Rotate an array of n elements to the right by k steps.

For example, with n = 7 and k = 3, the array [1,2,3,4,5,6,7] is rotated to [5,6,7,1,2,3,4].

Note:
Try to come up as many solutions as you can, there are at least 3 different ways to solve this problem.

Hint:
Could you do it in-place with O(1) extra space?

思路:通过三次翻转来实现移位

class Solution {
public:
void rotate(vector<int>& nums, int k) {
int size = nums.size();
k %= size;
if(k == size || k == ) return; reverse(nums,,size--k);
reverse(nums,size-k,size-);
reverse(nums, , size-);
return;
} void reverse(vector<int>& nums, int start, int end){
int tmp;
while(start < end){
tmp = nums[start];
nums[start] = nums[end];
nums[end] = tmp;
start++;
end--;
}
}
};

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