NBUT 1219 Time 2010辽宁省赛
Time limit 1000 ms
Memory limit 131072 kB
Digital clock use 4 digits to express time, each digit is described by 3*3 characters (including”|”,”_”and” “).now given the current time, please tell us how can it be expressed by the digital clock.
Input
Each case contains 4 integers in a line, separated by space.
Proceed to the end of file.
Output
Sample Input
1 2 5 6
2 3 4 2
Sample Output
_ _ _
| _||_ |_
||_ _||_|
_ _ _
_| _||_| _|
|_ _| ||_
Hint
The digits showed by the digital clock are as follows:
_ _ _ _ _ _ _ _
| _| _||_||_ |_ ||_||_|| |
||_ _| | _||_| ||_| _||_| 签到题,理清楚就好,代码如下
#include <iostream>
#include<stdio.h>
using namespace std;
int num[];
char s1[][]={
{' ','_',' '},{' ',' ',' '},{' ','_',' '},{' ','_',' '},
{' ',' ',' '},{' ','_',' '},{' ','_',' '},{' ','_',' '},
{' ','_',' '},{' ','_',' '}
};
char s2[][]={
{'|',' ','|'},{' ',' ','|'},{' ','_','|'},{' ','_','|'},
{'|','_','|'},{'|','_',' '},{'|','_',' '},{' ',' ','|'},
{'|','_','|'},{'|','_','|'}
};
char s3[][]={
{'|','_','|'},{' ',' ','|'},{'|','_',' '},{' ','_','|'},
{' ',' ','|'},{' ','_','|'},{'|','_','|'},{' ',' ','|'},
{'|','_','|'},{' ','_','|'}
};
int main()
{
while(~scanf("%d",&num[]))
{
for(int i=;i<;i++)scanf("%d",&num[i]); for(int i=;i<;i++)
for(int j=;j<;j++)
{ printf("%c",s1[num[i]][j]);
}
printf("\n");
for(int i=;i<;i++)
for(int j=;j<;j++)
{
printf("%c",s2[num[i]][j]);
}
printf("\n");
for(int i=;i<;i++)
for(int j=;j<;j++)
{
printf("%c",s3[num[i]][j]);
}
printf("\n"); } return ;
}
NBUT 1219 Time 2010辽宁省赛的更多相关文章
- NBUT 1221 Intermediary 2010辽宁省赛
Time limit 1000 ms Memory limit 131072 kB It is widely known that any two strangers can get to know ...
- NBUT 1220 SPY 2010辽宁省赛
Time limit 1000 ms Memory limit 131072 kB The National Intelligence Council of X Nation receives a ...
- NBUT 1217 Dinner 2010辽宁省赛
Time limit 1000 ms Memory limit 32768 kB Little A is one member of ACM team. He had just won the g ...
- NBUT 1224 Happiness Hotel 2010辽宁省赛
Time limit 1000 ms Memory limit 131072 kB The life of Little A is good, and, he managed to get enoug ...
- NBUT 1222 English Game 2010辽宁省赛
Time limit 1000 ms Memory limit 131072 kB This English game is a simple English words connection gam ...
- NBUT 1225 NEW RDSP MODE I 2010辽宁省赛
Time limit 1000 ms Memory limit 131072 kB Little A has became fascinated with the game Dota recent ...
- NBUT 1218 You are my brother 2010辽宁省赛
Time limit 1000 ms Memory limit 131072 kB Little A gets to know a new friend, Little B, recently. On ...
- NBUT 1223 Friends number 2010辽宁省赛
Time limit 1000 ms Memory limit 131072 kB Paula and Tai are couple. There are many stories betwee ...
- ZOJ 1985 Largest Rectangle in a Histogram(刷广告)2010辽宁省赛
Largest Rectangle in a Histogram Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 21204 ...
随机推荐
- AngularJS监听路由变化
使用AngularJS时,当路由发生改变时,我们需要做某些处理,此时可以监听路由事件,常用的是$routeStartChange, $routeChangeSuccess.完整例子如下: <!D ...
- c++ 二分法查找(binary_search)
#include <iostream> // cout #include <algorithm> // binary_search, sort #include <vec ...
- 一步一步实现JS拖拽插件
js拖拽是常见的网页效果,本文将从零开始实现一个简单的js插件. 一.js拖拽插件的原理 常见的拖拽操作是什么样的呢?整过过程大概有下面几个步骤: 1.用鼠标点击被拖拽的元素 2.按住鼠标不放,移动鼠 ...
- 消息/事件, 同步/异步/协程, 并发/并行 协程与状态机 ——从python asyncio引发的集中学习
我比较笨,只看用await asyncio.sleep(x)实现的例子,看再多,也还是不会. 已经在unity3d里用过coroutine了,也知道是“你执行一下,主动让出权限:我执行一下,主动让出权 ...
- 新概念 Lesson 2 Sorry, sir.
Is this your handbag? 这是你的手提包吗? Yes,it is. /No it isn't 人称代词的主格宾格 形容性物主代词的用法 Does the man get his um ...
- LeetCode--191--位1的个数
问题描述: 编写一个函数,输入是一个无符号整数,返回其二进制表达式中数字位数为 ‘1’ 的个数(也被称为汉明重量). 示例 : 输入: 11 输出: 3 解释: 整数 11 的二进制表示为 00000 ...
- php--------http 状态代码及其原因
HTTP 400 - 请求无效HTTP 401.1 - 未授权:登录失败HTTP 401.2 - 未授权:服务器配置问题导致登录失败HTTP 401.3 - ACL 禁止访问资源HTTP 401.4 ...
- 1 python基础知识
一.python简介 编译型:将所有的源码先编译成机器型语言,并保存为二进制文件,然后一次性执行c c++ go swift 解释型:将代码一行一行边编译边解释python javascript ph ...
- 利用nodeJs anywhere搭建本地服务器环境
1.npm install anywhere -g 如果是mac系统会提示你权限不够,需要在代码前加上 sudo获取管理员权限.即sudo npm install anywhere -g. 2.安装完 ...
- Leetcode 94
/** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode ...