latin-1 codec cant encode characters in position 42-48: ordinal not in range256 下载文件时候报错
python后端写下载文件, 这个时候出现了这个错误
latin-1 codec cant encode characters in position 42-48: ordinal not in range256
怎么办:
查起因: 发现文件名有中文名字, 所以导致错误, 编码是latin-1编码, 所以我们需要解码成unicode在编码成latin-1
先看代码:
这段代码涉及python转码问题, 一定要注意
FilePathName = self.get_argument("FilePathName", None) #获取文件名
FileName = str(FilePathName.split("/")[-1]).strip() # 得到文件名
latinFileName = FileName.encode("utf-8").decode("latin1") # 这句很关键, 要解析成latin-1才OK,这样就不会报错
class DownFileHandler(downBaseRequestHandler):
@tornado.gen.coroutine
def get(self, *args, **kwargs): if self.verifyFlag == 1 and self.status == 0:
status = 2000 try:
FilePathName = self.get_argument("FilePathName", None)
FilePathName = MyBase64.decryption(unquote(FilePathName)) # 这句是解密
FileName = str(FilePathName.split("/")[-1]).strip()
latinFileName = FileName.encode("utf-8").decode("latin1") # 这句很关键, 要解析成latin-1才OK,这样就不会报错
newFileName = str(int(time.time())) + "." + FileName.split(".")[1] # 第二种方式就是换一个文件名
self.set_header("Content-Type", "application/x-zip-compressed")
# -----<或者这么写> ----- #
# self.set_header("Content-Type", "application/octet-stream")
self.set_header("Content-Disposition", "attachment; filename=%s" % latinFileName)
f = open(FilePathName, 'rb')
while True:
b = f.read(8096)
if not b:
break
else:
self.write(b)
self.flush()
f.close() except Exception as e:
e = FormatErrorCode(e)
my_log.error(e)
status = int(e[0])
self.write(json.dumps(result(status=status)))
self.finish()
else:
self.write(json.dumps(result(status=4005)))
self.finish()
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