[LeetCode] Read N Characters Given Read4 I & II
The API: int read4(char *buf) reads 4 characters at a time from a file.
The return value is the actual number of characters read. For example, it returns 3 if there is only 3 characters left in the file.
By using the read4 API, implement the function int read(char *buf, int n) that reads n characters from the file.
Note:
The read function will only be called once for each test case.
// Forward declaration of the read4 API.
int read4(char *buf); class Solution {
public:
/**
* @param buf Destination buffer
* @param n Maximum number of characters to read
* @return The number of characters read
*/
int read(char *buf, int n) {
char tmp[];
int idx = , cnt4;
while (idx < n) {
cnt4 = read4(tmp);
for (int i = ; i < cnt4 && idx < n; ++i) {
buf[idx++] = tmp[i];
}
if (cnt4 < ) break;
}
return idx;
}
};
Read N Characters Given Read4 II - Call multiple times
The API: int read4(char *buf) reads 4 characters at a time from a file.
The return value is the actual number of characters read. For example, it returns 3 if there is only 3 characters left in the file.
By using the read4 API, implement the function int read(char *buf, int n) that reads n characters from the file.
Note:
The read function may be called multiple times.
// Forward declaration of the read4 API.
int read4(char *buf); class Solution {
private:
char tmp[];
int tmp_idx = , tmp_len = ;
public:
/**
* @param buf Destination buffer
* @param n Maximum number of characters to read
* @return The number of characters read
*/
int read(char *buf, int n) {
int idx = ;
bool flag;
while (idx < n) {
flag = true;
if (tmp_idx == tmp_len) {
tmp_idx = ;
tmp_len = read4(tmp);
if (tmp_len != ) flag = false;
}
for (; tmp_idx < tmp_len && idx < n; ++tmp_idx) {
buf[idx++] = tmp[tmp_idx];
}
if (!flag) break;
}
return idx;
}
};
[LeetCode] Read N Characters Given Read4 I & II的更多相关文章
- [LeetCode] Read N Characters Given Read4 II - Call multiple times 用Read4来读取N个字符之二 - 多次调用
The API: int read4(char *buf) reads 4 characters at a time from a file. The return value is the actu ...
- LeetCode Read N Characters Given Read4 II - Call multiple times
原题链接在这里:https://leetcode.com/problems/read-n-characters-given-read4-ii-call-multiple-times/ 题目: The ...
- [LeetCode] Read N Characters Given Read4 用Read4来读取N个字符
The API: int read4(char *buf) reads 4 characters at a time from a file.The return value is the actua ...
- LeetCode Read N Characters Given Read4
原题链接在这里:https://leetcode.com/problems/read-n-characters-given-read4/ 题目: The API: int read4(char *bu ...
- Read N Characters Given Read4 I & II
The API: int read4(char *buf) reads 4 characters at a time from a file. The return value is the actu ...
- 【LeetCode】158. Read N Characters Given Read4 II - Call multiple times
Difficulty: Hard More:[目录]LeetCode Java实现 Description Similar to Question [Read N Characters Given ...
- [LeetCode] 157. Read N Characters Given Read4 用Read4来读取N个字符
The API: int read4(char *buf) reads 4 characters at a time from a file.The return value is the actua ...
- [Locked] Read N Characters Given Read4 & Read N Characters Given Read4 II - Call multiple times
Read N Characters Given Read4 The API: int read4(char *buf) reads 4 characters at a time from a file ...
- 【LeetCode】157. Read N Characters Given Read4 解题报告(C++)
作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 直接调用 日期 题目地址:https://leetco ...
随机推荐
- SpringBoot集成jdbcTemplate/JPA
1.pom.xml <!-- jdbcTemplate 依赖 --> <dependency> <groupId>org.springframework.boot& ...
- Linux c —— opendir函数和readdir函数内涵及用法(转)
opendir函数 头文件:#include <sys/types.h> #include <dirent.h> 函数:DIR *opendir(const char *na ...
- 2011的n次方
题目:http://noi.openjudge.cn/ch0204/2991/ 总时间限制:1000ms 内存限制: 65536kB 描述 已知长度最大为200位的正整数n,请求出2011^n的后四 ...
- Weblogic部署gbk编码的项目乱码
问题描述: weblogic默认部署的项目编码utf-8,由于项目特殊编码gbk导致打开项目中文全是乱码! 心哇凉哇凉.... 问题解决: 01.调休jvm参数 xxx_domains/bin/set ...
- 转:Irrlicht 0.1引擎源码分析与研究(一)
目录(?)[-] 主要技术特性 引擎概览 Irrlicht的窗口管理 Irrlicht引擎主要是由一个名叫Nikolaus Gebhardt奥地利人所设计,是sourceforge上的一个开源项目 ...
- SG 函数初步 HDU 1536 && HDU 1944
题目链接:http://acm.hdu.edu.cn/showproblem.php? pid=1944 pid=1536"> http://acm.hdu.edu.cn/showpr ...
- android使用GestureDetector实现手势下滑关闭页面的效果。
实现类似Android风云直播手机端注册登录页,当手势向下滑动的时候,关闭页面的效果. 使用GestureDetector来实现这个效果,当手势在屏幕上面滑动的时候 ,会掉用onFling方法,所以, ...
- 使用 Chrome 开发者工具进行 JavaScript 问题定位与调试
转自:https://www.ibm.com/developerworks/cn/web/1410_wangcy_chromejs/ 引言 Google Chrome 是由 Goole 公司开发的一款 ...
- 使用自连接、for xml path('')和stuff合并显示多行数据到一行中(转)
原文: http://njm.iteye.com/blog/795881 --使用 自连接.for xml path('')和stuff合并显示多行数据到一行中 --注 --1.计算列可以不用包含在聚 ...
- Librec的AoBPR算法实现
Librec的AoBPR算法实现:(基于1.3版本) 要用AoBPR,但是没有找到相应的配置文件,应该怎么办呢? ——因为用的是1.3版本,所以没有,2.0版本有的.[跟BPR参数一样,就 ...