zabbix 微信报警脚本

不知道是什么原因直接用Python脚本zabbix无法执行脚本，需要一个shell来启动

#! /bin/bash
userid=$
content=$
python /data/zabbix/alertscripts/weixin.py  $userid $content

#!/usr/bin/env python
# _*_ coding:utf8 _*_
import urllib2
import simplejson as json
import sys
class weChat:
    def __init__(self,url,Corpid,Secret):
        url = '%s/cgi-bin/gettoken?corpid=%s&corpsecret=%s' % (url,Corpid,Secret)
        res = self.url_req(url)
        self.token = res['access_token']

    def url_req(self,url,method='get',data={}):
        if method == 'get':
            req = urllib2.Request(url)
            res = json.loads(urllib2.urlopen(req).read())
        elif method == 'post':
                        req = urllib2.Request(url,data)
                        res = json.loads(urllib2.urlopen(req).read())
        else:
            print 'error request method...exit'
            sys.exit()
        return res
    def send_message(self,userlist,content,agentid=):
        self.userlist = userlist
        self.content = content
        url = 'https://qyapi.weixin.qq.com/cgi-bin/message/send?access_token=%s' % self.token
        data = {
                      "touser": "",
                      "toparty": "",
                      "totag": "",
                      "msgtype": "text",
                      "agentid": "",
                      "text": {
                          "content": ""
                      },
                      "safe":""
                   }
        data['touser'] = userlist
        data['agentid'] = agentid
        data['text']['content'] = content
        data = json.dumps(data,ensure_ascii=False)
    #   print data
        res = self.url_req(url,method='post',data=data)
        if res['errmsg'] == 'ok':
            print 'send sucessed!!!'
        else:
            print 'send failed!!'
            print res

if __name__ == '__main__':
      userlist = sys.argv[]
#      userlist = 'ZhangSen'
      content = sys.argv[:]
      content = '\n'.join(content)
#      content = 'test1'
      Corpid = 'xxx'  #此处对应修改
      Secret = 'xxx'  #此处对应修改
      url = 'https://qyapi.weixin.qq.com'

wechat = weChat(url,Corpid,Secret)
wechat.send_message(userlist,content)

上面这脚本有个问题不能发中文消息，下面这个可以发中文

#!/usr/bin/python
# _*_coding:utf- _*_
import urllib2
import json
import sys

reload(sys)
sys.setdefaultencoding('utf-8')

def gettoken(corpid, corpsecret):
    gettoken_url = 'https://qyapi.weixin.qq.com/cgi-bin/gettoken?corpid=' + corpid + '&corpsecret=' + corpsecret
    try:
        token_file = urllib2.urlopen(gettoken_url)
    except urllib2.HTTPError as e:
        e.code
        e.read().decode("utf8")
        sys.exit()
    token_data = token_file.read().decode('utf-8')
    token_json = json.loads(token_data)
    token_json.keys()
    token = token_json['access_token']
    return token

def senddata(access_token, user, party, agent, subject, content):
    send_url = 'https://qyapi.weixin.qq.com/cgi-bin/message/send?access_token=' + access_token
    send_values = "{\"touser\":\"" + user + "\",\"toparty\":\"" + party + "\",\"totag\":\"\",\"msgtype\":\"text\",\"agentid\":\"" + agent + "\",\"text\":{\"content\":\"" + subject + content + "\"},\"safe\":\"0\"}"
    send_request = urllib2.Request(send_url, send_values)
    response = json.loads(urllib2.urlopen(send_request).read())
    print "send sucessed!!!"
    str(response)

if __name__ == '__main__':
    user = str(sys.argv[])  # 参数1:发送给用户的账号,必须关注企业号,并对企业号有发消息权限
    party = str('')  # 参数2:发送给组的id号,必须对企业号有权限
    agent = str('')  # 参数3:企业号中的应用id
    subject = str('')  # 参数4:标题【消息内容的一部分】
    content = str(sys.argv[])  # 参数5:文本具体内容
    corpid = 'xxx'  # CorpID是企业号的标识
    corpsecret = 'xxx'   # corpsecretSecret是管理组凭证密钥
    try:
        accesstoken = gettoken(corpid, corpsecret)
        senddata(accesstoken, user, party, agent, subject, content)
    except Exception, e:
        print "error"
        str(e) + "Error Please Check \"corpid\" or \"corpsecret\" Config"