces Round #402 D String Game(二分)
[题目类型]二分答案 &题解: 只要你想到二分答案就不是难题了,但我当时确实是想不到. [时间复杂度]\(O(nlogn)\) &代码: #include <cstdio> ...
- CodeForces - 779D String Game 常规二分
题意:给你两个串,S2是S1 的一个子串(可以不连续).给你一个s1字符下标的一个排列,按照这个数列删数,问你最多删到第几个时S2仍是S1 的一个子串. 题解:二分删掉的数.判定函数很好写和单调性也可 ...
- CodeForces - 779D String Game(二分)
Little Nastya has a hobby, she likes to remove some letters from word, to obtain another word. But i ...
- Codeforces 862D. Mahmoud and Ehab and the binary string 【二分】(交互)
<题目链接> 题目大意: 有一个长度为n(n<1000)的01串,该串中至少有一个0和一个1,现在由你构造出一些01串,进行询问,然后系统会给出你构造的串与原串的 Hamming ...
- Codeforces.862D.Mahmoud and Ehab and the binary string(交互 二分)
题目链接 \(Description\) 有一个长为\(n\)的二进制串,保证\(01\)都存在.你可以询问不超过\(15\)次,每次询问你给出一个长为\(n\)的二进制串,交互库会返回你的串和目标串 ...
- codeforces 803D Magazine Ad(二分+贪心)
Magazine Ad 题目链接:http://codeforces.com/contest/803/problem/D ——每天在线,欢迎留言谈论. 题目大意: 给你一个数字k,和一行字符 例: g ...
随机推荐
- window document树
- 附加任务:团队作业7 Alpha冲刺
附加任务:团队作业7 Alpha冲刺 附加任务要求参考东北师范大学陈志勇老师博客:https://edu.cnblogs.com/campus/nenu/2016SE_NENU/homework/19 ...
- 12.13java过关测试
库存物资管理系统: 1.首先建两个数据表,一个pass用于商品的增删改查,一个passd记录商品的出库与入库信息: 2.建两个实体类,用来传递商品与单据的信息 3.在添加与删除时,填写入库或者出库单据 ...
- 制作u盘kali系统启动盘
准备好一个容量大于8G的u盘,和kali系统的镜像文件. 下载universal-usb-install软件,打开设置如下,create等待几分钟. 下载minitool分区工具,插入u盘,打开min ...
- python -- 初始函数 函数的定义,函数的返回值以及函数的参数
1.什么是函数,函数的定义及语法 2.函数的返回值 3.函数的参数 一.函数的定义及语法 函数的定义:定义了一个动作或者功能,是对功能的封装 语法: def 函数名( 形参列表 ): ...
- JMeter学习(十八)JMeter处理Cookie与Session(转载)
转载自 http://www.cnblogs.com/yangxia-test 有些网站保存信息是使用Cookie,有些则是使用Session.对于这两种方式,JMeter都给予一定的支持. 1.Co ...
- django models返回数据根据某字段倒序排列
例如有一个models表叫做report,report表中有一个endtime,想将结果按照endtime倒序排列 正序排列的方法:[models对象.objects.order_by(“字段名& ...
- linux 查看端口占用
参考 https://www.cnblogs.com/wangtao1993/p/6144183.html lsof -i:8000
- PERL 正则表达式简介
来源:脚本之家 网址:http://www.jb51.net/article/17429.htm 一.简介 二.匹配操作符 三.模式中的特殊字符 1.字符+ 2.字符 []和[^] 3.字符 *和? ...
- 第九章 词典 (e)桶/计数排序